Displaying 1 result from an estimated 1 matches for "203928_x_at".
2007 Apr 20
1
simply this loop?
Hi, anyone interested in this:
I tried to simply this loop with lapply or something but haven't figured it out:
mapt = c("203929_s_at", "203930_s_at", "203928_x_at", "206401_s_at")
mapt.combn <- lapply(1:4, function(i) combn(mapt, i))
out = list()
k = 1
for (i in 1:length(mapt.combn)){
for (j in 1:ncol(mapt.combn[[i]])){
out[[k]] = mapt.combn[[i]][,j]
k = k + 1
}
}
out
# the following two lines create a list of list, which is not my...