search for: 16.8

Displaying 20 results from an estimated 87 matches for "16.8".

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2013 Apr 15
2
Remove Rows Based on Factor
Dear R Helpers, I did a search for deleting rows based on conditions but wasn't able to find an example that addressed the error that I am getting. I am hoping that this is a simple syntax phenomenon that somebody else knows off the top of their head. My apologies for not providing a reproducible example but I think that the information given will allow someone to give me a hint. I want to
2020 Apr 30
0
Certified Asterisk 16.8-cert2 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert2. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert2 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2020 Jun 19
0
Certified Asterisk 16.8-cert3 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert3. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert3 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2020 Nov 05
0
Asterisk 13.37.1, 16.14.1, 17.8.1, 18.0.1 and 16.8-cert5 Now Available (Security)
The Asterisk Development Team would like to announce security releases for Asterisk 13, 16, 17 and 18, and Certified Asterisk 16.8. The available releases are released as versions 13.37.1, 16.14.1, 17.8.1, 18.0.1 and 16.8-cert5. These releases are available for immediate download at https://downloads.asterisk.org/pub/telephony/asterisk/releases
2020 Apr 30
0
Certified Asterisk 16.8-cert2 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert2. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert2 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2020 Jun 19
0
Certified Asterisk 16.8-cert3 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert3. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert3 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2007 Nov 14
2
adding in missing values in a sequence
Hi, I have a data frame with two columns of data, one an indexing column and the other a data column. My issue is, this data frame is incomplete and there are missing lines. I want to know how I can find and add data into these missing lines. See example below ## Example data data <- data.frame(index=c(1:4,6:10), data=c (1.5,4.3,5.6,6.7,7.1,12.5,14.5,16.8,3.4)) index data 1 1
2013 Jan 03
2
Sas by function in R
Hello, It's an alternative to use SAS by function in R? I want to plot d histograms by plot.from example bellow: Thank you! plot d 1 1 16.3 2 1 25.0 3 1 57.8 4 1 17.0 5 2 10.8 13 2 96.4 17 3 76.0 18 3 32.0 19 3 11.0 20 3 11.0 24 3 106.0 25 3 12.5 21 4 19.3 22 4 12.0 26 4 15.0 27 5 99.3 32 7 11.0 36
2020 Jun 01
1
Asterisk 16 Certified 16.8 and MagicJack Incoming Calls
I upgraded our Asterisk 13 LTS to Asterisk 16 Certified 16.8 yesterday and converted form SIP to PJSIP using the python script as a start and then mofiying from there.  I ran into an issue when testing that incoming calls from MagicJack would go silent after about 10 seconds.  This happened while in the automated attendant area.  This problem did not occur with Asterisk 13 LTS.  I reverted PJSIP
2020 Nov 05
0
AST-2020-002: Outbound INVITE loop on challenge with different nonce.
Asterisk Project Security Advisory – AST-2020-002 Product Asterisk Summary Outbound INVITE loop on challenge with different nonce. Nature of Advisory Denial of Service Susceptibility Remote
2005 Jun 15
4
Multiple line plots
Greetings, I would like to plot three lines on the same figure, and I am lost. There is an answer to a similar thread… but I tried matplot and it is beyond me. An example of the data follows: Year EM IM BM 1983 9.1 16.8 -7.7 1984 12.0 18.0 -6.0 1985 13.6 19.1 -5.5 1986 12.4 17.3 -4.9 1987 14.6 20.3 -5.7 1988 20.6 23.3 -2.6 1989 25.0 27.2 -2.2 1990 28.4 30.2 -1.8 1991 33.3 31.2 2.1 1992 40.6
2020 Nov 05
0
AST-2020-001: Remote crash in res_pjsip_session
Asterisk Project Security Advisory - AST-2020-001 Product Asterisk Summary Remote crash in res_pjsip_session Nature of Advisory Denial of service Susceptibility Remote authenticated sessions Severity
2006 Feb 06
3
iteration history
Dear R Users I would like to use optim function to optimize a function. I read help but I couldn't find what I need: is it possible to get information after each iteration, for example as there is in MATLAB: Gradient's Iteration Func-count f(x) Step-size infinity-norm 0 24 388.976
2009 Dec 22
2
3-D barplot
Hi, I would like to create a 3 dimensional barplot of 16 odds ratios that demonstrate an interaction between two variables (CD14 and CD23). Here is an example of what the graph I would like to produce (http://www.xfy.com/manual/dev/developer/1.4/spec/image/chart/type_3d.gif): Here is are the odds ratios I would like to graph: Odds ratios CD14-1 CD14-2 CD14-3 CD14-4 CD23-1 1 0.61
2012 Oct 11
4
characters, mathematical expressions and computed values
Hello, I have to add "Age (bar(x)=14.3) as a title on a chart. I am unable to get this to working. I have tried bquote, substitute and expression, but they are only doing a part of the job. new<- c(14.3, 18.5, 18.1, 17.7, 18, 15.9, 19.6, 17.3, 17.8, 17.5, 15.4, 16.3, 15, 17.1, 17.1, 16.4, 15.2, 16.7, 16.7, 16.9, 14.5, 16.6, 15.8, 15.2, 16.2, 15.6, 15, 17.1, 16.7, 15.6, 15, 15.8, 16.8,
2020 Apr 30
0
Certified Asterisk 16.8-cert1 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert1. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert1 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2020 Apr 30
0
Certified Asterisk 16.8-cert1 Now Available
The Asterisk Development Team would like to announce the release of Certified Asterisk 16.8-cert1. This release is available for immediate download at https://downloads.asterisk.org/pub/telephony/certified-asterisk The release of Certified Asterisk 16.8-cert1 resolves several issues reported by the community and would have not been possible without your participation. Thank you! The following
2009 Apr 19
0
Tow to perform diallel analysis in R?
I want to use a diallel analysis in R, for some of my own data. I've been through the primary literature and textbooks, and remain stumped as to how to implment this in R. I can illustrate the problem using a published example dataset: [Cockerham and Weir (1977) Quadratic Analyses of Reciprocal Crosses. Biometrics, Vol. 33, No. 1 pp. 187-203] In this study, 8 different individuals were
2010 Dec 27
3
linear regression with dates
Hi, I am trying to do simple linear regression using dates in R but receiving error messages. With the data shown below, I would like to regress x on y. x y 11/12/1999 56.8 11/29/1999 17.9 01/04/2000 27.4 1/14/2000 96.8 1/31/2000 49.5 R gives the following error messages after reading the linear regression command: Error in storage.mode(y) <-
2013 Apr 10
6
means in tables
Hi. I have 2 tables, with same dimensions (8000 x 5). Something like: tab1: V1 V2 V3 V4 V5 14.23 1.71 2.43 15.6 127 13.20 1.78 2.14 11.2 100 13.16 2.36 2.67 18.6 101 14.37 1.95 2.50 16.8 113 13.24 2.59 2.87 21.0 118 tab2: V1 V2 V3 V4 V5 1.23 1.1 2.3 1.6 17 1.20 1.8 2.4 1.2 10 1.16 2.6 2.7 1.6 11 1.37 1.5 2.0 1.8 13 1.24 2.9 2.7 2.0 18 I need generate a table of averages, the