Displaying 4 results from an estimated 4 matches for "1980l".
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1980
2012 May 19
4
weighted averages for two variables
Hi R users,
I have a dataset with multiple variables and i'm trying to weigh average
depths for fish species per year by their abundance (CPUE. I have tried the
weighted.mean function but as i have two columns for the x value the lenghts
differ with the w (CPUE). How do I solve this problem?
So far I have tried this:
data<-by(allspecies, list(allspecies$Depth, allspecies$Year),
2010 Jan 16
2
Drought severity index: Excel to R
Dear all,
I'm trying to make an R code for the drought severity index (DSI)
developed by Philips and McGregor (1998). You can refer to the
description of the algorithm on page 19 from
http://dissertations.port.ac.uk/229/01/MaloneS.pdf
The code is given in Excel as the following and can be found on page 60
from the same link.
C7 =
IF(C6<0,IF(@SUM(A6:A1)<0,C6+A6,"0"),
2012 Sep 02
3
Loading Chess Data
All,
What would be the most efficient way to load the data at the following
address into a dataframe?
http://ratings.fide.com/top.phtml?list=men
Thanks,
David
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2012 Jul 10
2
estimation of NA by predict command
..., 121L, 253L, 385L, 517L, 649L, 781L, 913L, 1045L, 1177L,
1309L, 1441L, 1573L, 1705L, 1837L, 1969L, 2101L, 2233L, 2365L,
2497L, 2629L, 2761L, 2893L, 3025L, 3157L, 3289L, 3421L, 3553L,
3685L, 3808L, 3929L, 132L, 264L, 396L, 528L, 660L, 792L, 924L,
1056L, 1188L, 1320L, 1452L, 1584L, 1716L, 1848L, 1980L, 2112L,
2244L, 2376L, 2508L, 2640L, 2772L, 2904L, 3036L, 3168L, 3300L,
3432L, 3564L, 3696L, 3819L, 3940L, 4017L), .Label = c("01.01.1962",
"01.01.1963", "01.01.1964", "01.01.1965", "01.01.1966", "01.01.1967",
"01.01.1969", &q...