search for: 20spreading

Sanjoy, My answer is that step 3, commuting the multiply with the sign-extends, is invalid, As this is what causes the `udiv` to fault. I think it is invalid with or without the “freeze”, why do you think step 3, the commute, without the “freeze" is valid ? Also, do you think you can come up with an example that does not depend on signed overflow being “undefined” ? Peter