Displaying 10 results from an estimated 10 matches for "1.398".
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1.39
2020 Feb 17
2
Use of "no-touch-required" with "cert-authority"
Hello,
In testing security key support in OpenSSH 8.2, I had some trouble making the ?no-touch-required? option in the authorized_keys file work in conjunction with OpenSSH certificates. I think I?ve figured it out, but I think there may be a bug in ssh-keygen related to this.
To make ?no-touch-required? work with certificates, I actually had to do three things:
Generate the security key with
2011 May 31
2
Forcing a negative slope in linear regression?
Dear forum members,
How can I force a negative slope in a linear regression even though the
slope might be positive?
I will need it for the purpose of determining the trend due reasons other
than biological because the biological (genetic) trend is not positive for
these data.
Thanks. Julia
Example of the data:
[1] 1.254 1.235 1.261 0.952 1.202 1.152 0.801 0.424 0.330 0.251 0.229
2010 Feb 04
2
help needed using t.test with factors
I am trying to use t.test on the following data:
date type INTERVAL nCASES MTF SDF MTO SDO
nFST MF nOBS MO MB BIASCV BIASEV ME MAE
RMSE CRCF
2001-06-15 avn GE1.00 4385 0.246 0.300 1.502
0.556 1367 1.373 4385 1.502 1.471 0.285 0.164
-1.256 1.266 1.399 0.056
2001-06-15 avn
2014 Feb 03
1
ssh config Host case insensitive
Hi,
There seems to be an issue where a case sensitive Host entry is no
longer working after update to openssh 6.5
example entry: (was working before update)
Host MyHost
Hostname 192.168.0.1
Port 1234
User root
IdentityFile ~/.ssh/id_rsa
When issuing "ssh MyHost" the outcome is now:
ssh: Could not resolve hostname myhost: Name or service not known
When the above entry is changed
2014 Mar 31
1
Version string
6.2p2 prints the same version string in the debugging output as it does
when invoked with -V:
% ssh -V
OpenSSH_6.2p2, OpenSSL 0.9.8y 5 Feb 2013
% ssh -v nonesuch |& head -1
OpenSSH_6.2p2, OpenSSL 0.9.8y 5 Feb 2013
6.3p1 and newer don't - I don't have anything at hand that runs 6.3p1,
but here are 6.[456]p1:
% ssh -V
OpenSSH_6.4p1, OpenSSL 1.0.1e-freebsd 11 Feb 2013
% ssh -v
2011 Sep 02
1
Parameters in Gamma Frailty model
Dear all,
I'm new to frailty model. I have a question on the output from 'survival'
pack. Below is the output. What does gamma1,2,3 refer to? How do I
calculate joint hazard function or marginal hazard function using info
below? Many thanks!
Call:
coxph(formula = surv ~ as.factor(tibia) + frailty(as.factor(bdcat)),
data = try)
n=877 (1 observation deleted due to missingness)
2009 Aug 01
2
Cox ridge regression
Hello,
I have questions regarding penalized Cox regression using survival
package (functions coxph() and ridge()). I am using R 2.8.0 on Ubuntu
Linux and survival package version 2.35-4.
Question 1. Consider the following example from help(ridge):
> fit1 <- coxph(Surv(futime, fustat) ~ rx + ridge(age, ecog.ps, theta=1), ovarian)
As I understand, this builds a model in which `rx' is
2009 Dec 18
1
linear contrasts for trends in an anova
Hi everybody,
I'm trying to construct contrasts for an ANOVA to determine if there is a significant trend in the means of my groups.
In the following example, based on the type of 2x3 ANOVA I'm trying to perform, does the linear polynomial contrast generated by contr.poly allow me to test for a linear trend across groups?
doi=data.frame(
Group=c(
rep(1, 5), rep(2, 5), rep(3, 5),
2012 Dec 07
1
Help with manipulation of matrix object
Hi list,
I have a problem which I was stuck on for a while, and after many days
still cannot find a solution to.
I have a matrix, measuring m X n. An example matrix will be this:
>dput(sample)
structure(c(2315101, 2315102, 2315103, 2315104, 2315105, 2315107,
2315108, 2315110, 2315112, 2315114, 2315116, 2315118, 2315120,
2315122, 2315124, 2315126, 2315127, 2315128, 2315130, 2315131,
2315132,
2014 Sep 01
1
Correlation Matrix with a Covariate
R Help -
I'm trying to run a correlation matrix with a covariate of "age" and will
at some point will also want to covary other variables concurrently.
I'm using the "psych" package and have tried other methods such as writing
a loop to extract semi-partial correlations, but it does not seem to be
working. How can I accomplish this?
library(psych)
> set.cor(y =