Displaying 20 results from an estimated 384 matches for "1985".
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185
2009 Apr 28
3
help working with date values
My data contains a variable "observation_date" and it contains values as:
1985-09-02
1985-09-15
1985-07-31
1985-09-02
I need to process data annually rather than daily, therefore I'm trying to
1) either extract the first 4 digits from this field and use them as a new
variable "year" or 2) keep the variable as it is and process the analysis
using the first 4 d...
2017 Nov 01
3
Adding Records to a Table in R
Dear R friends,
I am currently working with time series data, and I have a table(as data
frame) that has looks like this (TransitDate are in format = "%e-%B-%Y") :
TransitDate Transits CargoTons
1985-04-01 100 2500
1985-05-01 135 4500
1985-06-01 120 1750
1985-07-01 100 3750
1985-08-01 200 1250
The problem is, that there are several periods that don?t exist in the
table, so it has the following behavior:...
2017 Nov 01
0
Adding Records to a Table in R
Hi Paul,
#First I set up some sample data since I don't have a copy of your data
dtOrig <- as.Date( c("1985-04-01","1985-07-01","1985-12-01","1986-04-01"))
dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325),
CargoTons=c(1000,1080,3785,4200) )
#Generate the complete set of dates as a data frame
dfDates<- data.frame( TransitDate=seq(from=as.Date(...
2011 Apr 25
2
Problem with ddply in the plyr-package: surprising output of a date-column
...rectly. Any idea what I do wrong?
df <- data.frame(cbind(ID1=c(1,2,2,3,3,4,4),ID2=c('a','b','b','c','d','e','e'),ID3=c("v1","v1","v1","v1","v2","v1","v1"),
Date=c("1985-05-1","1985-05-2","1985-05-3","1985-05-4","1985-05-5","1985-05-6","1985-05-7"),
Value=c(1,2,3,4,5,6,7)))
df[,1] <- as.character(df[,1])
df[,2] <- as.character(df[,2])
df$Date <- strptime(df$Date,"%Y-%m...
2010 Jul 27
1
repeating rows in R
...d 3
cases of HIV in my data, not 2 cases of HIV and 1 case of cancer. Is there
an easy way to expand my data so that I actually end up with 22 rows instead
of 10? Specifically, my data currently look like this:
>my data
AdmitYear Race Age.yrs. Insurance HIV Cancer NoRecords
1 1985 A 20 0 0
0 1
2 1985 A 21 0 0
0 1
3 1985 A 22 1 1
0 1
4 1985 A 23 0 0
0 2
5 1985 A...
2011 Jan 26
1
Using diff and transform
...with a difference column. The problem is that diff gives
one less than the number of elements in the original data frame. So
transform gives an error message. I know the first element of diff should be
NA or ideally 0. But not sure how I get there. Any suggestions ?
j
Date Close
1 11/20/1985 156.412
2 11/21/1985 155.112
3 11/22/1985 154.182
4 11/25/1985 154.192
5 11/26/1985 153.722
6 11/27/1985 153.712
d <-diff(j[,2])
d
[1] -1.30 -0.93 0.01 -0.47 -0.01
j <- transform(j, delta=diff(j[,2]))
Error in data.frame(list(Date = c(5620L, 5639L, 5657L, 5706L, 5721L, 5736L :
argument...
2017 Nov 08
3
Adding Records to a Table in R
...the values in dataset1 and only add
the dates missing with value 0.
Best regards,
Paul
2017-11-01 15:21 GMT-05:00 Eric Berger <ericjberger at gmail.com>:
> Hi Paul,
>
> #First I set up some sample data since I don't have a copy of your data
> dtOrig <- as.Date( c("1985-04-01","1985-07-01","1985-12-01","1986-04-01"))
> dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325),
> CargoTons=c(1000,1080,3785,4200) )
>
> #Generate the complete set of dates as a data frame
> dfDates<- data.frame( Trans...
2017 Nov 08
0
Adding Records to a Table in R
...alue 0.
>
> Best regards,
>
> Paul
>
> 2017-11-01 15:21 GMT-05:00 Eric Berger <ericjberger at gmail.com>:
>
> > Hi Paul,
> >
> > #First I set up some sample data since I don't have a copy of your
> > data dtOrig <- as.Date(
> > c("1985-04-01","1985-07-01","1985-12-01","1986-04-01"))
> > dfOrig <- data.frame( TransitDate=dtOrig, Transits=c(100,100,500,325),
> > CargoTons=c(1000,1080,3785,4200) )
> >
> > #Generate the complete set of dates as a data frame
> > dfDat...
2017 Jul 04
5
about adding a column for water year
...s
the structure below. But the wyear column just shows one year. Could anyone
help me with this problem? Thanks.
DF
year month day time flow
1972 1 1 1972-01-01 5
1972 1 2 1972-01-02 5.5
1972 1 3 1972-01-03 6
...
1985 12 31 1985-12-31 6
for(i in 1972:1985){
if(DF$year==i & DF$month %in% 1:9){
DF$wyear <- i {
}else{
DF$wyear < i-1
}
}
}
[[alternative HTML version deleted]]
2005 Oct 04
2
newbie questions - looping through hierarchial datafille
...lot_no tree_no leader_no;
* calculate mean dbh in each plot
data dbh
set datafile;
by inventory stratum_no plot_no tree_no leader_no
if first.leader_no then output;
proc summary data = diameter;
by inventory stratum plot tree;
var diameter;
output out = mean mean=;
run;
A BENALLA_1
X 1 10 YE=1985
P 1 20.25 slope=14 SPP:P.RAD
T 1 25
L 0 28.5 21.3528
F 0 21.3528 SFNSW_DIC:P
F 21.3528 100 SFNSW_DIC:P
T 2 25
L 0 32 23.1
F 0 6.5 SFNSW_DIC:A
F 6.5 23.1 SFNSW_DIC:C
F 23.1 100 SFNSW_DIC:C
T 3 25
L 0 39.5 22.2407
F 0 4.7 SFNSW_DIC:A
F 4.7 6.7 SFNSW_DIC:C
P 2 20.25 slope=13 SPP:P.RAD
T 1 25
L 0 38 22...
2011 Nov 19
3
reshape data.frame
A late friday afternoon coding question. I'm having a hard time thinking
of the correct search terms for what I want to do.
If I have a df like this:
a <-
data.frame(name=c(rep('a',10),rep('b',15)),year=c(1971:1980,1971:1985),amount=1:25)
name year amount
1 a 1971 1
2 a 1972 2
3 a 1973 3
4 a 1974 4
5 a 1975 5
6 a 1976 6
7 a 1977 7
8 a 1978 8
9 a 1979 9
10 a 1980 10
11 b 1971 11
12 b 1972 12
13 b 1973 13
14...
2009 Jun 03
1
insert and count missing data
Hi R-users,
I have missing data for the month. My question is how do I insert the missing month and fill up the cell with 'na' for the rain amount? Then I would like to count the percentage of missing data.
No Year month rain
1398 1985 10 104.2
1399 1985 11 138.0
1400 1985 12 120.4
1401 1986 1 12.6
1402 1986 2 19.4
1403 1986 3 1.0
1404 1986 4 58.8
1405 1986 5 98.4
1406 1986 6 56.6
1407 1986 7 280.4
1408 1986 8 128.2
1409 1986 9 100.0
1410 1986 10 166.0
1411 1986 12 68.1
1...
2012 Sep 07
4
[Bug 1985] -N and -O stop
https://bugzilla.mindrot.org/show_bug.cgi?id=1985
Damien Miller <djm at mindrot.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Blocks| |2035
--- Comment #2 from Damien Miller <djm at mindrot.org>...
2017 Jul 04
0
about adding a column for water year
...expr
where
"cond A length-one logical vector that is not NA."
Your cond is a vector of length nrow(DF), so you don't want if, you
want ifelse().
Did you fail to show us your warning messages??
2. Revising your code and eliminating the extraneous brackets, one gets:
for(i in 1972:1985){
ifelse(DF$year==i & DF$month %in% 1:9, DF$wyear <- i,
DF$wyear < i-1)
}
But that doesn't work either, giving only 1985. Why? -- because the
assignment statement DF$wyear <- i assigns the single value i to the
whole column. So the whole column gets the last value of 1985,...
2017 Jul 05
4
Help with reshape/reshape2 needed
....387500000
1969 0.087500000
1970 0.275000000
1973 0.500000000
1974 0.362500000
1976 0.925000000
1978 0.712500000
1979 0.337500000
1980 0.700000000
1981 0.425000000
1982 0.212500000
1983 0.312500000
1986 0.237500000
1958 0.643564356
1963 0.250000000
1968 0.211538462
1976 0.317307692
1981 0.673076923
1985 0.730769231
1986 0.057692308
1957 0.073394495
1966 0.742574257
1961 0.082568807
1964 0.165137615
1965 0.137614679
1959 0.128712871
1968 0.587155963
1969 0.660550459
1970 0.477064220
1971 0.513761468
1973 0.449541284
1974 0.128440367
1968 0.415841584
1977 0.009174312
1979 0.339449541
1981 0.59633027...
2016 Oct 04
0
CentOS-announce Digest, Vol 140, Issue 1
...Contents of CentOS-announce digest..."
Today's Topics:
1. CEEA-2016:1982 CentOS 5 tzdata Enhancement Update (Johnny Hughes)
2. CEEA-2016:1982 CentOS 6 tzdata Enhancement Update (Johnny Hughes)
3. CEEA-2016:1982 CentOS 7 tzdata Enhancement Update (Johnny Hughes)
4. CESA-2016:1985 Important CentOS 6 thunderbird Security Update
(Johnny Hughes)
5. CESA-2016:1985 Important CentOS 5 thunderbird Security Update
(Johnny Hughes)
6. CESA-2016:1985 Important CentOS 7 thunderbird Security Update
(Johnny Hughes)
------------------------------------------------...
2004 Nov 03
2
[Bug 1985] rsync hangs reading pipe
https://bugzilla.samba.org/show_bug.cgi?id=1985
------- Additional Comments From Uwe.Girlich@philosys.de 2004-11-02 23:13 -------
Created an attachment (id=753)
--> (https://bugzilla.samba.org/attachment.cgi?id=753&action=view)
shell script to reproduce the rsync problem
This shell script creates some directories, a file and a nam...
2017 Jul 05
0
Help with reshape/reshape2 needed
The reason it doesn't work easily with reshape/reshape2 is that the
order of the rows is not determined. Your answer could be
1957 1958 ... 1985 1986
0.8625000 0.7500000 ... 0.7307692 0.23750000
0.0733945 0.6435644 ... NA 0.05769231
0.5096154 NA ... NA 0.65137615
or
1957 1958 ... 1985 1986
0.0733945 0.6435644 ... NA 0.05769231
0.8625000 0.7500000 ... 0.7307692 0.23750000
0.5096154...
2017 Jul 04
0
about adding a column for water year
Hello,
You have a '{' too many.
for(i in 1972:1985){
if(DF$year==i & DF$month %in% 1:9){
DF$wyear <- i
}else{
DF$wyear < i-1
}
}
}
I believe this is it.
Hope this helps,
Rui Barradas
Em 04-07-2017 19:31, lily li escreveu:
> Hi R users,
> I have a question about adding a column for wa...
2017 Jul 05
1
Help with reshape/reshape2 needed
...rary(prettyR)
stretch_df(tadf,1,2)
Jim
On Thu, Jul 6, 2017 at 6:50 AM, Ista Zahn <istazahn at gmail.com> wrote:
> The reason it doesn't work easily with reshape/reshape2 is that the
> order of the rows is not determined. Your answer could be
>
> 1957 1958 ... 1985 1986
> 0.8625000 0.7500000 ... 0.7307692 0.23750000
> 0.0733945 0.6435644 ... NA 0.05769231
> 0.5096154 NA ... NA 0.65137615
>
> or
>
> 1957 1958 ... 1985 1986
> 0.0733945 0.6435644 ... NA 0.05769231
> 0.8625000 0.750...