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2017 Feb 16
3
Unsigned int displaying as negative
Tim, The issue is saturation is treated differently for signed than it is for unsigned. Ryan On Thu, Feb 16, 2017 at 9:49 AM, Tim Northover <t.p.northover at gmail.com> wrote: > On 15 February 2017 at 17:02, Ryan Taylor <ryta1203 at gmail.com> wrote: > > Tim, yes, I am on a very unique architecture, just about every > instruction > > has a signed and unsigned