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Hi, I try to configure printers drivers on a samba server named lct8 (i read the printing support in samba 2.2.x), the smb.conf looks like : [global] secutity = SERVER passwd server = PDC (...) printer admin = @sysadmin, guy [print$] path = /usr/local/samba/printers write list = @sysadmin, guy create mask = 0644 guest ok = Yes [hpcolor] path = /tmp printable = Yes With win2k (host

Here's the story so far. I had a problem serving a printer from samba 2.2.3-6 (the -6 is specific to Debian I think) to a Windows XP client and found reports of Signal 11 in samba's logfile, so I filed a bug report (Debian Bug#135115) and also sent the log etc to samba@samba.org. The problem is now cured and I can print again, following changes I made to both the client and server.

I sent this to the list last week, and haven't seen it pop up. Either I deleted it when it did appear, or possibly it was destroyed as spam...? If it did appear and I somehow missed it, appologies. In a nutshell, can the function FUN supplied to by() deduce what level of factor by() was on when FUN was called? I've been digging through the functions, and can't see where the

Hello, what does this error message indicate and how do I avoid this? (sample code below) Thank you. -Tosh #read in the data table co<-read.table("co.txt",header=T,as.is=T) for (i in 1:3){ paste("logco",i, sep="")<-log(co$co[co$day==i]) } Gives the error: Error: Target of assignment expands to non-language object

Hi! I want to display 2 graphs with different number of data points on the x-axis. The code below scales them so it seems that testtwo has the same number of data points as testone. How can I fix that? thanks. z<-1:50; x<-1:100; plot(x,testone,type="l",xlab="",ylab="",main="",lty=4,axes=FALSE,ylim=c(-1.0,1.0),cex=1); par(new=TRUE);

This seems to be a recurrent topic, but I don't remember hearing a definitive answer. I also apologies for cross-posting. Say I have a numerical response variable and a bunch of multi-level factors I want to use for modeling. I don't expect factor interaction to be important so there will be no interactions in the model. All this would be a perfect job for ANOVA except for one additional

i am having some problems with a program that i am writing and i think that knowing how the while command works will help me to figure out where i am going wrong *when do you get kicked out of a while loop?* (i.e., in the following example what would the final value of 'a' be?) i thought it would be 99 but running it in R i get 101 (and 101 for x too!) while (x <100) { for (i in