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Dear Mehdi, I've changed your example a little bit: float saxpy(float a, float *x, float *y, int n) { int j = 0; for (int i = 0; i < n; ++i) { y[j] = a*x[i] + y[I]; // Change 'I' into 'j'? ++j; } } I get this code below, once I replace 'I' with 'j'. We are copying n positions of both arrays, 'x' and 'y': float saxpy(float a,

...The tool takes care of figuring out the sizes of the array AFAIK (haven’t read the paper yet to understand the novelty in the approach here). — Mehdi -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20170103/1da218ba/attachment.html>