Displaying 1 result from an estimated 1 matches for "10q3".
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1093
2012 May 08
2
How to deal with a dataframe within a dataframe?
...ks, robert
> agg <- aggregate(formula=df$value ~ df$quarter + df$tool,
+ FUN=cp.cpk, lsl=1300, usl=1500)
> head(agg)
df$quarter df$tool df$value
1 09Q3 VS1A 1.800534, 1.628483
2 10Q1 VS1A 1.299652, 1.261302
3 10Q2 VS1A 1.699018, 1.381570
4 10Q3 VS1A 1.311681, 1.067232
> head(agg["df$value"])
df$value
1 1.800534, 1.628483
2 1.299652, 1.261302
3 1.699018, 1.381570
4 1.311681, 1.067232
> class(agg["df$value"])
[1] "data.frame"
> head(agg["df$value"][1]) # trying to select 1st co...