search for: 0.66

Hi, list- ?? I've got a large list of multi-column data and I'd like to filter it according to a threshold, such as, "show me the values that are above 0.4 for each line." For instance, if the line of data were: > line v1 v2 v3 v4 v5 v6 v7 v8 v9 1 -0.32 0.66 -0.35 -0.82 0.38 0.66 -0.02 -0.11 -0.64 I can do this > line[,line >= 0.4]

I've been attempting to export a graphics file of my lattice plots and no matter what color I use for the bg= argument in the bmp/jpeg/png function, the background is grey. bmp(filename = "c:/my_paper/resids.bmp", width=1024, height=1024, pointsize=10, bg="transparent") # these are lattice plots. plot them in a 3x2 matrix print( hgqqplot, position=c(0.0, 0.66, 0.5, 1.0 ),

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

Dear Rhelp, I would like to get alternate tick labels for the xyplot: library(lattice) library(grid) xy <-xyplot(decrease ~ treatment, OrchardSprays, ??? main= "Some plot", ??????? groups = rowpos, type = "a", ??? ??????????? page???? = function(n){ ???????????????????????? grid.text(LETTERS[j], ???????????????????????? y = 0.95, ???????????????????????? x = 0.15,

Hello, all, We're now starting to cover hypothesis tests in my Stats 101 course. As usual in courses using the Lock5 textbook, 3rd ed., the homework answers are calculated using their StatKey application. In addition (and for no extra credit), I'm trying to solve the problems using R. In the case of hypothesis test, in addition to manually setting up randomized null hypothesis

Hi again R People: I have the following time series: >x.ts Jan Feb Mar Apr May Jun Jul Aug Sep 2000 0.95 0.66 0.83 0.66 -1.45 -1.25 0.33 1.03 -0.48 2001 2.55 1.21 -1.10 -0.63 0.01 -2.20 -0.51 1.12 1.11 2002 -1.37 0.55 -0.63 -0.56 0.92 -1.73 0.59 0.77 0.30 2003 0.55 -0.01 -0.54 2.27 -1.29 -0.23 0.09 -0.50 -0.61 Oct Nov Dec 2000 0.84 -1.35

Hi all, I have this problem with lattice that xyplot() won't draw some of my axis labels if the type (i.e. the relation argument) of scales is set as free. For example, in the plot below, I would want it to also show: 1. the labels E1,...E6 below the 10th panel (i.e. 3rd row, 2 col)....just as it is now done below the 12th panel.... 2. as well as the labels (2,4,6,8) on the top of panels 1

Hello! I am getting the following errors when running optim() [I tried optim() with 3 different methods as you can see]: Error in optim(c(0.66, 0.999, 0.064), pe, NULL, method = "L-BFGS-B") : objective function in optim evaluates to length 6 not 1 > out <- optim( c(0.66, 0.999, 0.064), pe, NULL, method = "Nelder-Mead") Error in optim(c(0.66, 0.999, 0.064),

Hi, Rui and Michael, thank you both for replying. Yeah, I'm not supposed to know about Chi-squared yet. So far, all of our work with hypothesis tests has involved creating the sample data, then resampling it to create a null distribution, and finally computing p-values. The prop.test() would work. obviously. I'll look into that. I didn't know about it. I'm really struck by the

How about calculating a 95% confidence interval about the estimated proportion in favor. The PooledInfRate package will do this for you. If confidence intervals overlap then there is no significant difference. -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of Kevin Zembower via R-help Sent: Saturday, March 29, 2025 12:10 PM To: R-help email list

Hello, trying to get something like this to work and am failing: pie( c(length(strongN14),length(weakN14),length(weakN15),length(strongN15),length(ambiguous)), labels = c(>= 0.66, >= 0.33, <= -0.33, <= -0.66), col = c("#9999FF","#0000CC","#009900","lightgreen","white") ) Can't figure out a way to display the 'greater or

Dear R-List, I am sure there must be a very simple way to do this - I just do not know how... This is what I want to do: #my dataframe df<-data.frame(id=c("x01","x02","x03","x04","x05","x06"),a=c(1,2,NA,4,5,6),b=c(2,4,6,8,10,NA),c=c(NA,3,9,12,NA,NA),sum=c(3,9,15,24,15,6))    id    a     b     c   sum 1 x01  1     2    NA   3 2

Thanks a lot to Demitris for a prompt answer some minutes ago on another tread (see below). To avoid excess mails on the list, I move onto next question: I have another small plotting problem that confuses me. I want to plot results from a field trial series, using the numbers of the trials as symbols in the plot. pch = as.character(trial_no) works fine, but truncates the trial number to the

Hello, I have three datasets StartSignals, MainData, StopSignals and need to compound the data for each variable in MainData over dates that fall between the Start and Stop signals. (Stop signals are common and the same to all X1:X5 variables). Please see sample below: The one way I was thinking of doing this project was to setup a nested "FOR" loop and go through the three data

hello, i'm pete ,how can i order rows of matrix by max to min value? I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K are clusters. I need first and second largest elements of the i-th row. for example 1 0.66 0.04 0.01 0.30 2 0.02 0.89 0.09 0.00 3 0.06 0.92 0.01 0.01 4 0.07 0.71 0.21 0.01 5 0.10 0.85 0.04 0.01 6 0.91 0.04 0.02 0.02 7 0.00 0.01 0.98 0.00 8 0.02

Dear all, Please suggest me how can I do it. I have a matrix which look like following: x1 x2 x3 t1 .01 0.3 0 t2 0 0.1 0.01 t3 0 .01 .01 t4 0 0 t5 5 0 0 t6 0 0 0 t7 0 0 0 t8 0 0 0 t9 0.6 0 0 t10 0 0 0.66 t11 0 0.6 0.11 t12 0 0.4 0 I want to sort decreasing order in each column based on rows. and then to display only those rows which has a value. The expected out put matrix will

Hi 2 all ! I have problems with concurrent filesystem actions on a ocfs2 filesystem which is mounted by 2 nodes. OS=RH5ES and OCFS2=1.2.6 F.e.: If I have a LV called testlv which is mounted on /mnt on both servers and I do a "dd if=/dev/zero of=/mnt/test.a bs=1024 count=1000000" on server 1 and do at the same time a du -hs /mnt/test.a it takes about 5 seconds for du -hs to execute: 270M

R 2.15.1 OS X (MLion) Colleagues, I am aware that changes in mfrow / mfcol in par() affect cex (from help: In a layout with exactly two rows and columns the base value of ?"cex"? is reduced by a factor of 0.83: if there are three or more of either rows or columns, the reduction factor is 0.66). I generate a multipage PDF in which mfrow varies such that cex is impacted. This affect

Dear Friends I have a technical question about conducting 2 way repeated measures ANOVA analysis using R. 1. Data set: repeated measurement of activity over night (2 hr. intervals) repeated (within subject)factor: Hours Between subject: Species, Sex Dependent variables: specimens Here is how the data arranged for the analysis: Subject Replicate Hour Sp. Specimens 1 1 1 a 2 1 1 a

Hi guys, Suppose I have 2 data frames ie: values one 0.32 two 0.25 three 0.11 and values two 0.66 one 0.74 three 0.19 nb the first column is the row names in both cases How can I combine them on the row names column? Ie to make something like values.1 values.2 one 0.32 0.74 two 0.25 0.66 three 0.11 0.19 I guess its