search for: 0.55

Folks, The contour() function wants x and y to be in increasing order. I have a situation where I have a grid in x and y, and associated z values, which looks like this: x y z [1,] 0.00 20 1.000 [2,] 0.00 30 1.000 [3,] 0.00 40 1.000 [4,] 0.00 50 1.000 [5,] 0.00 60 1.000 [6,] 0.00 70 1.000 [7,] 0.00 80 0.000 [8,] 0.00 90

CentOS Errata and Security Advisory CESA-2010:0499 seamonkey security update for CentOS 3 x86_64: https://rhn.redhat.com/errata/RHSA-2010-0499.html The following updated file has been uploaded and is currently syncing to the mirrors: x86_64: updates/x86_64/RPMS/seamonkey-1.0.9-0.55.el3.centos3.i386.rpm updates/x86_64/RPMS/seamonkey-1.0.9-0.55.el3.centos3.x86_64.rpm

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

Folks, A few days ago, I had asked a question on this mailing list about making a contour plot where a function z(x,y) is evaluated on a grid of (x,y) points, and the data structure at hand is a simple table of (x,y,z) points. As usual, R has wonderful resources (and subtle complexity) in doing this, and the gurus of the list showed me the way. Here's a complete working example. One might

Dear list I'm testing a predictor and I produced nice performance plots with ROCR package utilizing the 3 standard command pred <- prediction(predictions, labels) perf <- performance(pred, measure = "tpr", x.measure = "fpr") plot(perf, col=rainbow(10)) The pred object and the perfo object are S4 with the following slots An object of class "performance"

CentOS Errata and Security Advisory CESA-2010:0499 seamonkey security update for CentOS 3 i386: https://rhn.redhat.com/errata/RHSA-2010-0499.html The following updated file has been uploaded and is currently syncing to the mirrors: i386: updates/i386/RPMS/seamonkey-1.0.9-0.55.el3.centos3.i386.rpm updates/i386/RPMS/seamonkey-chat-1.0.9-0.55.el3.centos3.i386.rpm

Hi, Round(0.55,1)=0.5 Round(2.55,1)=2.6 Can this be right? Thanks, Ed [[alternative HTML version deleted]]

Hello! I'm a college undergrad desperately trying to finish up my thesis. I have a dataset on the distribution of a grassland bird from the Breeding Bird Survey. I have a very straightforward and simple version of the logistic growth model to describe changes in this bird's abundance over time. The variables are the natural birth rate, mortality, and carrying capacity. The equation itself

Hi All- This seems like such a pathetic problem to be posting about, but I have no idea why this testcase does not work. I have tried this using R 2.4.1, 2.4.0, 2.3.0, and 2.0.0 on several different computers (Mac OS 10.4.8, Windows XP, Linux). Below the signature, you will find my test case R code. My point in this folly is to take a dataframe of 300,000 rows, create a filter based on two

Hi, I'm trying to make multiple plots in a same graph window in R. The multiple graphs are showing up in the right positions on the window, but I'm having the problem that the graphic window is being refreshed every time a new plot is drawn, so that I end up with only the last graph coming up; the previous ones are all erased If I try to print in a .eps file directly, then I end up

> (FICB[,"temp"]) [1] "0.30" "0.55" "0.45" "2.30" "0.45" "0.30" "0.25" "0.30" "0.30" "1.05" "1.00" "1.00" [13] "0.30" "0.30" "0.30" "0.55" "0.30" "0.30" "0.30" "0.25" "1.00"

> as.character(seq(-.25,.95,.1)) [1] "-0.25" "-0.15" "-0.05" "0.05" "0.15" "0.25" "0.35" "0.45" "0.55" "0.65" "0.75" "0.85" "0.95" > as.character(seq(-.35,.95,.1)) [1] "-0.35" "-0.25"

Dear expeRts, I would simplify following code. --------------------------------------------- youtput <- function(x1, x2){ n <- length(x1) y <- vector(mode="numeric", length=n) for(i in 1:n){ if(x1[i] >=5 & x1[i] <= 10 & x2[i] >=5 & x2[i] <=10) y[i] <- 0.631 * x1[i]^0.55 * x2[i]^0.65 if(x1[i] >=10 & x1[i] <= 15 &

Hi again R People: I have the following time series: >x.ts Jan Feb Mar Apr May Jun Jul Aug Sep 2000 0.95 0.66 0.83 0.66 -1.45 -1.25 0.33 1.03 -0.48 2001 2.55 1.21 -1.10 -0.63 0.01 -2.20 -0.51 1.12 1.11 2002 -1.37 0.55 -0.63 -0.56 0.92 -1.73 0.59 0.77 0.30 2003 0.55 -0.01 -0.54 2.27 -1.29 -0.23 0.09 -0.50 -0.61 Oct Nov Dec 2000 0.84 -1.35

I am looking for simple introduction to cluster analysis using R, that would be understandable to a novice in statistics. Or, could someone perhaps help me understand how to proceed in my analysis? I am very new to both statistics and R, but am trying hard to avoid having to use SPSS as everyone around me... I have dataset on people presenting their opinions on different religious

Hi, I am trying to add text to the bottom of a lattice bwplot with multiple panels. I would like to add a label below each boxplot, but the labels do not come from the data. I've tried the following, code: f1 <- c(rep(c(rep("a", 3), rep("b", 3), rep("c", 3)), 2)) f2 <- c(rep("A", 9), rep("B", 9)) dv <- c(0.9, 0.8, 0.85, 0.6, 0.65,

Full_Name: John Garvin Version: 1.9.0 OS: Linux Submission from: (NULL) (128.42.129.78) This may or may not technically be a bug, but it's certainly an annoyance. Rprof only takes into account computation that occurs inside functions. If a time-consuming operation occurs outside a function, it doesn't record the time it takes. Consider this program 'array.r': Rprof() foo <-

I've a matrix like this: 1985 1.38 1.27 1.84 2.10 0.59 3.47 1986 1.05 1.13 1.21 1.54 0.21 2.14 1987 1.33 1.21 1.77 1.44 0.27 2.85 1988 1.86 1.06 2.33 2.14 0.55 1.40 1989 2.10 0.65 2.74 2.43 1.19 1.45 1990 1.55 0.00 1.59 1.94 0.99 2.14 1991 0.92

I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)

Hello R-users, I apologize for my question but I'm a newbie. I want to read a file which columns separator is "\t". At the end of each row there is a "\n" to go to the following line. The three first lines are remarks lines and the fourth contains columns titles ( variables names, ids, dates, calculated values, observed values...) . I do: read.table("myFile",