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Hello, I am trying to filter a data set like below so that the peaks in the Phase value are more obvious and can be identified by a peak finding function following the useful advise of Carl Witthoft. I have written the following for(i in length(data$Phase)){ newphase=if(abs(data$Phase[i+1]-data$Phase[i])>6){ data$Phase[i+1] }else{data$Phase[i] } } I get the following error which I have not

Hi i would like to use some graphs or tables to explore the data and make some sensible guesses of what to expect to see in a glm model to assess if toxin concentration and sex have a relationship with the kill rate of rats. But i cant seem to work it out as i have two predictor variables~help?Thanks.:) Here's my data. >

>>>>> Winston Chang <winstonchang1 at gmail.com> >>>>> on Fri, 23 Jan 2015 10:15:53 -0600 writes: > I think you can simplify a little by replacing this: > pkg %in% loadedNamespaces() > with this: > .getNamespace(pkg) almost: It would be !is.null(.getNamespace(pkg)) > Whereas getNamespace(pkg) will load the

Hello, I need some help on a regression I am running please. I am running a multiple regression in R and I am getting weird outputs and would like your help in resolving it. This is the code I run: Reg = lm (Final$Y.t.-Final$Y.t.1. ~ Final$ Y.t.1. + Final$Cor + Final$Gov+ Final$Inv+ Final$TrOp + Final$Pop+ Final$Sch , data = Final) summary(Reg) And the output I get is pasted below. As

>>>>> Michael Lawrence <lawrence.michael at gene.com> >>>>> on Mon, 26 Jan 2015 05:12:55 -0800 writes: > A isNamespaceLoaded() function would be a useful thing to > have in general if we are interested in readable code. An > efficient implementation would be just a bonus. Good point (readability), and thank you for the support! Note

Hi Rabby, Before you run your regression, try this: is.factor(Final$Cor) If this returns TRUE, then this variable is a factor and it will be treated as a number of levels rather than a set of numeric values. This usually happens when a text file is read in and there is at least one value that cannot be converted to numeric. So if you are doing something like this:

A isNamespaceLoaded() function would be a useful thing to have in general if we are interested in readable code. An efficient implementation would be just a bonus. On Mon, Jan 26, 2015 at 3:36 AM, Martin Maechler <maechler at lynne.stat.math.ethz.ch> wrote: >>>>>> Winston Chang <winstonchang1 at gmail.com> >>>>>> on Fri, 23 Jan 2015 10:15:53

isLoadedNamespace() sounds fine to me.. Thanks for addressing this, Michael On Mon, Jan 26, 2015 at 5:51 AM, Martin Maechler < maechler at lynne.stat.math.ethz.ch> wrote: > >>>>> Michael Lawrence <lawrence.michael at gene.com> > >>>>> on Mon, 26 Jan 2015 05:12:55 -0800 writes: > > > A isNamespaceLoaded() function would be a useful

Hi, I'm trying to get the p-value from the 'lm' regression function as a list object. For example, I can get r^2 from the following code by entering summary(fm)$r.squared. Is there a way to get the p-value? If not, is there a function where I can enter the f-value and degrees of freedom to get the p-value? Thanks. x <- c(1,2,3,4,5,6,7,8,9,10) y <- c(1,2,3,4,4,5,6,8,1,9) fm

Hello, Thank you to all those great folks that have helped me in the past (especially Dennis Murphy). I have a new challenge. I often generate time-series data sets that look like the one below, with a variable ("Phase") which has a series of flat-topped peaks (sample data below with 5 "peaks"). I would like to calculate the phase value for each peak. It would be great to

Hi all, Profiling turned up a bit of a speedbump in the library function. I submitted a patch to the R bug tracker as bug 16168 and I've also included it below. The alternate code is simpler and easier to read/maintain, I believe. Any thoughts on other ways to write this? Index: src/library/base/R/library.R =================================================================== ---

Hello all! I have a problem to arrange data in another form. My initial data is like this: 'data.frame': 421 obs. of 58 variables: $ 01A: num NA NA NA NA NA NA NA NA NA NA ... $ 01B: num NA NA NA NA NA NA NA NA NA NA ... $ 03A: num NA NA NA NA NA NA NA NA NA NA ... $ 03B: num NA NA NA NA NA NA NA NA NA NA ... $ 05A: num NA NA NA NA NA NA NA NA NA NA ... $ 05B: num NA NA NA NA