search for: 1960

Displaying 20 results from an estimated 306 matches for "1960".

Did you mean: 1,60
2005 Sep 07
2
Month recognition issue
...t; month.abb [1] "Jan" "Feb" "Mar" "Apr" "May" "Jun" "Jul" "Aug" "Sep" "Oct" [11] "Nov" "Dec" I get the abbreviated english version of every month > x <- c("1-jan-1960", "2-feb-1960", >"31-mar-1960", "30-apr-1960","2-may-1960", >"31-jun-1960", "30-jul-1960","2-aug-1960", >"31-sep-1960", "30-oct-1960", "30-nov-1960", >"30-dec-1960"); &...
2005 Sep 07
1
Language issue
...t; month.abb [1] "Jan" "Feb" "Mar" "Apr" "May" "Jun" "Jul" "Aug" "Sep" "Oct" [11] "Nov" "Dec" I get the abbreviated english version of every month > x <- c("1-jan-1960", "2-feb-1960", >"31-mar-1960", "30-apr-1960","2-may-1960", >"31-jun-1960", "30-jul-1960","2-aug-1960", >"31-sep-1960", "30-oct-1960", "30-nov-1960", >"30-dec-1960"); &...
2010 Nov 09
0
Preservar el nombre de un nodo en una lista después de unir dos listas diferentes
...6] -0.874 -0.874 -0.874 -0.874 -0.66 ... $ Anom_e1756: num [1:456] -0.984 -0.984 -0.984 -0.874 -0.464 ... $ Anom_e1773: num [1:456] -0.875 -0.95 -0.95 -0.838 -0.727 ... ... str(datos) List of 67 $ e1751.PtoLaCruz.cr.txt          :'data.frame': 456 obs. of  4 variables:  ..$ A  : int [1:456] 1960 1960 1960 1960 1960 1960 1960 1960 1960 1960 ...  ..$ M  : int [1:456] 1 2 3 4 5 6 7 8 9 10 ...  ..$ PRE: num [1:456] 0 0 0 0 10.6 ...  ..$ COD: Factor w/ 2 levels "FE","O": 2 2 2 2 2 2 2 2 2 2 ... $ e1756.ChaparroC.cr.txt          :'data.frame': 456 obs. of  4 variables...
2004 May 03
3
R 1.9.0 on AIX, 64-bit
...[4,] 2 4 > stopifnot(typeof(res) == "list") > ## were not implemented in 1.8.1 > > > ## Date objects with NA's > (t1 <- strptime(c("6. Aug. 1930", "3. Nov. 1925", "28. Mar. 1959", + NA, paste(1:29," Feb. 1960", sep=".")), + format = "%d. %b. %Y")) [1] "1930-08-06" "1925-11-03" "1959-03-28" NA "1960-02-01" [6] "1960-02-02" "1960-02-03" "1960-02-04" "1960-02-05" "1960-...
2004 Dec 06
0
R doesn't understand dates prior to 1 Jan 1970
...st by changing "1910" to "1970", but it crops up later, too (reg-tests-1.R): > > ## Date objects with NA's > > (t1 <- strptime(c("6. Aug. 1930", "3. Nov. 1925", "28. Mar. 1959", > + NA, paste(1:29," Feb. 1960", sep=".")), > + format = "%d. %b. %Y")) > [1] "1930-08-06" "1925-11-03" "1959-03-28" NA "1960-02-01" > [6] "1960-02-02" "1960-02-03" "1960-02-04" "1960-02-05&quot...
2002 Apr 02
1
cbind.ts bug?
The following creates a time series tt1 whose values rise from 1 to 20 and another time series tt2 each of whose values are 10 larger than the corresponding value in tt1. When we attempt to bind them together as columns, the entry after Dec 1960 is erroneously listed as NA 1960 instead of Jan 1961. If n is changed to either 19 or is changed to 21 in the example below, the example suddenly works correctly. > n <- 20 > x <- 1:n > tt1 <- ts(x,start=c(1960,2),freq=12) > tt2 <- ts(10+x,start=c(1960,2),freq=12) >...
2008 Mar 02
1
question on lag.zoo
...hat I assumed. > x <- zoo(11:21) > z <- zoo(1:10, yearqtr(seq(1959.25, 1961.5, by = 0.25)), frequency = 4) > x 1 2 3 4 5 6 7 8 9 10 11 11 12 13 14 15 16 17 18 19 20 21 > lag(x) 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 20 21 > z 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4 1961 Q1 1961 Q2 1961 Q3 1 2 3 4 5 6 7 8 9 10 > lag(z) 1959 Q1 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4 1961 Q1 1961 Q2 1 2 3 4 5 6 7 8 9...
2004 Apr 23
4
is.na(valid_date) too often true on SGI MIPS (PR#6814)
Full_Name: George N. White III Version: 1.9.0 OS: Irix 6.5.21m Submission from: (NULL) (142.176.61.212) R-1.9.0 built using the SGI MIPSPro compilers Installation directory: /usr/local C compiler: c99 -OPT:IEEE_NaN_inf=ON -mips4 -n32 -O3 -OPT:Olimit_opt=on C++ compiler: CC -OPT:IEEE_NaN_inf=ON -mips4 -n32 -O3 -OPT:Olimit_opt=on -LANG:std Fortran compiler:
2011 Jun 13
1
maintaining row connections during aggregate
Dear All, I have several sets of data such as this: year jday avg_m3s 1 1960 1 4.262307 2 1960 2 4.242308 3 1960 3 4.216923 4 1960 4 4.185385 5 1960 5 4.151538 6 1960 6 4.133846 ... There is a value for each day of multiple years. In this particular data set it goes up to 1974. I am am looking to obtain the minimum and maximum values for each year, but a...
2006 Apr 17
1
as.Date / size of par
dear list, i have a problem plotting revenue against the date. the str. of date looks like: Class 'Date' num [1:10493] -3649 -3648 -3647 -3646 -3643 ... the head looks like: [1] "1960-01-05" "1960-01-06" "1960-01-07" "1960-01-08" "1960-01-11" [6] "1960-01-12" i´d like to plot it against the years, but can´t figure out how that works. an other problem is the size of par. i want to put two graphics in one sheet. that works...
2001 Oct 01
2
problem with strptime example (PR#811)
Hello, strptime is still not working correctly in my computer (Windows 98 and R Version 1.3.1) From x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") strptime(x, "%d%b%Y") I obtain [1] "NA" "NA" "NA" "NA" while x <- c("01011960", "02011960", "3131960", "3071960") strptime(x, &...
2012 Dec 17
1
subset handling
...43197 EA 1959 3 1.23709684580 EA 1959 4 1.91200005963 EA 1959 5 4.18354847346 EA 1959 6 5.18333338729 EA 1959 7 2.786451610112 EA 1959 8 1.615161311495 EA 1959 9 1.295333312878 EA 1959 10 1.200322614261 EA 1959 11 1.103333315644 EA 1959 12 1.0903226455 EA 1960 1 0.91580651838 EA 1960 2 0.90068973221 EA 1960 3 0.99258064604 EA 1960 4 2.01500005987 EA 1960 5 5.22516137370 EA 1960 6 7.86533338753 EA 1960 7 5.503548410136 EA 1960 8 3.169354811519 EA 1960 9 2.951000012902 EA 1960 10 3.548064514285 EA 1960 11 2.1...
2009 Oct 26
3
as.POSIXct month problem
Hi everybody When I try example of strptime x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") z <- strptime(x, "%d%b%Y") The result is; > z [1] NA NA NA NA I have got the same result with complete form of month but not with numeric form. Any idea? [[alternative HTML version deleted]]
2002 Oct 17
4
Newbie Time Series Questions
I have a data set of monthly river flows from 1960-2000, which are similar in structure to the nottem data: > klam.flow Oct Nov Dec Jan Feb Mar Apr May Jun Jul Aug Sep 1961 1461 1716 2524 1773 1906 2005 1756 1575 1387 983 1094 1382 1962 1907 2253 1985 1907 1769 1676 2634 1386 929 766 968 1309 ... I tried plotting with...
2010 Nov 16
0
renaming a list of data frames y calculating with lapply
...have some questions about lists indexing, names and the lapply function. first have a look to my data (names changed) it's a rainfall record for 67 stations, str(data) List of 67 $ e9999.somename.xx.txt :'data.frame': 456 obs. of 5 variables: ..$ Y : int [1:456] 1960 1960 1960 1960 1960 1960 1960 1960 1960 1960 ... ..$ M : int [1:456] 1 2 3 4 5 6 7 8 9 10 ... ..$ PRE : num [1:456] 0 0 0 0 10.6 ... ..$ COD : Factor w/ 2 levels "FE","O": 2 2 2 2 2 2 2 2 2 2 ... ..$ piece: num [1:456] -0.874 -0.874 -0.874 -0.874 -0.66 ... ... on a...
2011 Dec 13
5
[Bug 1960] New: Running sshd in wrong SELinux context causes segmentation fault when a user logs in
https://bugzilla.mindrot.org/show_bug.cgi?id=1960 Bug #: 1960 Summary: Running sshd in wrong SELinux context causes segmentation fault when a user logs in Classification: Unclassified Product: Portable OpenSSH Version: 5.8p1 Platform: amd64 OS/Version: Linux...
2009 Mar 21
5
macro in a loop
Hi there, Thanks for your time in advance. I am trying to read in multiple files. For example, data.1940 <- read.table("c:/data/1940.csv",header=TRUE,sep=",") data.1950 <- read.table("c:/data/1950.csv",header=TRUE,sep=",") data.1960 <- read.table("c:/data/1960.csv",header=TRUE,sep=",") How can I write a loop to read the data? I was trying to use the following year<-c(1940,1950,1960) for (j in 1:3){ data.year[j] <- read.table("c:/data/year[j] .csv",header=TRUE,sep=&qu...
2004 Dec 02
6
dropping rows
...estions, but I can't seem to figure this out. I have a dataframe called master containing 30-odd variables. In this dataframe, I have observations across these 30 variables from 1930 to 2003 (I've made a "year" variable). How can I drop all rows for which the year is less than 1960? I'm assuming something with ifelse() but I can't quite figure it out. I would appreciate a suggestion of some syntax. Thanks! Toby
2017 Jul 05
4
Help with reshape/reshape2 needed
Hi all: I'm struggling with getting my data re-formatted using functions in reshape/reshape2 to get from: 1957 0.862500000 1958 0.750000000 1959 0.300000000 1960 0.287500000 1963 0.675000000 1964 0.937500000 1965 0.025000000 1966 0.387500000 1969 0.087500000 1970 0.275000000 1973 0.500000000 1974 0.362500000 1976 0.925000000 1978 0.712500000 1979 0.337500000 1980 0.700000000 1981 0.425000000 1982 0.212500000 1983 0.312500000 1986 0.237500000 1958 0.64356435...
2001 Jan 11
2
problem with strptime example (PR#811)
On Thu, 11 Jan 2001 stephen@anc.ed.ac.uk wrote: > Hi, > > The help file for strptime has the following code which doesn't work > for me: > > ## read in date info in format `ddmmmyyyy' > x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960") > z <- strptime(x, "%d%b%Y") > > z > [1] "NA" "NA" "NA" "NA" > > Do these work for other people? Yes, on several platforms. It will be a problem w...