search for: 0.45

Hi, I'm a database admin for a database which manage chromatographic results of products during stability studies. I use R for the reporting of the results in MS Word through R2wd. But now I think I need your help: suppose we have the following data frame: ID rrt Mnd Result 1 0.45 0 0.10 1 0.48 0 0.30 1 1.24 0 0.50 2 0.45 3 0.20 2 0.48 3 0.60 2 1.22 3 0.40 3

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> (FICB[,"temp"]) [1] "0.30" "0.55" "0.45" "2.30" "0.45" "0.30" "0.25" "0.30" "0.30" "1.05" "1.00" "1.00" [13] "0.30" "0.30" "0.30" "0.55" "0.30" "0.30" "0.30" "0.25" "1.00"

Folks, The contour() function wants x and y to be in increasing order. I have a situation where I have a grid in x and y, and associated z values, which looks like this: x y z [1,] 0.00 20 1.000 [2,] 0.00 30 1.000 [3,] 0.00 40 1.000 [4,] 0.00 50 1.000 [5,] 0.00 60 1.000 [6,] 0.00 70 1.000 [7,] 0.00 80 0.000 [8,] 0.00 90

Please help me to produce smoothed contour plots. I have dependent data generated at regular intervals of two independent variables and would like to produce smoothed contour plots - I cannot get interp (alima) to produce cubic interpolations of the data, only linear ones. I'm interested in smoothing as the data generation process is stochastic and produces small variations which I'd

Dear developer, in my version of R (2.4.0) as weel as in a more recent version (2.6.0) on different computers, we found this problem : > a<-(58/40-1) > a [1] 0.45 > b<-(18/40) > b [1] 0.45 > a<b [1] TRUE > a==b [1] FALSE > Something seems wrong here. but if we do > c<-0.45 > d<-0.45 > c<d [1] FALSE then everything is ok. If we use 59

Hello: I would like to be able to do a 3D scatter plot from 3 variables, 2 independent and 1 dependent. The closest R function I could find for this is "cloud". However cloud uses, as input, a matrix where the value of each matrix element is the dependent variable value at that matrix coordinate. My problem is that the independent variable values are floating point and can be of

CentOS Errata and Security Advisory CESA-2009:1432 seamonkey security update for CentOS 3 x86_64: https://rhn.redhat.com/errata/RHSA-2009-1432.html The following updated file has been uploaded and is currently syncing to the mirrors: x86_64: updates/x86_64/RPMS/seamonkey-1.0.9-0.45.el3.centos3.i386.rpm updates/x86_64/RPMS/seamonkey-1.0.9-0.45.el3.centos3.x86_64.rpm

Folks, A few days ago, I had asked a question on this mailing list about making a contour plot where a function z(x,y) is evaluated on a grid of (x,y) points, and the data structure at hand is a simple table of (x,y,z) points. As usual, R has wonderful resources (and subtle complexity) in doing this, and the gurus of the list showed me the way. Here's a complete working example. One might

Please help me to produce smoothed contour plots. I have dependent data generated at regular intervals of two independent variables and would like to produce smoothed contour plots - I cannot get interp (alima) to produce cubic interpolations of the data, only linear ones. I'm interested in smoothing as the data generation process is stochastic and produces small variations which I'd

CentOS Errata and Security Advisory CESA-2009:1432 seamonkey security update for CentOS 3 i386: https://rhn.redhat.com/errata/RHSA-2009-1432.html The following updated file has been uploaded and is currently syncing to the mirrors: i386: updates/i386/RPMS/seamonkey-1.0.9-0.45.el3.centos3.i386.rpm updates/i386/RPMS/seamonkey-chat-1.0.9-0.45.el3.centos3.i386.rpm

Hallo, I have a table of names and values: joe 0.45 mike 0.34 jim 0.25 I would like to fill-in a table of all pairs of names (which I aleady have) joe.mike NA NA joe.jim NA NA mike.jim NA NA with the values from the first table in the order of the pairs. The outcome looks like joe.mike 0.45 0.34 joe.jim 0.45 0.25 mike.jim 0.34 0.25 Thanks a lot, Serguei [[alternative HTML version deleted]]

Hola La duda que tengo es la siguiente Quiero coger elementos de unas listas de valores y que haga un bucle con unas condiciones: que no sean iguales k y z y que si ha hecho la simulación para, por ejemplo 0.1 y 0.15, no lo haga para 0.15 y 0.1 (es decir tener combinaciones de esas litas) La primera condición es fácil, pero con la segunda lo conseguido creando una lista en txt y que la lea

Hi All- This seems like such a pathetic problem to be posting about, but I have no idea why this testcase does not work. I have tried this using R 2.4.1, 2.4.0, 2.3.0, and 2.0.0 on several different computers (Mac OS 10.4.8, Windows XP, Linux). Below the signature, you will find my test case R code. My point in this folly is to take a dataframe of 300,000 rows, create a filter based on two

Hi list, I'd like to make a factor with seven 1s and three 2s using the factor() function. That is, 1 1 1 1 1 1 1 2 2 2 I will then bind this factor to the matrix below using cbind.data.frame(). 0.56 0.48 0.22 0.59 0.32 0.64 0.26 0.60 0.25 0.38 0.24 0.45 0.56 0.67 0.78 0.97 0.87 0.79 0.82 0.85 I am new to R and have been using various manuals and have made many attempts without

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Dear all, I am running R 2.4.1. > library(siggenes); > library(multtest); > cl<-rep(c(0,1),c(3,3)); > sub<-exprs(AffyExpData[,c(1:3,7:9)]); > gn<-geneNames(AffyRAwData); > sam.out<-sam(sub,cl,rand=123,gene.names=gn); We're doing 20 complete permutations > sam.out SAM Analysis for the Two-Class Unpaired Case Assuming Unequal Variances Delta p0

Hi, in the code below, I am drawing 1000 samples from two beta distributions, each time using the same random number seed. Using set.seed(80) produces results I expect, in that the differences between the distributions are very small. Using set.seed(20) produces results I can't make sense of. Around half of the time, it behaves as with set.seed(80), but around half of the time, it behaves

Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")

> as.character(seq(-.25,.95,.1)) [1] "-0.25" "-0.15" "-0.05" "0.05" "0.15" "0.25" "0.35" "0.45" "0.55" "0.65" "0.75" "0.85" "0.95" > as.character(seq(-.35,.95,.1)) [1] "-0.35" "-0.25"