Displaying 16 results from an estimated 16 matches for "22.28".
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2.2.28
2009 Feb 11
2
Question about apply()
Hello, everyone!
Assume you have this data:
data <- structure(c(66.609375, 67.09375, 66.40625, 66.734375, 67.109375,
66.875, 66.09375, 65.921875, 66.546875, 66.140625, 66.140625,
65.65625, 65.875, 65.59375, 65.515625, 66.09375, 66.015625, 66.140625,
66.109375, 66.421875, 1702.7, 1647.7, 1649.4, 1639.9, 1696.4,
1710.9, 1690.2, 1677.9, 1694.4, 1713.9, 1713.9, 1705.4, 1708.4,
1692.9, 1689.6,
2018 Nov 22
2
Problems after upgrading to 2.3.2.1
Hi,
I've just upgraded dovecot from 2.2.35 to 2.3.2.1 on my mail server
and noticed something odd. My mail clients (mutt and Apple mail) both stopped
seeing new mail in my mailboxes.
For example, ~/Maildir/mailinglist1/new has 5 new mails. In mutt, vieweing the
list of mailboxes mutt reports 0 new mail for "mailinglist1". Opening up the
actual mailbox in mutt reveals the 5 new
2008 Aug 21
3
Boxplot 5% and 95% quantile instead of 25% and 75%
Hi,
I'm new to the whole R-thing as a replacement for Matlab, not disappointed sofar ;)
I found out how to make nice looking boxplots, but i also would like the make a boxplot with 5% and 95% instead of the standard 25 and 75% quantiles.
My csv input looks something like:
LOCATION FILTER NR DATE VALUE MONTH
Peelhorst01 1 14-Jan-94 23.07 1
Peelhorst01 1 28-Jan-94 23.68 1
Peelhorst01 1
2004 Jul 16
3
interpreting profiling output
I have some trouble interpreting the output from profiling. I have
read the help pages Rprof, summaryRprof and consult the R extensions
manual, but I still have problems understanding the output.
Basically the output consist of self.time and total.time. I have the
understanding that total.time is the time spent in a given function
including any subcalls or child functions or whatever the
2008 Mar 06
2
Help with parsing a data file
Hi All,
I need to parse data from a file, example shown below. The first two lines
can be skipped, the third line contains the column names. The next 13 lines
can be skipped. The next line "1991" is a year value, with the following 13
values data for that year. The file then repeats this format with (year, 13
lines of data for that year). I would ideally like to end up with an
2007 Aug 21
2
Optimization problem
Hello Folks,
Very new to R so bear with me, running 5.2 on XP. Trying to do a zero-inflated negative binomial regression on placental scar data as dependent. Lactation, location, number of tick larvae present and mass of mouse are independents. Dataframe and attributes below:
Location Lac Scars Lar Mass Lacfac
1 Tullychurry 0 0 15 13.87 0
2 Somerset 0 0 0
2018 Nov 23
0
Problems after upgrading to 2.3.2.1
On 22 Nov 2018, at 22.28, Joel Dahl <joel at vnode.se> wrote:
>
> Hi,
>
> I've just upgraded dovecot from 2.2.35 to 2.3.2.1 on my mail server
> and noticed something odd. My mail clients (mutt and Apple mail) both stopped
> seeing new mail in my mailboxes.
>
> For example, ~/Maildir/mailinglist1/new has 5 new mails. In mutt, vieweing the
> list of mailboxes
2011 Dec 31
1
fts_solr break-imap-search 2.1
Is "break-imap-search" still required using 2.1 with Solr to index TEXT
& BODY searches?
--
Daniel
2006 Sep 18
2
problems in sourcing R script
Dear list,
First my information:
platform i386-pc-linux-gnu
arch i386
os linux-gnu
system i386, linux-gnu
status
major 2
minor 3.1
year 2006
month 06
day 01
svn rev 38247
language R
version.string Version 2.3.1 (2006-06-01)
Now my question:
How is it possible that a command in an R script is not
2007 Mar 04
6
Backgroundrb spiking CPU after first run on Mongrel cluster
I''ve been troubleshooting this problem for several hours now and haven''t
been able to figure out what''s wrong. I have two boxes, dev and prod, both
are identical except that prod uses Ruby 1.8.5 and dev uses 1.8.4. Both are
running Slave 1.2.0, Daemons 1.0.5, and Backroundrb 0.2.1.
The behavior I''m seeing is this. When I first start Backgroundrb, this is
what
2007 Aug 16
2
Newbie
Hello,
I'm a bit new to the world of R so forgive my ignorance. I'm trying to do a zero-inflated negative binomial regression and have received an error message and i'm not sure what it means. I'm running R 2.5.1 on XP. I have just tried a really simple version of the model to see if it would run before I put all the variables in. I have attached all the variables to the
2012 Sep 19
5
Dovecot deliver Segmentation fault when arrive the first message
Hi,
I have found this strange problem. I'm working with Debian 6, dovecot
2.1.9 and vpopmail-auth.
LDA is configured and works fine but the problem is when the first
message arrive "dovecot-lda" return a "Segmentation fault", the message
is written to the user's Mailbox but the message remains, also, in the
queue of qmail (deferral: Segmentation_fault/) and at the
2002 May 09
4
Rsquared in summary(lm)
Hello,
I'm doing some linear regression:
>lm<-lm(osas~alp,data)
>summary(lm)
However, the Rsquared in the output of summary() is not the same as the
"standard" Rsquared calculated by spreadsheets, and outlined in
statistical guidebooks, being SSR/SSTO. The output says "multiple
Rsquared", but it is no multiple regression...
What's the difference?
Thanks,
2016 May 25
1
Slow RAID Check/high %iowait during check after updgrade from CentOS 6.5 -> CentOS 7.2
On 2016-05-25 19:13, Kelly Lesperance wrote:
> Hdparm didn?t get far:
>
> [root at r1k1 ~] # hdparm -tT /dev/sda
>
> /dev/sda:
> Timing cached reads: Alarm clock
> [root at r1k1 ~] #
Hi Kelly,
Try running 'iostat -xdmc 1'. Look for a single drive that has
substantially greater await than ~10msec. If all the drives
except one are taking 6-8msec, but one is very
2014 Sep 01
1
Correlation Matrix with a Covariate
R Help -
I'm trying to run a correlation matrix with a covariate of "age" and will
at some point will also want to covary other variables concurrently.
I'm using the "psych" package and have tried other methods such as writing
a loop to extract semi-partial correlations, but it does not seem to be
working. How can I accomplish this?
library(psych)
> set.cor(y =
2013 Apr 22
7
Multiple lon lat points in the map with ggplot2
Hello R users,
For the last few days I am struggling with the following task:
my data.frame:
A1 A2 A3 B1 B2
B3
58.81 53.292 54.501 13.013 17.39 19.407 56.02 56.251 54.033 20.099 13.15
10.411 55.376 53.099 57.625 13.396 21.031 13.22 58.584 53.194 54.218
13.038 16.854 19.289 55.7 55.921 53.847 19.942 13.153 9.828 55.093 52.934