search for: 0.83

CentOS Errata and Bugfix Advisory 2011:1007 Upstream details at : https://rhn.redhat.com/errata/RHBA-2011-1007.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) x86_64: fb86795bd28ea3adb5c2a8319819bd82 samba3x-3.5.4-0.83.el5.x86_64.rpm ab308cb8053a8cf590229d03347da918 samba3x-client-3.5.4-0.83.el5.x86_64.rpm

CentOS Errata and Security Advisory 2011:1220 Moderate Upstream details at : https://rhn.redhat.com/errata/RHSA-2011-1220.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) x86_64: d1af26928e5b3437ed117f2ffbef2cb3 samba3x-3.5.4-0.83.el5_7.2.x86_64.rpm 0277d8f285c5006f57ae9f3a50ceb8fc samba3x-client-3.5.4-0.83.el5_7.2.x86_64.rpm

Peter, There was a mis-merge in the ia64 patch you put into 0.83. Olaf Hering pointed it out. The patch is attached. Olaf claims that he is still unable to compile for ia64 with is toolchain. He's getting the following error: <olh> libc.so(.got+0x0): multiple definition of `_GLOBAL_OFFSET_TABLE_' <olh> tests/getenvtest.o(.got.plt+0x0): first defined here <olh>

CentOS Errata and Bugfix Advisory 2011:1007 Upstream details at : https://rhn.redhat.com/errata/RHBA-2011-1007.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) i386: 0b924fc207821b327e4a48e40015c866 samba3x-3.5.4-0.83.el5.i386.rpm 72312ee2509accb48b5ae361297e8943 samba3x-client-3.5.4-0.83.el5.i386.rpm

CentOS Errata and Security Advisory 2011:1220 Moderate Upstream details at : https://rhn.redhat.com/errata/RHSA-2011-1220.html The following updated files have been uploaded and are currently syncing to the mirrors: ( md5sum Filename ) i386: 155e4c1fd8f4165e83e602cee07f3e68 samba3x-3.5.4-0.83.el5_7.2.i386.rpm cdaf234215185ad93ae0c773edb625e2 samba3x-client-3.5.4-0.83.el5_7.2.i386.rpm

Folks, I have a 'matching' matrix between variables A, X, L, O: > a <- structure(c(1, 0.41, 0.58, 0.75, 0.41, 1, 0.6, 0.86, 0.58, 0.6, 1, 0.83, 0.75, 0.86, 0.83, 1), .Dim = c(4L, 4L), .Dimnames = list( c("A", "X", "L", "O"), c("A", "X", "L", "O"))) > a A X L O A 1.00 0.41

t<--4:4 y<-c(5,7,10,13,15,16,14,12,11) plot(t,y,type="l") how can i add a curve y=0.83*t-0.44*t^2 in the graph? [[alternative HTML version deleted]]

I have 2 zoo objects - 1) Interest rate spread between 10-YR-US-Treasury and 2-YR-US-Treasury (object name = sprd) 2) S&P 500 index (object name = spy) > str(spy) ?zoo? series from 1976-06-01 to 2011-03-31 Data: num [1:8791] 99.8 100.2 100.1 99.2 98.6 ... Index: Class 'Date' num [1:8791] 2343 2344 2345 2346 2349 ... > str(sprd) ?zoo? series from 1976-06-01 to 2011-03-31

Dear all Is there an easy way to display only one half (top-right or bottom-left) of a correlation matrix? > require(Hmisc) > rcorr(as.matrix(mtcars[ , 1:4])) mpg cyl disp hp mpg 1.00 -0.85 -0.85 -0.78 cyl -0.85 1.00 0.90 0.83 disp -0.85 0.90 1.00 0.79 hp -0.78 0.83 0.79 1.00 n= 32 P mpg cyl disp hp mpg 0 0 0 cyl 0 0 0 disp 0 0

Hello, I am trying to plot a curve over points plotted with se's in xYplot (see example below). I can get Figure 1 below to plot the data with error. However, I keep getting a the error message "Error using packet 1 object "y" not found" Can anyone see what I am doing wrong? Thanks! John ------------------------------- a=0.002; b=31.7; c=0.51

Dear r-helpers, why do I get an output in the first iteration of the for-loop which contains the string values of the input vector, and how can I avoid that? Here's the output (only line 1 is wrong) latentVariable Indiv Group 1 rPlanning rIterat rTDD 2 rPlanning 0.79 0.84 3 rIterat 0.79 0.83 4 rTDD 0.9 0.96 5 rStandup 0.83 0.82 6

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Well, I think this is not the only time you guys ever seen that kind of mails. First of all, I did checked all that is to be checked before writing to list. wbinfo -u and wbinfo -g work flawless. Also wbinfo -a, so I can authenticate without problems. The setup is a normal trust setup where domain X (my domain) trusts domain Y (another company).

I've a matrix like this: 1985 1.38 1.27 1.84 2.10 0.59 3.47 1986 1.05 1.13 1.21 1.54 0.21 2.14 1987 1.33 1.21 1.77 1.44 0.27 2.85 1988 1.86 1.06 2.33 2.14 0.55 1.40 1989 2.10 0.65 2.74 2.43 1.19 1.45 1990 1.55 0.00 1.59 1.94 0.99 2.14 1991 0.92

R 2.15.1 OS X (MLion) Colleagues, I am aware that changes in mfrow / mfcol in par() affect cex (from help: In a layout with exactly two rows and columns the base value of ?"cex"? is reduced by a factor of 0.83: if there are three or more of either rows or columns, the reduction factor is 0.66). I generate a multipage PDF in which mfrow varies such that cex is impacted. This affect

Hi. I'm trying to plot two ecdf's on the same graph using two different colors. I can plot using the same color, but it doesn't work when I change colors? Any suggestions? Thanks in advance for your help. x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46) y <- c(1.15, 0.88, 0.90, 0.74, 1.21) plot(ecdf(x)) # it works without col='blue', but doesn't

When printing a table it is broken at some point (depending how long are the associated names) >>> see example below. Is there a way to control number of columns being printed for a given chunk of the table? Best regards, Ryszard > z5 AAAAAAA BBBBBBB CCCCCCC DDDDDDD EEEEEEE FFFFFFF GGGGGGG HHHHHHH IIIIIII AAAAAAA 1.00 -0.69 -0.54 -0.88 NA NA NA

Dear all ?Hmisc::rcorr states that it takes as main argument "a numeric matrix". But is it normal that it fails in such an ugly way on a data frame? (See below.) If the function didn't attempt any conversion to a matrix, I would have expected it to state that in the error message that it didn't accept 'data.frame' objects in its input. Also, I vaguely remember having used

I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

Hello, I have what should be an easy question. I'm a new r user and making the transition from menus to the command line so as to do batch processing of tons of data. One of my data streams needs to be detrended. It's a vector of numbers that follows a negative exponential decay. I need to fit a curve to it and use the residuals as an object. The data looks something like this: foo.dat