search for: 1.456

Good morning, I am a new R user and I am trying to learn how to use it. I am trying to solve this problem. I have a dataframe df of daily securities (for a year) earnings as follows: SEC_ID DAY EARNING IT0000001 20070101 5.467 IT0000001 20070102 5.456 IT0000001 20070103 4.954 IT0000001 20070104 3.456 .......................... IT0000002 20070101 1.456 IT0000002 20070102 1.345

Hi all: Can someone advice me on how to hold the residuals Mean sq value on a string so it can be used in other calculations. I was trying something like this: Msquare<-dfr$Mean sq but fails..Thanks dfr <- read.table(textConnection("percentQ Efficiency 1.565 0.0125 1.94 0.0213 0.876 0.003736 1.027 0.006 1.536 0.0148 1.536 0.0162 2.607 0.02 1.456 0.0157 2.16 0.0103

Hello ! I am attempting to switch from being a long time SAS user to R, and would really appreciate a bit of help ! The first thing I do in getting a large dataset (thousands of obervations and hundreds of variables) is to run a SAS command PROC CONTENTS VARNUM command - this provides me a table with the name of each variable, its type and length; then I run a PROC MEANS - for numerical

Hello R community, I have a question regarding correlation and regression analysis. I have two variables, x and y. Both have a standard deviation of 1; thus, correlation and slope from the linear regression (which also must have an intercept of zero) are equal. I want to probe two particular questions: 1) Is the slope significantly different from zero? This should be easy with the lm

hello list, I am attempting to sync two imap servers using the imapsync perl script. It seems handy and easy. Here's what happens when I try to do this: # # Postfix master process configuration file. For details on the format # of the file, see the master(5) manual page (command: "man 5 master"). # -o smtpd_sasl_auth_enable=yes # -o

Hi all, I''m using ferret and acts_as_ferret on Win XP. Trying to index a location table with over 2,5 Mio. rows in UTF-8 I''m getting the error: "IO Error: IO Error occured: Error reading the segment infos. Store listing was ..." The error occurs after some hours of running. The index file system looks like this after the abort: 11.08.2007 12:30 <DIR>

Hi all: I have always used SPSS to estimate weekly covariance based on a linear regression model but have to hard code the model Std. Error and the Mean-Square and then execute one week a the time. I was wondering if someone could give me an idea on how to estimate weekly(WK) covariance using the summary and anova of "dfr"(lineal model below). I have to do this for 52

Hello, I am starting to use R for various analyses, for example I use the ca package to do Correspondence Analysis. I am also looking to use packages such as: pls Partial Least Squares plspm Partial Least Squares Path Modelling However, although I can use packages such as these on un-weighted data there does not appear to be a facility to take account of weighted data. I am a

Dear all, I have the following question. Is it possible in R to call for the p-value directly in a model like this a <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) b <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) summary(lm(a~(b+0))) or even in this a <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) b <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)

Hi, having used both the gee pacakge and the geepack package, i am unsure of how to interpret the results. Here are the results from the geeglm function from the geepack package > gee2<-geeglm(data$erythema~data$product, data = data, id=subject, > family=binomial, corstr="independence") Warning message: In model.response(mf, "numeric") : using

Hi R user, I am a kind of an intermediate user of R. Now I am using GLM model (library MASS, VEGUS). I used a backward stepwise logistic regression, but i got a problem in removing those predictors which are above 0.05. I don't want to include those variables which were above 0.05 in final backward stepwise logetsic regression model. for example: first I run the model,

I want to take the first row of each unique ID value from a data frame. For instance > ddTable <- data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry")) I want a dataset that is Id Name 1 Paul 2 Bob > unique(ddTable) Will give me all 4 rows, and > unique(ddTable$Id) Will give me c(1,2), but not accompanied by the name column.

Hi Louis, It's simple to run a r script from the excel spreadsheet. Just write your code, source("C:\\Quantil Aplicativos\\Genercauca\\BackwardSelectionNC.r"), into a cell of a workingsheet. Then right-click the cell and select "run code" in the pop-up menu. Hope this will help you. Best, Bernard -----????----- ???: r-help-bounces at r-project.org [mailto:r-help-bounces