search for: 0.32

Dear R family, I have a question about how to detect some duplicate numeric observations. Suppose that I have two variables dataset. order value 1 0.52 2 0.23 3 0.43 4 0.21 5 0.32 6 0.32 7 0.32 8 0.32 9 0.32 10 0.12 11 0.46 12 0.09 13 0.32 14 0.25 ; Could you help me indicate where the duplicate observations in a row (e.g., 0.32) are? best, moohwan

Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,

CentOS Errata and Security Advisory 2009:0257 https://rhn.redhat.com/errata/RHSA-2009-0257.html The following updated files have been uploaded and are currently syncing to the mirrors: s390: updates/s390/RPMS/seamonkey-1.0.9-0.32.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-chat-1.0.9-0.32.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-devel-1.0.9-0.32.el3.centos3.s390.rpm

Dear R family, Suppose I have two series. order value 1 0.52 2 0.23 3 0.43 4 0.21 5 0.32 6 0.32 7 0.32 8 0.32 9 0.32 10 0.12 11 0.46 12 0.09 13 0.32 14 0.25 For these two series, I figured out the way to detect the locations of duplicate values. The next thing to do is remove the repeated values except for a value that would not be next to each other. In other words, while keeping the

CentOS Errata and Security Advisory CESA-2009:0257 seamonkey security update for CentOS 3 x86_64: https://rhn.redhat.com/errata/RHSA-2009-0257.html The following updated file has been uploaded and is currently syncing to the mirrors: x86_64: updates/x86_64/RPMS/seamonkey-1.0.9-0.32.el3.centos3.i386.rpm updates/x86_64/RPMS/seamonkey-1.0.9-0.32.el3.centos3.x86_64.rpm

CentOS Errata and Security Advisory CESA-2009:0257 seamonkey security update for CentOS 3 i386: https://rhn.redhat.com/errata/RHSA-2009-0257.html The following updated file has been uploaded and is currently syncing to the mirrors: i386: updates/i386/RPMS/seamonkey-1.0.9-0.32.el3.centos3.i386.rpm updates/i386/RPMS/seamonkey-chat-1.0.9-0.32.el3.centos3.i386.rpm

Hello everyone,           I have a basic question regarding logical operators. > x<-seq(-1,1,by=0.02) > x   [1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78  [13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54  [25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30  [37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16

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CentOS Errata and Security Advisory 2009:0257 https://rhn.redhat.com/errata/RHSA-2009-0257.html The following updated files have been uploaded and are currently syncing to the mirrors: ia64: updates/ia64/RPMS/seamonkey-1.0.9-0.32.el3.centos3.ia64.rpm updates/ia64/RPMS/seamonkey-chat-1.0.9-0.32.el3.centos3.ia64.rpm updates/ia64/RPMS/seamonkey-devel-1.0.9-0.32.el3.centos3.ia64.rpm

The following errata for CentOS-2 have been built and uploaded to the centos mirror: RHSA-2009:0398-01 Critical: seamonkey security update Files available: seamonkey-1.0.9-0.32.el2.c2.1.i386.rpm seamonkey-chat-1.0.9-0.32.el2.c2.1.i386.rpm seamonkey-devel-1.0.9-0.32.el2.c2.1.i386.rpm seamonkey-dom-inspector-1.0.9-0.32.el2.c2.1.i386.rpm seamonkey-js-debugger-1.0.9-0.32.el2.c2.1.i386.rpm

One more Version! It's time to test this script until it is one of the last versions. I don't want to spend more time into this so I desided to soonly quit this project. Here the Changes since 0.31: 0.32 No Changes to Functitonality, but cool stuff :) - Better Trap-handling - Nicer Sleeper-function (I love it) - No output to the shell but only the ones by getwinegit.sh blackbox? no,

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Hi list, I'd like to make a factor with seven 1s and three 2s using the factor() function. That is, 1 1 1 1 1 1 1 2 2 2 I will then bind this factor to the matrix below using cbind.data.frame(). 0.56 0.48 0.22 0.59 0.32 0.64 0.26 0.60 0.25 0.38 0.24 0.45 0.56 0.67 0.78 0.97 0.87 0.79 0.82 0.85 I am new to R and have been using various manuals and have made many attempts without

I have a dataframe (x) and I'm plotting the 5th column vs the index. I also have a vector (v) with a few select points that I want to emphasize with a dot for those points > head(x) period AP EU LA NA 1 Jan 2007 0.18 0.45 0.19 3.19 2 Feb 2007 0.14 0.48 0.36 3.55 3 Mar 2007 0.14 0.42 0.46 2.61 4 Apr 2007 0.24 0.73 0.32 4.32 5 May 2007 0.19 0.60 0.32 4.40 6 Jun 2007 0.14 0.38

Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.

$ R --version R 1.6.1 (2002-11-01). So I would like to perform principal components analysis on a 16X16 correlation matrix, [princomp(cov.mat=x) where x is correlation matrix], the problem is princomp complains that it is not non-negative definite. I called eigen() on the correlation matrix and found that one of the eigenvectors is close to zero & negative (-0.001832311). Is there any way

Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")

Hi, I have some problems with my repeated measures analysis. When I compute it with SPSS I get different results than with R. Probably I am doing something wrong in R. I have two groups (1,2) both having to solve a task under two conditions (1,2). That is one between subject factor (group) and one within subject factor (task). I tried the following: aov(Score

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Dear all I am a BEGINNER and have R on my Mac. I saved my excel file as .txt file, I have just one column with first row as the column name. My file when read by R looks like this. After reading the table I try to make a histogram by hist(dbh), it says object dbh not found. What am I doing wrong? thanks dbh 1 11.53 2 16.05 3 7.36 4 16.05 5 8.66 6 12.74 7 22.93 8 7.55 9