search for: 2.99

Hello! This is not a topic I am well versed in but required to become well versed in...I welcome any assistance! Using R, I want to create an optimal design for an experiment. I'll be analyzing the results with logistic regression or some generalized linear model. I am thinking that the algdesign package can help (but no idea where to start?). I'm presenting an example here that I have

Hii, I will create boxplots from matrices. I have the following data sets: 5.0 1.78 2.99 2.019 0 10.0 1.79 3.00 1.744 0 15.0 1.78 2.98 1.936 0 20.0 1.78 2.99 1.975 0 25.0 1.73 2.91 3.591 0 30.0 1.79 3.00 1.966 0 35.0 1.79 3.00 2.451 0 40.0 1.79 3.00

Dear all I am a BEGINNER and have R on my Mac. I saved my excel file as .txt file, I have just one column with first row as the column name. My file when read by R looks like this. After reading the table I try to make a histogram by hist(dbh), it says object dbh not found. What am I doing wrong? thanks dbh 1 11.53 2 16.05 3 7.36 4 16.05 5 8.66 6 12.74 7 22.93 8 7.55 9

I have the ewma function as shown below. I think I copied it from an oldSplus help page on filter and then modified it with a lot of help from Achim. ewma<-function(x,lambda = 1, init = x[1]) { rval<-filter(lambda*coredata(x),filter=(1-lambda),method="recursive",ini t=init) rval<-zoo(coredata(rval),index(x)) rval } It sort of works but , if there are NA values in the input

Thank you so much Dr. Nash, I truly appreciate your kind and valuable contribution. Cheers, Paul El El s?b, 19 de ago. de 2023 a la(s) 3:35 p. m., J C Nash < profjcnash at gmail.com> escribi?: > Why bother. nlsr can find a solution from very crude start. > > Mixture <- c(17, 14, 5, 1, 11, 2, 16, 7, 19, 23, 20, 6, 13, 21, 3, 18, 15, > 26, 8, 22) > x1 <- c(69.98, 72.5,

Dear R helpers,   I have following input files. (Actually they are more than 10 rates but here i am considering only 2 rates to write my problem)   rate1.csv min1        max1            min2          max2          min3           max3 1.05        1.30               1.30          1.65             1.65          1.99   rate2.csv min1        max1            min2          max2          min3          

Dear friends, Hope you are all doing well and having a great weekend. I have data that was collected on specific gravity and spectrophotometer analysis for 26 mixtures of NG (nitroglycerine), TA (triacetin), and 2 NDPA (2 - nitrodiphenylamine). In the dataset, x1 = %NG, x2 = %TA, and x3 = %2 NDPA. The response variable is the specific gravity, and the rest of the variables are the predictors.

The cautions people have given about starting values are worth heeding. That nlxb() does well in many cases is useful, but not foolproof. And John Fox has shown that the problem can be tackled very simply too. Best, JN On 2023-08-19 18:42, Paul Bernal wrote: > Thank you so much Dr. Nash, I truly appreciate your kind and valuable contribution. > > Cheers, > Paul > > El El

Dear All. I have some problem with combined two data frame. .... I have first data frame .. GPAX THAI MATH SCINCE SOCIAL HEALT ART CAREER LANGUAGE 1227 2.99 3.32 2.50 2.64 3.05 3.60 3.72 3.57 2.62 1704 2.81 2.56 2.48 2.86 3.22 3.19 3.55 3.20 2.51 617 2.18 1.90 1.97 2.06 2.38 3.50 3.54 2.33 1.70 876 2.82 3.14 2.73 2.46 2.71 3.11 3.04 3.24 2.90

Hi r-users, I would like to draw line plots. However, the plot starts from 11121 data and plot data ENTRY last in the plot. Here is the code and data. datn <- read.table(header=TRUE, text=' LEVEL STATUS CGPA DIPLOMA ENTRY 3.32 DIPLOMA 11121 2.91 DIPLOMA 11122 2.90 DIPLOMA 12131 2.89 DIPLOMA 12132 2.89 DIPLOMA 13141 2.93 DIPLOMA 13142 2.96 DIPLOMA 14151 2.76 DIPLOMA 14152 2.73 STPM

There was some discussion on this list recently about the voiptalk silver service. I've just had an e-mail from them saying that the price has been reduced to 2.99 per month. However, they still only provide an 0870 number whereas pipecall provide a local call rate 0845 number in the fee. Chris

Hi Andrey, Questions and feedback are very much welcome. - The explanation as to why the improvements can vary between the IR and MIR outliner mainly boil down to the level of abstraction that each are working at. The MIR level has very accurate heuristics and is effectively the last post ISel target independent code gen pass. The IR outliner on the other hand has more estimation in the cost

I upgraded (NetBSD 2.99 i386) from 1.0rc7 to 1.0rc24 and then tried rc25, and in both cases need to restart Dovecot every day or so (low volume server). It seems to run out of file descriptors. I have now raised the file descriptor limit to 1024, but that is not a long-term solution... ... Mar 5 11:41:38 arioch dovecot: pipe() failed: Too many open files Mar 5 11:42:38 arioch

I have a GeForce 8800GT that I am trying to lower the fan speed on. I can change the fan RPM from high to not-as-high but I want more control over it. It is too loud and it was quieter with the blob. Maybe the temps are too high to make it quieter. # echo 1 >/sys/devices/pci0000:00/0000:00:02.0/0000:01:00.0/i2c-6/6-002e/pwm1_enable # sensors fam15h_power-pci-00c4 Adapter: PCI adapter power1:

Hello, I am doing simulations, and I generate a list at each iteration (with three component matrices in the example below), saving the results in a list. For example, after two iterations, I have something like > str(sim.theta) List of 2 $ :List of 3 ..$ : num [1:6, 1:4] -3.67 -1.07 -2.99 -18.38 -3.26 ... ..$ : num [1:6, 1:6] -7.56 -3.14 -4.99 1.03 2.79 ... ..$ : num [1:6, 1:4]

Good Evening R Community: I believe I understand the basics of using the boot() bootstrap resampling function in the boot() package. I have not had any trouble creating a boot.object to which I apply the boot.ci() function to calculate one or all of the available confidence intervals. What I am not sure about is if this set of functions can generate more than one confidence interval of one or

Dear List, Can anyone please explain the difference between cluster() and frailty() in a coxph? I am a bit puzzled about it. Would appreciate any useful reference or direction. cheers, Ehsan > marginal.model <- coxph(Surv(time, status) ~ rx + cluster(litter), rats) > frailty.model <- coxph(Surv(time, status) ~ rx + frailty(litter), rats) > marginal.model Call: coxph(formula =

Hi, Thanks for the reproducible example. Looking at str(datn) would give you a clue. STATUS is a factor because it contains character values. Factor levels by default are alphabetical with numbers first, but you can change those. > str(datn) 'data.frame': 36 obs. of 3 variables: $ LEVEL : Factor w/ 4 levels "DIPLOMA","MATRIC",..: 1 1 1 1 1 1 1 1 1 4 ... $

Dear all, I need to use R for one estimation, and i have readily available stata command, but i need also the R version of the same command. the estimation in stata is as following: 1. Compute mean values of relevant variables . sum inno lnE lnM Variable | Obs Mean Std. Dev. Min Max -------------+--------------------------------------------------------

I'd like to superimpose a ksmooth() onto a barplot(). My data is: > d 2009-06-20 2009-06-21 2009-06-22 2009-06-23 2009-06-24 2009-06-25 2009-06-26 2009-06-27 2009-06-28 2009-06-29 2009-06-30 2009-07-01 2009-07-02 Same Breed (B) 12.64 21.08 13.52 12.51 13.71 9.91 14.24 7.18 11.81 5.92 12.04 17.96