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I've never noticed this before, though it's probably not new. In 1.2.3 for Windows, if I print a short vector the formatting is different than if I print a long one, whether or not they fit on one line. The short/long split appears to be between 9 and 10 elements: > 1:9 [1] 1 2 3 4 5 6 7 8 9 > 1:10 [1] 1 2 3 4 5 6 7 8 9 10 > sqrt(1:9) [1] 1.000000 1.414214

Hi list, My attention was drawn to the foreach package by recent posts...I decided to have a look... I'm using R.2.9.1 on Windows, I have downloaded the foreach package today (v 1.2.1), together with iterators (v. 1.0.1) and codetools (v.0.2-2). Full of hope I try the most simple thing of all out of the package vignette : > x <- foreach(i = 1:3) %do% sqrt(i) and get : > Erreur

> Date: Wed, 30 Jun 1999 11:12:24 +0200 (MET DST) > From: Torsten Hothorn <hothorn at amadeus.statistik.uni-dortmund.de> > > yesterday I had a little shock using qr (or lm). having a matrix > > X <- cbind(1,diag(3)) > y <- 1:3 > > the qr.coef returns one NA (because X is singular). So I computed the > Moore-Penrose inverse of X (just from the

I am faced with a situation wherein I have to use multiple lapply's. The pseudo-code could be approximated to something as below: For each X from i=1 to n For each Y based on j=1 to m For each F from 1 to f Do some calculation based on Fij Store Xi,Yj = Fij End For F End for Y End for X Is there anyway to optimize the processing logic further? I *guess* using the multiple lapply

Hello, I am working with a matrix of multilocus genotypes for ~180 individual snail samples, with substantial missing data. I am trying to calculate the pairwise genetic distance between individuals using the stats package 'dist' function, using euclidean distance. I took a subset of this dataset (3 samples x 3 loci) to test how euclidean distance is calculated: 3x3 subset used

Hi, I'm experimenting with a few learners that require a matrix as their input. (Currently svmpath, vbmp, etc.) I currently have a dataframe with 50 columns and 20,000 rows. I tried using: x <- as.matrix(my_data.frame) If I then as, "is.matrix(x)", I get TRUE. However everywhere I've tried to use the matrix returns errors. Is there a step I'm missing? Thanks! -N

I have a 50*50 matrix,some entry are NAs,I want to replace these NA by 0,so can I use some syntax to do so other than using ifelse? I tried to use replace(a,NA,0),it didnt work~~(a is matrix name) Thanks~ [[alternative HTML version deleted]]

Trying to find a quick/slick/easily interpretable way to collapse a data set. Suppose I have a data set that looks like this: h <- structure(list(INDEX = structure(1:6, .Label = c("1", "2", "3", "4", "5", "6"), class = "factor"), TICKS = c(0, 0, 0, 0, 0, 3 ), BROOD = structure(c(1L, 1L, 2L, 3L, 3L, 3L), .Label =

Why does the expression "(-8)^(1/3)" return NaN, instead of -2? This is not answered by http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-powers-of-negative-numbers-wrong_003f Thanks, Dave [[alternative HTML version deleted]]