Displaying 1 result from an estimated 1 matches for "0.49125".
Did you mean:
0.491250
2013 Apr 03
4
Better way of writing R code
Dear R forum,
(Pl note this is not a finance problem)
I have two data.frames as
currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",