Displaying 20 results from an estimated 634 matches for "1991".
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191
2008 Mar 08
1
plotting NAs
...#39;m trying to plot 2 time series lined up with par(mfrow=c(2,1)), so that the time index is the same for the two series. The data have monthly frequency.
An example will illustrate:
# data for these dates (monthly frequency) do not have NAs:
require(zoo)
monthly.dates<- as.Date(c(
"1991-01-31",
"1991-02-28",
"1991-03-31",
"1991-04-30",
"1991-05-30"
))
monthly.only.data<- 1:length(monthly.dates)
# data for these extra dates (daily frequency) do have NAs interspersed with
# non-NA data having monthly frequency:
daily.da...
2009 Oct 07
1
Formatting outputs:(chronological object)
...year 1990,
1990-01-01 314.7547
1990-02-01 266.0105
1990-03-01 353.7275
1990-04-01 273.8321
1990-05-01 325.3691
1990-06-01 253.1501
1990-07-01 318.1684
1990-08-01 291.2097
1990-09-01 298.6409
1990-10-01 304.0167
1990-11-01 279.4668
1990-12-01 286.9456
Total for year 1990 = xxx
Observation for year 1991
1991-01-01 313.1515
1991-02-01 297.9274
1991-03-01 315.2565
1991-04-01 290.9797
1991-05-01 327.0480
1991-06-01 281.5030
1991-07-01 316.7332
1991-08-01 289.9122
1991-09-01 296.9334
1991-10-01 280.2053
1991-11-01 295.6098
1991-12-01 321.6451
Total for year 1991 = xxx
Any help would be highly apprec...
2005 Mar 22
1
List of tables rather than an extra dimension in the table or (l)apply(xtabs)
...w/ 18 levels "0-4","5-9","10-14",..: 1 1 1 1 1 1 1 1 1 1 ...
..$ lga : Factor w/ 23 levels "Carnamah (S)",..: 1 2 3 4 5 6 7 8 9 10 ... # 23 subregions
..$ psn : num [1:4009] 71 336 26 84 30 133 904 385 99 110 ...
..$ year : num [1:4009] 1991 1991 1991 1991 1991 ...
..$ agecomp : Factor w/ 14 levels "0-4","5-9","10-14",..: 1 1 1 1 1 1 1 1 1 1 ...
..$ RegionNum: num [1:4009] 1 1 1 1 1 1 1 1 1 1 ...
$ 2:`data.frame': 720 obs. of 7 variables:
..$ sex : Factor w/ 2 levels "Females&qu...
2006 Nov 23
1
how to loop this?
...uot;1990-10-23", "1990-10-31", "1990-11-12", "1990-11-18", "1990-11-23",
"1990-11-27", "1990-12-04", "1990-12-07", "1990-12-13", "1990-12-16",
"1990-12-18", "1990-12-27", "1991-01-09", "1991-01-12", "1991-01-14",
"1991-01-19", "1991-01-24", "1991-02-04", "1991-02-07", "1991-02-10",
"1991-02-12", "1991-02-14", "1991-02-20", "1991-02-25", "1991-02-...
2008 Oct 29
1
Subsetting data in a loop
...at$Year==i,]
name<-paste("Year",i)
one_year[name]<-myear
}
mydat:
Year Month Day number other Ind1 Ind2 Ind3 Ind4
1985 8 13 1 1 0 0 0 0
1986 8 5 2 3 0 0 0 0
1991 4 24 3 0 0 0 0 0
1991 4 25 4 0 0 0 0 0
1991 8 2 5 0 0 0 0 0
1991 8 6 6 0 0 0 0 0
1991 9 4 ...
2008 Mar 20
3
Problem with diff(strptime(...
...55 1.0020534 0.8323066 1.0841889 0.9993155
1.1690623
[8] 0.8131417 2.0177960 2.8390372
There have been a few messages about this problem, but apparently no
solution. The problem can be seen with these examples (I haven't
included the real data as it is not mine):
foodate<-c("1/7/1991","1/8/1991","1/8/1991","3/8/1991")
as.numeric(diff(strptime(foodate,"%d/%m/%Y"))/365.25)
[1] 7333.0595 0.0000 473.1006
foodate<-factor(c("1/7/1991","1/8/1991","1/8/1991","3/8/1991"))
as.numeric(diff(strptim...
2009 Mar 19
1
problem with Dates
...erent between 2 dates and
getting minimum in vector of dates
that is i m working with dates in formate "6/22/1992 12:00:00 AM"
and the vector is
[1] 6/4/1992 12:00:00 AM 2/13/1992 12:00:00 AM 6/19/1992 12:00:00 AM
[4] 2/11/1992 12:00:00 AM 6/22/1992 12:00:00 AM 10/3/1991 12:00:00 AM
[7] 5/12/1992 12:00:00 AM 7/11/1991 12:00:00 AM 2/6/1992 12:00:00 AM
[10] 10/4/1991 12:00:00 AM 1/31/1992 12:00:00 AM 6/9/1992 12:00:00 AM
[13] 10/9/1991 12:00:00 AM 6/10/1992 12:00:00 AM 7/19/1991 12:00:00 AM
[16] 7/18/1991 12:00:00 AM 9/20/1991 12:00:00 AM 8/6/1992 12:...
2006 Nov 22
3
dataframe manipulation
...uot;, "1990-10-23", "1990-10-31", "1990-11-12", "1990-11-18",
"1990-11-23", "1990-11-27", "1990-12-04", "1990-12-07", "1990-12-13",
"1990-12-16", "1990-12-18", "1990-12-27", "1991-01-09", "1991-01-12",
"1991-01-14", "1991-01-19", "1991-01-24", "1991-02-04", "1991-02-07",
"1991-02-10", "1991-02-12", "1991-02-14", "1991-02-20", "1991-02-25",
"1991-02-27"...
2017 Jun 07
4
Determining which.max() within groups
...ng the dataset below, I got close to what I'm after, but not quite all
the way there. Any suggestions appreciated:
Daily <- read.table(textConnection(" Date wyr Q
1911-04-01 1990 4.530695
1911-04-02 1990 4.700596
1911-04-03 1990 4.898814
1911-04-04 1990 5.097032
1911-04-05 1991 5.295250
1911-04-06 1991 6.569508
1911-04-07 1991 5.861587
1911-04-08 1991 5.153666
1911-04-09 1992 4.445745
1911-04-10 1992 3.737824
1911-04-11 1992 3.001586
1911-04-12 1992 3.001586
1911-04-13 1993 2.350298
1911-04-14 1993 2.661784
1911-04-16 1993 3.001586
1911-04-17 1993 2.661784
1911-04-19 1994...
2007 Dec 19
3
plot cummulative sum from calendar time
I have the following list of observations of calendar time:
[1] 03-Nov-1997 09-Oct-1991 27-Aug-1992 01-Jul-1994 19-Jan-1990 12-Nov-1993
[7] 08-Oct-1993 10-Nov-1982 08-Dec-1986 23-Dec-1987 02-Aug-1995 20-Oct-1998
[13] 29-Apr-1991 16-Mar-1994 20-May-1991 28-Dec-1987 14-Jul-1999 27-Nov-1998
[19] 09-Sep-1999 26-Aug-1999 20-Jun-1997 05-May-1995 26-Mar-1998 15-Aug-1994
[25] 24-Jun-1996 02-...
2007 Jun 20
1
Date and selection
Dear R experts,
Suppose I have a data.frame recording the date and test results of
some subjects like this:
Name Date results
John 01/01/1991 2
John 02/01/1991 3
John 09/0101991 4
Micheal 02/01/1991 4
Micheal 04/01/1991 5
....
How to select the earliest (or latest) test result from all subjects?
Thank you.
Regards,
CH
--
"The scientists of today think deeply instead of clearly. One must be
sane to think clearly, but one can...
2008 Mar 30
2
convert weekly time series data to monthly
...ke to collapse the data into monthly averages to merge with a
monthly series. The input data set for the monthly series takes the
following form:
M-Y Year Month Change
Aug-1990 1990 8 -226.871
Sep-1990 1990 9 -896.333
Oct-1990 1990 10 111.419
Nov-1990 1990 11 -364.2
Dec-1990 1990 12 -527.645
Jan-1991 1991 1 -70.935
Feb-1991 1991 2 231.214
Mar-1991 1991 3 -239
... ... ..... .. ....
The merged data set should be of class(ts).
I can perform the conversions outside of R and then import but I would
rather perform all conversions within R. I have looked through the zoo and
Rmetrics packages but...
2017 Oct 06
2
Time series: xts/zoo object at annual (yearly) frequency
Hi,
I'd like to make a time series at an annual frequency.
> a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993"))
Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) :
order.by requires an appropriate time-based object
> a<-xts(x=c(2,4,5), order.by=1991:1993)
Error in xts(x = c(2, 4, 5), order.by = 1991:1993) :
ord...
2009 Nov 08
1
Turn dates into age
Ive got a big column of dates (also some fields dont have a date so they have
NA instead),
that i have converted into date format as so...
dates<-as.character(data[,"date_commissioned"]); # converted dates to
characters
dates[1:10]
[1] "19910101" "19860101" "19910101" "19860101" "19910101" "19910101"
"19910101" "19910101" "19910101" "19910101"
dateObs <- as.Date(dates,format="%Y%m%d")
dateObs[1:10]
[1] "1991-01-01" &qu...
2008 Apr 25
4
Constructing dummy variables for months for a time series object
I have a TS of monthly observations.
head(data4)
1991(1) 1991(2) 1991(3) 1991(4) 1991(5) 1991(6)
12.00864 11.94203 11.98386 12.01900 12.19226 12.15488
Now I want to make 11 dummy variables indicating months. Therefore I did followings :
For Jan :
rep(c(rep(0,0), 1, rep(0, 11)), 17)
For Feb :
rep(c(rep(0,1), 1, rep(0, 10)), 17...
2009 Jan 28
3
Newbie Question About Histograms
Hello everyone. Just have a question , cant figure out how to make this
histogram.
I have this table, that i stored in a variable name new.data2. Table looks
like this
Year GeoArea SmpNo Month Gear Maturity Length Age YearC
1989 1 362 10 22 1 225 1 1988
1991 1 267 10 10 1 191 1 1990
1991 1 267 10 10 1 202 1 1990
1992 1 305 10 8 1 162 1 1991
1992 1 305 10 8 1 165 1 1991
1992 1 305 10 8 1 166 1 1991
1992 1 305 10...
2017 Jun 07
0
Determining which.max() within groups
cumsum() seems to be what you need.
This can probably be done more elegantly, but ...
out <- aggregate(Q ~ wyr, data = Daily, which.max)
tbl <- table(Daily$wyr)
out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)]))
out
## yields
wyr Q
1 1990 4
2 1991 6
3 1992 9
4 1993 15
5 1994 18
I leave the matter of Julian dates to you or others.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic s...
2010 Aug 06
3
How to apply apply?!
guRus
I have say a dataframe, d and I wish to do the following:
1) For each row, I want to take one particular value of the row and multiply
it by 2. How do I do it. Say the data frame is as below:
OPEN HIGH LOW CLOSE 1931.2 1931.2 1931.2 1931.2 0 0 0 999.05 0 0 0 1052.5
0 0 0 987.8 0 0 0 925.6 0 0 0 866 0 0 0 1400.2 0 0 0 754.5 0 0 0 702.6 0 0 0
653.25 0 0 0 348 0 0 0 801 866.55 866.55
2004 Jun 11
4
Regression query
...can throw some light on this matter and how to
use R to detect
the interactions effectively .
Thanks
Regards
Dev
------Final 'lm model'--------------------
> logmodelfull_minus_run_hr_walk_batting <- lm(log(salary) ~ hit+rbi + walk
+ obp + strike.out+free.agent.eligible+free.agent.1991+arbitr.elgible.)
> summary(logmodelfull_minus_run_hr_walk_batting)
Call:
lm(formula = log(salary) ~ hit + rbi + walk + obp + strike.out +
free.agent.eligible + free.agent.1991 + arbitr.elgible.)
Residuals:
Min 1Q Median 3Q Max
-2.41786 -0.28911 -0.02814 0.31890 1....
2009 Sep 30
2
Few questions about oVirt install.
Hi.
I have successfully installed ovirt.
Boot 2 nodex throught PXE boot, and added to pool.
Whe i try to create NFS storage, they in state: pending setup.
How to add NFS storage?
taskomatic.log
INFO Wed Sep 30 16:59:09 +0300 2009 (1991) starting task_refresh_pool
INFO Wed Sep 30 16:59:09 +0300 2009 (1991) storage_find_suitable_host:
host node3.ovirt.priv uuid 30303234-3144-3832-4638-3931FF
FFFFFF
INFO Wed Sep 30 16:59:09 +0300 2009 (1991) host.is_disabled is 0
INFO Wed Sep 30 16:59:10 +0300 2009 (1991) refresh being done on nod...