search for: 02172300

...414312.49534",..: 2 >3 4 5 6 7 8 9 10 11 ... > $ 02169570,,:'data.frame': 17 obs. of 1 variable: > ..$ CYEAR_Decimal.load_00600_W.load_00600_F: Factor w/ 17 levels >",,","2000.875,2897.79043403356,5155.6776796",..: 2 3 4 5 6 7 8 9 10 11 ... > $ 02172300,,:'data.frame': 12 obs. of 1 variable: > ..$ CYEAR_Decimal.load_00600_W.load_00600_F: Factor w/ 12 levels "2001.875,,899.46439731",..: 1 2 3 >4 5 6 7 8 9 10 ... > > >I actually found the dataset containing Bostoncitydata, etc.. I will work on that. > >...

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

Hi all, I have a couple of questions. 1) Is there a more effective way to remove the following pattern (patternrm) from the station_id_Timeseries (see below) patternrm <- c(_2000_4_OND, _2001_1_JFM, _2001_2_AMJ, _2001_3_JAS, _2001_4_OND, _2002_1_JFM, _2002_2_AMJ, _2002_3_JAS, _2002_4_OND, _2003_1_JFM, _2003_2_AMJ, _2003_3_JAS, _2003_4_OND, _2004_1_JFM, _2004_2_AMJ, _2004_3_JAS, _2000_4_OND) #