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--------------------------------------------------------------------- Red Hat, Inc. Security Advisory Synopsis: New lpr packages available Advisory ID: RHSA-2000:002-01 Issue date: 2000-01-07 Updated on: 2000-01-07 Keywords: lpr lpd DNS sendmail Cross references: --------------------------------------------------------------------- 1. Topic: New lpr packages are available to fix two

Hi, I'm a database admin for a database which manage chromatographic results of products during stability studies. I use R for the reporting of the results in MS Word through R2wd. But now I think I need your help: suppose we have the following data frame: ID rrt Mnd Result 1 0.45 0 0.10 1 0.48 0 0.30 1 1.24 0 0.50 2 0.45 3 0.20 2 0.48 3 0.60 2 1.22 3 0.40 3

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

Hi R users, I have a data frame that contains 10K obs and 200 variables where I am trying to format the numeric columns to look like the output table below (format to 2 decimal places) but I am having no luck.. Can someone tell me the best way to accomplist this? Thanks in advance for any help! str(ad.test) 'data.frame': 10,000 obs. of 200 variables: $ ID : Factor

Dear R users, I have some trouble with the aggregate function. Here are my data > daf S_id AF_Class count... R_gc_percent S_length 5 8264497 1 30 0.48 35678 6 8264497 3 7 0.48 35678 8 8264554 1 31 0.51 38894 9 8264554 2 11 0.51 38894 10 8264554 3 1 0.51 38894

Is there an easy way of converting an aov.summary into a matrix in which the rows are the factor names and the columns are Df, Sum Sq, Mean Sq, F value and Pr. For example, convert Df Sum Sq Mean Sq F value Pr(>F) block 5 343.29 68.66 4.4467 0.015939 * N 1 189.28 189.28 12.2587 0.004372 ** P 1 8.40 8.40 0.5441 0.474904 K

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

Dear arun and all R users, I will first of all try to simply define my issue.. I have data in the following format Year Discharge dd/mm/yyyy x .. … … … There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that??? I have also ,written

Folks My Centos 7 systems are all failing to update because of Error: Package: orage-4.10.0-4.el7.x86_64 (@epel) Requires: libicalss.so.0()(64bit) Removing: libical-0.48-6.el7.x86_64 (@base) libicalss.so.0()(64bit) Updated By: libical-1.0.1-1.el7.x86_64 (cr) ~libicalss.so.1()(64bit) Error: Package: orage-4.10.0-4.el7.x86_64

Hi Step 1: I create a data.frame called iolm. Step 2: I create a conditional subset i_wtr. Step 3: In this subset I add 0.3 to all values in the IOLM_AST column. Step 4: Now I am looking for the best way to Œmerge¹ the altered subset back into the original iolm data.frame ## STEP 1 >iolm ID IOLM_AST IOLM_AXIS 1 1 1.15 165.33 2 2 1.20 79.00 3 3 0.40

Hi list, I'd like to make a factor with seven 1s and three 2s using the factor() function. That is, 1 1 1 1 1 1 1 2 2 2 I will then bind this factor to the matrix below using cbind.data.frame(). 0.56 0.48 0.22 0.59 0.32 0.64 0.26 0.60 0.25 0.38 0.24 0.45 0.56 0.67 0.78 0.97 0.87 0.79 0.82 0.85 I am new to R and have been using various manuals and have made many attempts without

Below is the code that I am using in a much larger function. I would expect a bankfull measure at zero to be between 0.6 and 0.8 approxfun is returning 0.8136986. I am sure that I am missing something. measure_bkf <- (structure(list(measurment_num = c(0, 0.2, 0.4, 0.6, 0.8, 1, 1.2, 1.4, 1.6, 1.8, 2, 2.2, 2.4, 2.6, 2.8, 3, 3.2, 3.4), bankfull_depths_m = c(-0.48, -0.48, -0.42, -0.26, 0.58,

I have observed that the tftp-hpa-0.48 tftp client sends an ACK in case it receives an error message from a tftp server. Inspecting the source code confirms this behaviour. According to the tftp RFC (RFC 1350), Sect. 2, server error messages should not be acknowledged by the client: "Most errors cause termination of the connection. An error is signalled by sending an error packet. This

Hello. Just to let everyone know: I've came across a motherboard with Intel Boot Agent GE 1.2.36 which is not able to get pxelinux.0 from tftpd-hpa 0.48 (configure ; make ; make install) without `-r blksize` option. Regards, Petya.

Apologies for sending again, I did not include the correct perl grep the first time. Please forgive the temporary idiot and do not feed the trolls. :-) Greetings again :-) On this particular production centos 4 mail server system if I rpm -qa | grep perl I get... perl-Filter-1.30-6 newt-perl-1.08-7 perl-DateManip-5.42a-3 perl-libwww-perl-5.79-5 perl-XML-Encoding-1.01-26

We encountered a weird problem today, and I thought some of you might like to hear the solution. The underlying change was listed in the 7.4 changelog, so it's not a bug, but it may drive you buggy. The majority of our HPC cluster nodes run CentOS 7, though the exact patch levels vary from node to node. None is older than 7.3, but a few newer nodes were kickstarted right to 7.4. The

Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")

Dear Rs: Hi, I am trying to read a big text file (nrows=243440, ncols=144). It seems the computational time of all the read methods (scan,readtable,read.delim) is not linear to the number of rows I want to read in: things became really slow once I tried to read in 100000 lines compare to 10000 lines). If I am reading the profiling result right, I guess scan wouldn't help either. My

Greetings :-) On this particular production centos 4 mail server system if I rpm -qa | grep perl I get... perl-Filter-1.30-6 newt-perl-1.08-7 perl-DateManip-5.42a-3 perl-libwww-perl-5.79-5 perl-XML-Encoding-1.01-26 perl-Time-HiRes-1.55-3 perl-URI-1.30-4 mod_perl-1.99_16-4.centos4 perl-HTML-Tagset-3.03-30 perl-Parse-Yapp-1.05-32 perl-XML-Parser-2.34-5 perl-XML-Dumper-0.71-2