Displaying 1 result from an estimated 1 matches for "1990m12".
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19901
2008 Dec 18
3
Parsing unusual date format
Hello,
If I have a character string like
d <- c("1990m3", "1992m8") #March 1990 and Aug 1992
what is the easiest way to convert it into any standard date form; for
example,
d <- c("01/03/1990", "01/08/1992")
I looked at as.Date but it doesn't seem to address my problem as I have an
"m" stuck in the middle of my character string