search for: 1.5

Thanks for all the helpful responses. I include the data file and the syntax file for reference. Again, if I use the fields function, as is, I get the message: Error in svd(tempM) : error 159 in dsvdc using traceback, I get: > traceback() 4: stop(paste("error ", z$info, " in dsvdc")) 3: svd(tempM) 2: Krig(x, Y, cov.function = rad.cov, m = m, decomp = decomp,

uhps!! I forgot to tell you that I'm running R 0.99.0 for windows32 on windows 95 osr2. Thank you very much for the latest R-1.0.0 (even if I don't tried it yet)!!! Andrea Rossetti University of Perugia (Italy) Statistical Science Department. ---------- Forwarded message ---------- Date: Tue, 29 Feb 2000 17:03:51 +0100 (MET) From: Andrea Rossetti <rossetti at markov.stat.unipg.it>

Hi R-List, I have a question regarding R-language formats, I think. I am producing a series of graphs (using plot, barplot, barchart, and bwplot, using either text or mtext to place values on the graphs) and tables for a Francophone country. In fact, I have already done so. However, while they are pleased with the results they've requested I convert all of my decimal points into the French

Dear R and S People: I have run across something very strange. Here is a function that I wrote for R: boot1 <- function(y,method="f",p=1) { n1 <- length(y) n2 <- n1*p n3 <- n2 - 1 a <- 0.5*(outer(1:n3,1:n3,function(x,y){n2 - pmax(x,y)})) return(a) } and here is the R output: > y1 [1] 9 8 7 3 6 > source("boot1.R") > boot1(y=y1,p=4) [,1] [,2]

Dear All, Consider the following code: pdf(file="figure.pdf",family="URWPalladio") curve(dlnorm(x,0,1.5),0,10,xlim=c(0,10),ylim=c(0,0.85),axes=F,xlab="",ylab="f") segments(exp(-1.5^2),0,exp(-1.5^2),dlnorm(exp(-1.5^2),0,1.5),lty="dashed") segments(1,0,1,dlnorm(1,0,1.5),lty="dashed")

Hello All, I am new to R and am having a problem. I have the following 29 x 5 array called temp with a mode "list". Sincere Exciting Competent Sophisticated Rugged 3.5 2.5 3.8 3.5 3.0 2.0 2.5 3.5 2.5 2.3 2.8 3.0 2.3 1.5 1.8 2.0 4.0 2.8 1.5 4.5 2.5 1.5 1.8 1.3 1.3

Dear all, I have noticed a little change in the behaviour of as.factor from R-2.2.1 to R-2.3.0, and can't find it in the NEWS. In R-2.3.0: > times <- 1:5 > class(times) <- "Date" > as.factor(times) [1] 1 2 3 4 5 Levels: 1 2 3 4 5 In R-2.2.1: > as.factor(times) [1] 1970-01-02 1970-01-03 1970-01-04 1970-01-05 1970-01-06 Levels: 1970-01-02 1970-01-03 1970-01-04

Dear all, I have noticed a little change in the behaviour of as.factor from R-2.2.1 to R-2.3.0, and can't find it in the NEWS. In R-2.3.0: > times <- 1:5 > class(times) <- "Date" > as.factor(times) [1] 1 2 3 4 5 Levels: 1 2 3 4 5 In R-2.2.1: > as.factor(times) [1] 1970-01-02 1970-01-03 1970-01-04 1970-01-05 1970-01-06 Levels: 1970-01-02 1970-01-03 1970-01-04

Hello, A made a xyplot using the lattice library in R (latest version). The publisher of our paper has requested: 1. all tick marks should point inwards instead of outwards. 2. All lines should be thicker (lines, axes, boxes, etc. Everything). Lines is easy...I used: lwd=1.5 but what about the lines of the axes, and the lines that build up the plot itself?....? Any

Hello, I am trying to plot SADIE red-blue plots of cluster indicies using filled.contour. I want a plot which only has three bins for the data: <-1.5, -1.5 - 1.5, >1.5, but I am having trouble getting there. example X1 X2 X3 X4 X5 1 -5 -4.5 1.0 4.5 6 2 -3 -2.0 1.2 -1.0 3 3 0 0.0 0.0 -0.5 -1 4 -2 -3.0 1.0 1.5 3 5 -6 -2.0 0.5 3.0 2 example<-as.matrix(example)

useR's, I am trying to find a quick way to change some values in a list that are subject to a condition to be NA. Consider the 3x1 matrix: delta <- matrix(c(2.5,2.5,1), nrow = 1) And consider the list named v that has 3 elements > v v[[1]] [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [1,] 4.25 3.25 2.25 1.25 0.25 0.75 1.75 2.75 3.75 4.25

Is the following developed in my console output a recognized bug or am I using the cat function incorrectly? Thanks, Stan > ifelse(class(data[[n]])!="factor",{print("yes")},{print("no")}) [1] "yes" [1] "yes" > ifelse(class(data[[n]])!="factor",{cat("yes")},{cat("no")}) yesError in ans[test & !nas] <-

raw <- read.csv(file=filename, head=TRUE,sep=",") I've read in a csv file, and I'm looking to access a column whose name is held in a string. For example, I want to access raw$one or raw$two, but this will depending on the string. Let's say that the string is decision<-"one". How would I access raw$one? The following doesn't work:

Tomasz Ciolek <tmc@goldweb.com.au> on 13.11.2001 01:51:25 An: Thomas Schweikle <tschweikle@fiducia.de> Kopie: "Tomasz Ciolek <tmc" Thema: Re: rsync exclude/include [FIDUCIA virengepr?ft - ohne Gew?hr, da? alle bekannten Viren und deren Varianten erkannt wurden.] > Umm loose the spaces between the - and the pattern?? removing spaces changes matching to

Hello, I'll use part of the iris dataset for an example of what I want to do. > data(iris) > iris<-iris[1:10,1:4] > iris Sepal.Length Sepal.Width Petal.Length Petal.Width 1 5.1 3.5 1.4 0.2 2 4.9 3.0 1.4 0.2 3 4.7 3.2 1.3 0.2 4 4.6 3.1 1.5

Hello, First time posting to this mail list. I'd like to use R in the most efficient way. I'm accomplishing what I want, but feel there is a more R'ish way to do it. Just learning R. *My goal: get ranks of value across rows with row names and column names intact.* I'm guessing one of the [?]apply functions will do what I need, but I couldn't sort out which one (after a lot

Would anyone help me solve my problem with R, please? I am very new to R. I am doing logistic regression analysis on the presence/absence of salamanders using several predictor variables, as shown below. I have checked my data, but I didn't find any 'NA' or empty cells. When I used step() or stepAIC to select significant predictor variables, <none>s appear to places where

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA256 with my gradient fixes in I thought it could do with a release, since there was a bunch of other changes. Aaron Plattner (1): Use the right screen from $DISPLAY Chris Wilson (13): repeat: Specify test width/height rather than relying on win_width/height blend: Combine multiple tests into a single XGetImage request

Dear list, I made a logistic regression model (MyModel) using lrm and penalization by pentrace for data of 104 patients, which consists of 5 explanatory variables and one binary outcome (poor/good). Then, I found bootcov and robcov function in rms package for calculation of confidence range of coefficients and odds ratio by bootstrap covariance matrix and Huber-White sandwich method,

Hello all, I'm having trouble creating an adjacency matrix. Basically, I need to turn the following distance matrix into an adjacency matrix based on whether values are >1.5 or not. If they are >1.5, then the returned value should be 0. If they are =<1.5, then the returned value should be 1. DistanceMatrix: A B C D E [1,]