Displaying 1 result from an estimated 1 matches for "22610l".
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22610
2012 May 29
1
Extract time from irregular date and time data records
...any leading zeroes
are dropped by the instrument. So if I use substr() to selected based
on character position I end up with incorrect times. So for example:
## df
df<-structure(list(Temperature = c(18.63, 18.4, 18.18, 16.99, 16.86,
11.39, 11.39, 11.37, 11.37, 11.37, 11.37), JulianDay.Hour = c(22610L,
22610L, 22610L, 22610L, 22610L, 22611L, 22611L, 22611L, 22611L,
22611L, 22611L), Minutes.Seconds = c(4608L, 4611L, 4614L, 4638L,
4641L, 141L, 144L, 208L, 211L, 214L, 238L)), .Names = c("Temperature",
"JulianDay.Hour", "Minutes.Seconds"), row.names = c(3176L, 3177L,
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