search for: 100,100

Displaying 20 results from an estimated 90 matches for "100,100".

Did you mean: 100,000
2012 Feb 21
2
Using substitute in nested function calls
...mbers, I really, like the feature that one can call R functions with mathematical expressions, e.g. curve(x^2, 0, 1) I wonder, how I can construct in a simple way a function like mycurve = function (expr) {...} such that that a call mycurve(x^2) has the same effect as the call curve(x^2, -100,100) Below is some code that works, but it seems much to complicated: it first substitutes and deparses the expression, creates a string with the new function call and then parses and evaluates the string again. Does anybody know a simpler, more elegant solution? mycurve = function(expr) {...
2012 May 11
1
domain/number line/range reduction problem
...inclusion/exclusion issue here for simplicity, but in a perfect world the resulting ranges would not include the s range endpoints and would include endpoints of the x range if they were not eliminated by an s range. Is there some function(s) in R that would make this easy? Ex 1. For: x_rng = c(-100,100) s1_rng = c(-25.5,30) s2_rng = c(0.77,10) s3_rng = c(25,35) s4_rng = c(70,80.3) s5_rng = c(90,95) I would get: xa_rng = c(-100,-25.5) xb_rng = c(35,70) xc_rng = c(80.3,90) xd_rng = c(95,100) Ex 2. For: x_rng = c(-50.5,100) s1_rng = c(-75.3,30) I would get: xa_rng = c(30,100) Ex 3. For: x_...
2012 May 12
2
range segment exclusion using range endpoints
...problem: I have endpoints of one x range (x_rng) and an unknown number of s ranges (s[#]_rng) also defined by the range endpoints. I'd like to remove the x ranges that overlap with the s ranges. The examples below demonstrate what I mean. What is the best way to do this? Ex 1. For: x_rng = c(-100,100) s1_rng = c(-25.5,30) s2_rng = c(0.77,10) s3_rng = c(25,35) s4_rng = c(70,80.3) s5_rng = c(90,95) I would get: -100,-25.5 35,70 80.3,90 95,100 Ex 2. For: x_rng = c(-50.5,100) s1_rng = c(-75.3,30) I would get: 30,100 Ex 3. For: x_rng = c(-75.3,30) s1_rng = c(-50.5,100) I would get: -75.3...
2020 Oct 06
4
Solving a simple linear equation using uniroot give error object 'x' not found
...I hope someone can tell we how I can fix the problem if(!require(rootSolve)){install.packages("rootSolve")} library(rootSolve) # Define the function yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) # Prove the function and a call to the function work yfun(10,100,10) # use uniroot to find a solution to the # function in the range -100 to 100 uniroot(yfun(x,10,20),c(-100,100)) My output: > # Define the function > yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) > # Prove the function and a call to the funciton works &g...
2020 Oct 06
0
Solving a simple linear equation using uniroot give error object 'x' not found
...roblem > > if(!require(rootSolve)){install.packages("rootSolve")} > library(rootSolve) > > # Define the function > yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) > # Prove the function and a call to the function work > yfun(10,100,10) > # use uniroot to find a solution to the > # function in the range -100 to 100 > uniroot(yfun(x,10,20),c(-100,100)) > > > My output: >> # Define the function >> yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) >> # Prove...
2006 Jun 27
3
looking for a more efficient R code.
Dear R-users I have four simple linear models, which are all in the form of a*X+b The estimated parameter vectors are a <- c(1,2,3,4) b <- c(4,3,2,1) My goal is to draw a plot where x-axis is X (range from -100 to 100) and y-axis is the sum of all four linear models X <- seq(-100,100, length=10000) plot(X, sum of the four linear functions) I started with a function for summing summing <- function(a,b) {temp <-0; for (i in 1:length(a)) temp <- temp + a[i]*X+b[i] } plot(X, summing(a,b)) I...
2010 Dec 18
1
how to use expression as function arguements?
Hi all, ##################################### integ=function(f,n){ # computes vector y = f(x) x=runif(10000) y=f hatI=mean(y) hatI } # example of use integ(x^2+x+100,100) ##################################### it returns an error says no obj 'x' how do I 'tell' R to treat 'f' as an input expression? Thanks. casper -- View this message in context: http://r.789695.n4.nabble....
2012 Jul 20
3
Crosstab with Average and Count
I have the following data: x <- as.factor(c(1,1,1,2,2,2,3,3,3)) y <- as.factor(c(10,10,10,20,20,20,30,30,30)) z <- c(100,100,NA,200,200,200,300,300,300) I could create the cross tab of x and y with Sum of z as its elements using the xtabs function as follows: # X Vs. Y with Sum Z xtabs(z ~ x + y) y x 10 20 30 1 200 0 0 2 0 600 0 3 0 0 900 How do I replace the sum with average and count...
2009 Jun 08
2
Re flect Back to Back Histograms in x-axis?
I've looked long and hard for this, but maybe I am missing something... There is a nice module that displays histograms reflected in the y axis, i.e. http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=136 but is it possible to reflect in the x-axis, so to have two datasets, one pointing up and one down rather than left and right? I haven't been able to find a way to plot this
2010 Oct 07
1
Quantile question
Simple Question I have 100x100 matrix and I want to calculte each row's 30,50% quantile ex) a=matrix(rnorm(10000),100,100) quantile(a[1,],c(0.3,0.5)) quantile(a[2,],c(0.3,0.5)) . . . . I want get results at once. so I try quantile(a[1:100,],c(0.3,0.5)) but I can get what I exactly want. How can I calculte that?...
2005 Jun 30
0
vecortizing uniroot() for numerical solutions
...^2)) # I'd like to solve it across a parameter space of d1 and d2, holding # h1 and h2 constant. # It seems that uniroot() can do it, but I don't see how to vectorize it. # This works just fine: R12 = function(d1, d2, h1, h2) (d1/(h1^2))-(h2*(d2^2)) uniroot(R12, interval=c(-100,100), tol=0.0001, d2=1, h1=1, h2=1) # but to explore the entire parameter space it seems I would need a series of loops R12 = function(d1, d2, h1, h2) (d1/(h1^2))-(h2*(d2^2)) df1=data.frame(h1=numeric(0), h2=numeric(0),d1=numeric(0),d2=numeric(0)) h1=1 h2=1 for(i in 1:5) { output=uniroot(...
2012 Jul 14
1
changing the x axis labels in a time series plot
...xis labels in a time series graph, from its default numbering (which starts at 1 and increments by 1), to values I have in another vector, "Year". It has to be a time series graph, I don't want to have to use a scatter plot because there are many lines to draw. Example: z = cbind(1:100,100:1); Year = 1322:1421 windows() plot.ts(z[,1:2],,"single", xaxt="n", xlab="") axis(1,at=Year) This doesn't work, not any of the permutations I've tried with the various arguments to plot.ts and axis. Thanks for any help. [[alternative HTML version deleted...
2010 May 26
2
xlim/ylim and actual axis length
...plotting wizards, when plotting in R, the actual lengths of the axes are slightly greater than the ranges of the x/y variables or xlim/ylim values. how do I control the amount by which the axes are enlarged? Is there a way to enforce that the lengths of the axes equal xlim/ylim? example: plot(0:100,0:100,pch="+") it can be observed, that the x- and y-axis join at approx. (-4,-4) and (104,104). If I want the axes to join at (0,0) and (100,100) I have to cheat R into doing it by providing wrong xlim/ylim values: plot(0:100,0:100,pch="+",xlim=c(4,96),ylim=c(4,96)) is there...
2012 May 05
1
Correct use of ddply with own function
...max(x2) df <- data.frame(x1,x2,x3) df } Probably this is not the best form of the function, but at least it produces what I want (data to plot a cumulative count curve). This function works on a single vector but I have a melted dataframe like: var1 <- rep(c("a","b"),c(100,100)) var2 <- runif(200,1,50) df.test <- data.frame(var1,var2) ..and I want to apply that function on var2 but splitted by the variable var1. I think this might be a case for ddply... anything like: ddply(df.test,.(var1),fn(var2))... maybe someone know how to do that (modifying my function...
2004 Oct 06
3
crossprod vs %*% timing
...A %*% a' many many times, and performance is becoming crucial. With f1 <- function(a,X){ ignore <- t(a) %*% X %*% a } f2 <- function(a,X){ ignore <- crossprod(t(crossprod(a,X)),a) } f3 <- function(a,X){ ignore <- crossprod(a,X) %*% a } a <- rnorm(100) X <- matrix(rnorm(10000),100,100) print(system.time( for(i in 1:10000){ f1(a,X)})) print(system.time( for(i in 1:10000){ f2(a,X)})) print(system.time( for(i in 1:10000){ f3(a,X)})) I get something like: [1] 2.68 0.05 2.66 0.00 0.00 [1] 0.48 0.00 0.49 0.00 0.00 [1] 0.29 0.00 0.31 0.00 0.00...
2004 Aug 27
4
SWIG Bug
...is static there isn''t a self value there, shifting all arguments over one. One way to demonstrate this is with the following sample: require ''wx'' #begin sample include Wx; class TestFrame < Frame def initialize() super(nil,-1,"Test",Point.new(100,100),Size.new(100,100)) @win = Window.new(self,-1,Point.new(0,0),Size.new(100,100)) end end class TestApp < App def on_init() TestFrame.new().show(true) end end TestApp.new().main_loop() #end sample On my build, Window won''t create complaining that there...
2015 Mar 19
3
Familia *pply
...ones de la familia *pply en todo lo que puedo, pero todavía no es algo que me surja tan rápidamente o naturalmente al momento de los loops como usar for(). Conozco las ventajas de usar estas funciones y por eso mi intento de hacerme de ellas. Por ejemplo en este problema: data=matrix(rnorm(100*20),20,100) col=sample(1:100,100) t1=Sys.time() medias=replicate(1000,{ sel=sample(1:20,10) pareja=sample(sel,100,replace = T) ta=Sys.time() *recep=NULL** ** for(i in 1:100){** ** n=col[i]** ** m=pareja[i]** ** c=data[m,n]** **...
2015 Mar 19
2
Familia *pply
...ía causar problemas, envío de nuevo el código sin formatos. La idea básica es para un set de números de columnas (desordenados) y un set de numeros de fila el loop lo que hace es ir a la fila y columna correspondiente de data, tomar el valor y luego hacer la media sobre esos. data=matrix(rnorm(100*20),20,100) col=sample(1:100,100) t1=Sys.time() medias=replicate(1000,{ sel=sample(1:20,10) pareja=sample(sel,100,replace = T) ta=Sys.time() recep=NULL for(i in 1:100){ n=col[i] m=pareja[i] c=data[m,n] recep=c(recep,c) } tb=Sys.time() media=mean(recep)...
2016 Apr 05
5
R-dvel [robustness Simulation study of 2 sample test on several combination of factors ]
...estions/36404707/simulation-study-of-2-sample-test-on-different-combination-of-factors#> If I wish to conduct a simulation on the robustness of two sample test by using R language, is that any ways in writing the code? There are several factors (sample sizes-(10,10),(10,25),(25,25),(25,50),(25,100),50,25),(50,100), (100,25),(100,100)) (standard deviation ratio- (1.00, 1.50, 2.00, 2.50, 3.00 and 3.50)) distribution of gamma distribution with unequal skewness and equal skewness I wish to test the pooled variance t test and welch t test and mann whitney by using the above combination of facto...
2004 Feb 29
0
[RESEND] Mixer + Joystick problems with a game. Anybody willing to debug?
...rrun on sound buffer 0x4534ff20 > fixme:dinput:JoystickAImpl_SetProperty (this=0x47d00090,<guid- > 0x0004>,0x4081fa78) > fixme:dinput:JoystickAImpl_SetProperty ph.dwSize = 24, ph.dwHeaderSize > =16, ph.dwObj = 258, ph.dwHow= 2 > fixme:dinput:JoystickAImpl_SetProperty proprange(-100,100) > fixme:dinput:JoystickAImpl_SetProperty (this=0x47d00090,<guid- > 0x0004>,0x4081fa78) > fixme:dinput:JoystickAImpl_SetProperty ph.dwSize = 24, ph.dwHeaderSize > =16, ph.dwObj = 514, ph.dwHow= 2 > fixme:dinput:JoystickAImpl_SetProperty proprange(-100,100)