search for: 2013l

...zmb"), class = "factor"), year = c(1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L, 1998L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L, 2007L, 2008L, 2009L, 2010L, 2011L, 2012L, 2013L, 2014L, 2015L, 1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L, 1998L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L, 2007L, 2008L, 2009L, 2010L, 2011L, 2012L, 2013L, 2014L, 2015L, 1991...

...> >?????????????????????????year = c(1991L, 1992L, 1993L, 1994L, 1995L, >1996L, 1997L,? > >???????????????????????????????????1998L, 1999L, 2000L, 2001L, 2002L, >2003L, 2004L, 2005L, 2006L,? > >???????????????????????????????????2007L, 2008L, 2009L, 2010L, 2011L, >2012L, 2013L, 2014L, 2015L,? > >???????????????????????????????????1991L, 1992L, 1993L, 1994L, 1995L, >1996L, 1997L, 1998L, 1999L,? > >???????????????????????????????????2000L, 2001L, 2002L, 2003L, 2004L, >2005L, 2006L, 2007L, 2008L,? > >???????????????????????????????????2009L, 2010L, 2...

...quot;), class = "factor"), ?????????????????????????year = c(1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L,? ???????????????????????????????????1998L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L,? ???????????????????????????????????2007L, 2008L, 2009L, 2010L, 2011L, 2012L, 2013L, 2014L, 2015L,? ???????????????????????????????????1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L, 1998L, 1999L,? ???????????????????????????????????2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L, 2007L, 2008L,? ???????????????????????????????????2009L, 2010L, 2011L, 2012L, 2013L, 2014L, 2015L...

... and the mailing list is picky about attachments... whatever you attached did not conform to the stringent requirements mentioned in the Posting Guide. Pasting the code right into the email is usually safest, though you DO have to post using plain text (as the Posting Guide indicates) or your code may get mangled by the automatic html format removal. On May 15, 2018 7:04:31 AM PDT, Bert Gunter

Hey, I have a set of income data which I'd like to fit to a gamma distribution. How can I estimate the two parameters of the gamma distribution for a vector, e.g. c(2039L, 2088L, 5966L, 2353L, 1966L, 2312L, 3305L, 2013L, 3376L, 3363L, 3567L, 4798L, 2032L, 1699L, 3001L, 2329L, 3944L, 2568L, 1699L, 4545L) I sense this will be a very easy one-liner, but my searching didn't come up with results yet. Thanks in advance, Alex

Unless there is good reason not to, always cc the list -- there are lots of smarter folks than I on it who can help. I may or may not have time to look at this. Hopefully someone else will. -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip

> Dear list, > > I have some data on a geneaology, here is a subset: > warmerge[1:11,c(1,6,25)] > Warrior SibID birth.year > 1100 3793 2013 1926 > 4 2013 2024 1934 > 1094 3769 2024 1918 > 632 2747 2037 1928 > 176 2083 2039 1944 > 187 2085 2039 1949 > 192 2086 2039 NA > 495

...;- data.frame(Year=2011:2015, Product=rep(c("Target", "3M", "Avery"), ? ? ?each=5), Sales=sample(1000:2000, 15), Region=rep(c("North", "South", ? ? ?"West"), each=5), stringsAsFactors=FALSE) dput(Tape) structure(list(Year = c(2011L, 2012L, 2013L, 2014L, 2015L, 2011L, 2012L, 2013L, 2014L, 2015L, 2011L, 2012L, 2013L, 2014L, 2015L ), Product = c("Target", "Target", "Target", "Target", "Target", "3M", "3M", "3M", "3M", "3M", "Avery",...

...;- data.frame(Year=2011:2015, Product=rep(c("Target", "3M", "Avery"), ? ? ?each=5), Sales=sample(1000:2000, 15), Region=rep(c("North", "South", ? ? ?"West"), each=5), stringsAsFactors=FALSE) dput(Tape) structure(list(Year = c(2011L, 2012L, 2013L, 2014L, 2015L, 2011L, 2012L, 2013L, 2014L, 2015L, 2011L, 2012L, 2013L, 2014L, 2015L ), Product = c("Target", "Target", "Target", "Target", "Target", "3M", "3M", "3M", "3M", "3M", "Avery",...

Hello folks, I have a big project to work on and the dataset is classified so I am just going to use my own example so everyone can understand what I am targeting. Let's take Target as an example: We consider three brands of tape: Target brand, 3M and Avery. The original data frame has 4 columns: Year of Record, Product_Name(which contains three brands of tape), Sales, and Region. I want to

...uot;, "OR", "OR"), oaz = c(38L, 205L, 140L, 277L, 329L, 209L, 222L, 24L, 67L, 187L, 156L, 181L, 174L, 248L, 42L, 279L, 273L, 357L, 160L, 183L)), .Names = c("oplt", "tree", "spp", "oaz"), row.names = c(1204L, 2943L, 5790L, 1616L, 5063L, 2013L, 5691L, 8188L, 8200L, 7822L, 6302L, 54L, 1698L, 2960L, 421L, 6690L, 775L, 245L, 6205L, 4121L), class = "data.frame") # count per spp invisible(lapply(ls(pat='ovs'), function(y) { cat(y, "\n") ; print(summary.factor(get(y)[,'spp'])) ; cat("\n") } ) )...

Hi Rhelpers, I would like to have some help with a plot which is beyond my capabilities. This plot that I am seeking involves an overlay of two different barcharts and one xyplot. The code that I have used is the following : #save(df1,file="M:\\KBR\\df1.RData") load(file="M:\\KBR\\df1.RData") # df1$Year.ord created to obtain the right order i.e. 2015M < 2015K

...30L, 3951L, 22L, 154L, 286L, 418L, 550L, 682L, 814L, 946L, 1078L, 1210L, 1342L, 1474L, 1606L, 1738L, 1870L, 2002L, 2134L, 2266L, 2398L, 2530L, 2662L, 2794L, 2926L, 3058L, 3190L, 3322L, 3454L, 3586L, 33L, 165L, 297L, 429L, 561L, 693L, 825L, 957L, 1089L, 1221L, 1353L, 1485L, 1617L, 1749L, 1881L, 2013L, 2145L, 2277L, 2409L, 2541L, 2673L, 2805L, 2937L, 3069L, 3201L, 3333L, 3465L, 3597L, 3720L, 3841L, 3962L, 44L, 176L, 308L, 440L, 572L, 704L, 836L, 968L, 1100L, 1232L, 1364L, 1496L, 1628L, 1760L, 1892L, 2024L, 2156L, 2288L, 2420L, 2552L, 2684L, 2816L, 2948L, 3080L, 3212L, 3344L, 3476L, 3608L, 3...