search for: 1.46

In checking over the solutions to some homework that I had assigned I observed the fact that in R (version 2.4.0) pnorm(-1.46) gives 0.07214504. The tables in the text book that I am using for the course give the probability as 0.0722. Fascinated, I scanned through 5 or 6 other text books (amongst the dozens of freebies from publishers that lurk on my shelf) and found that some agree with R

I'm pleased to announce that the ChemoSpec package is available on CRAN for the first time (as version 1.46-4). ChemoSpec is a collection of functions for plotting spectra (NMR, IR etc) and carrying out various forms of top-down exploratory data analysis, such as HCA, PCA and model-based clustering. The design permits comparison of data from samples which fall into groups such as

I'm pleased to announce that the ChemoSpec package is available on CRAN for the first time (as version 1.46-4). ChemoSpec is a collection of functions for plotting spectra (NMR, IR etc) and carrying out various forms of top-down exploratory data analysis, such as HCA, PCA and model-based clustering. The design permits comparison of data from samples which fall into groups such as

Hi, I've a list of list. I want to extract an element by the rownames. I can extract it by: data[[1]][[1]][[4]][1] But I want to exctract it by a command like this: data[[1]][["B0"]][["smac"]][["cont"]][1] It's possible? Thanks, Alfredo > str(data) List of 1 $ :List of 4 ..$ :List of 4 .. ..$ : num [1, 1:3] 0.4 0.458 0.5 .. ..$ : num

Is there an alternative to using link(2) to rename files in sftp-server? Some users use sftp to upload files to a vfat partition on an sftp-server, and then renaming doesn't work. This breaks konqueror, for example (from KDE, which u), which upload files first with a ".part" extension and then renames them removing this extension.

Hello, is there already a function in any R package which does source code formatting of deparsed lists? Let's create the following list: x <- list(a = round(rnorm(3), 2), b = round(rnorm(3), 2)) xx <-c(aa = round(rnorm(30)), f = function(a) a + b, list(x, x)) Now, I want deparse it in a way that yields something like: list( aa = c(0.25, 0.18, 0.84, -1.25, 0.09,

Hi. I'm trying to plot two ecdf's on the same graph using two different colors. I can plot using the same color, but it doesn't work when I change colors? Any suggestions? Thanks in advance for your help. x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46) y <- c(1.15, 0.88, 0.90, 0.74, 1.21) plot(ecdf(x)) # it works without col='blue', but doesn't

--------------------------------------------------------------------- Red Hat, Inc. Red Hat Security Advisory Synopsis: Printing exposes system files to reading. Advisory ID: RHSA-2001:112-07 Issue date: 2001-09-24 Updated on: 2001-10-25 Product: Red Hat Linux Keywords: Ghostscript lpr LPRng printing Cross references: Obsoletes:

Hi. I need to draw a circle whit center (a,b) and radio r. So I use the R code below a<-1.975 # valore x del centro b<-1.215 # valores y del centro r<-1.46 # radio x1<-seq(a-r,a+r,by=0.01); #los valores de x yp<-sqrt(r^2-(x1-a)^2)+b; # los valores y a partir de la ra??z positiva yn<-(-1)*sqrt(r^2-(x1-a)^2)+b; # los valores y a partir de la ra??z negativa x<-c(x1,x1);

Hi all! I've got a problem with thia PA168S/AT320P telephone. I got 2 servers: one with SER and the other with Asterisk. All users are on SER and Asterisk is the gateway/voicemail. In these days I'm starting some tests using Asterisk accounts users. With this PA168S/AT320P, if I use it with a user from SER, it's ok but I can forget to use it with Asterisk users!!! I've also updated

Markus, ignore the other stuff I sent.. I need to go back to bed and stop trying to code.. <sigh> For everone else.. Will this make everyone happy? This does the follow. it will always honor AllowUsers. If there is no Allow/DenyGroups it stated they are not in allowUsers. IF there are AllowDenyGroups it tries them. And then stated they are not in either AllowUsers nor AllowGroups

Hi all, I would like to predict some values for an nls regression function (functional response model Rogers type II). This is an asymptotic function of which I would like to predict the asymptotic value I estimated the paramters with nls, but can't seem to get predictions for values of m choice...... This is my script: RogersII_N <-

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

I got curious how the lld produced gnu hash tables compared to gold. To test that I timed "perf record ninja check-llvm" (just the lit run) in a BUILD_SHARED_LIBS build. The performance was almost identical, so I decided to try sysv versus gnu (both produced by lld). The results are interesting: % grep -v '^#' perf-gnu/perf.report-by-dso-sym | head 38.77% ld-2.24.so

aa <- (structure(list(X.0.85 = c(-1.02, -1.17, -1.29, -1.39, -1.46, -1.5, -1.52, -1.5, -1.46, -1.39, -1.3, -1.19, -1.07, -0.93, -0.79, -0.65, -0.5, -0.36, -0.22, -0.08, 0.05, 0.18, 0.3, 0.41, 0.52, 0.62, 0.72, 0.81, 0.89, 0.98, 1.05, 1.13, 1.19, 1.25, 1.29, 1.31, 1.31, 1.29, 1.24, 1.16, 1.06, 0.93, 0.77, 0.58, 0.38, 0.16, -0.07, -0.31, -0.89, -1.05, -1.19, -1.31, -1.41, -1.47, -1.51, -1.51,

I'm trying to write a function to find the means over factors of the responses in a mlm (something I would do easily in SAS with PROC SUMMARY). The not-working stub of a function to do what I want is below, and my problem is that I don't know how to call aggregate (or some other function) in the context of terms in a linear model extracted from a lm/mlm object. means.mlm <-

Short: get rid of the loops I use and optimize runtime Dear all, I want to calculate for each row the amount of the month ago. I use a matrix with 2100 rows and 22 colums (which is still a very small matrix. nrows of other matrixes can easily be more then 100000) Table before Year month quarter yearmonth Service ... Amount 2009 9 Q3 092009 A ...

The large percentages are from those tiny benchmarks. If you look at omnetpp (0.52%), and xalanc (1.46%), the increase is small. To get a better average increase, you can sum up total debug_line size before and after and compute percentage accordingly. David On Thu, Oct 27, 2016 at 1:11 PM, Dehao Chen <dehao at google.com> wrote: > The impact to debug_line is actually not small. I only

Sorry for the lack of reproducible data, but this seems to be a problem inherent to my dataset and I can't figure out where the issue is. I have several data frames set up as a time series with identical POSIXct date formats. If I keep the original data in data frame format and merge them using base merge- everything is perfect and everyone is happy. If I transform the data frames to zoo

Dear R-users, I am in the process of creating new custom functions and am quite puzzled by some discrepancies in execution time when I run some R scripts that call those new functions. So here is the situation: - let's assume I have created two custom functions, called myg and myf; - myg is mostly a plotting function, which makes a heavy use of grid and lattice functions; - myf is a function