search for: 0.275

Displaying 20 results from an estimated 42 matches for "0.275".

Did you mean: 0.25
1998 Apr 27
1
R-beta: vectors in dataframe?
I have a file: x y z 0.025 0.025 1.65775 0.025 0.050 1.62602 0.025 0.075 1.63683 0.025 0.100 1.91847 0.025 0.125 2.00913 0.025 0.150 1.82222 0.025 0.175 1.70901 0.025 0.200 1.39759 0.025 0.225 1.39089 0.025 0.250 1.04762 If I read the file like this: data<-read.table("file.dat") How do I access the vectors x,y,z that are inside the dataframe data? I studied Venables and
2010 Sep 16
2
problem reading Matlab file into R
Hi, I'm trying to read a .mat file into R (2.11.1) with medium success so far. The file I have is a MATLAB 5.0 MAT-file exported from RiverSurveyor LIVE software (http://www.sontek.com/software.php). I have R.matlab and Rcompression installed and readMat() starts reading the file, as can be seen in verbose mode (hence medium success), but then gives the following error: Error in dim(matrix)
2009 Jun 01
3
exporting data to csv file -problem with column names
I have a data.frame with three columns + the row number Sample MidPoint Count [1,] 1 0.025 1 [2,] 1 0.075 3 [3,] 1 0.125 15 [4,] 1 0.175 12 [5,] 1 0.225 5 [6,] 1 0.275 8 When I export the data to a csv the column names are shifted because the row numbers are being exported as well. Sample MidPoint
2012 Jul 02
1
How to get prediction for a variable in WinBUGS?
Dear all,I am a new user of WinBUGS and need your help. After running the following code, I got parameters of beta0 through beta4 (stats, density), but I don't know how to get the prediction of the last value of h, the variable I set to NA and want to model it using the following code.Does anyone can given me a hint? Any advice would be greatly appreciated.Best
2007 May 31
1
plotting variable sections of hourly time series data using plot.zoo
Dear list, I have to look examine hourly time - series and would like to plot variable section of them using plot.zoo. Hourly time series data which looks like this: YYYY MM DD HH P-uk P-kor P-SME EPOT EREA RO R1 R2 RGES S-SNO SI SSM SUZ SLZ 2003 1 1 1 0.385 0.456 0.021 0.000 0.000 0.000 0.013 0.223 0.235 0.01 0.38
2007 May 14
1
cross-validation / sensitivity anaylsis for logistic regression model
Hi, I have developed a logistic regression model in the form of (factor_1~ numeric + factor_2) and would like to perform a cross-validation or some similar form of sensitivity analysis on this model. using cv.glm() from the boot package: # dataframe from which model was built in 'z' # model is called 'm_geo.lrm' # as suggested in the man page for a binomial model: cost <-
2009 Jan 14
1
Can't find files after install package (Windows)
I am a total newbie at R but experienced with computers. If this is not the right forum for this question, please let me know one that is. I searched in the R manuals in the Help section, the Nabble help and Rseek but no luck. I am trying to install the package gcl on my recently installed R 2.8.1 I searched on cran for the windows version and found a zip file for the package In RGui, I ran
2005 Dec 05
1
Consult a analysis problem.Thank you!
Hello everybody, Could I consult you a question? I am doing an analysis about some data. I used Anova analysis. Its PValue returned is about 0.275, no signal. But through the box-chart, I think it exist discrepancy between A and B. And then I tried to use the ks.test, fisher.test and var.test to do analysis. Their PValue returned are all imperfect. If we think the PValue below 0.05 means it
2010 Nov 17
3
stacking consecutive columns
I have a file, each column of which is a separate year, and each row of each column is mean precipitation for that month. Looks like this (except it goes back to 1964). month X2000 X2001 X2002 X2003 X2004 X2005 X2006 X2007 X2008 X2009 1 1.600 1.010 4.320 2.110 0.925 3.275 3.460 0.675 1.315 2.920 2 2.960 3.905 3.230 2.380 2.720 1.880 2.430 1.380
2004 Aug 17
1
strptime() bug? And additional problem in package "tseries"
Hi all, I've got some problems with irts objects, one of which could be a bug: 1) Read a table with several columns from Postgres and the first column is Timestamp with timezone (this is OK). An extract is: raincida$ts: [2039] "25/03/2000 22:00:00 UTC" "25/03/2000 23:00:00 UTC" [2041] "26/03/2000 00:00:00 UTC" "26/03/2000 01:00:00 UTC" [2043]
2024 Aug 02
2
grep
Good Morning. Below I like statement like j<-grep(".r\\b",colnames(mydata),value=TRUE); j with the \\b option which I read long time ago which Ive found useful. Are there more or these options, other than ? grep? Thanks. dstat is just my own descriptive routine. > x ?[1] "age"????????? "sleep"??????? "primary"????? "middle" ?[5]
2006 Nov 28
2
Problem with pairs() in nlme
Dear r-helpers, After successfully running require(nlme) vfr.lmL <- lmList( estimate ~ (slant + respType + visField + hand)^2 | subject, vfr ) pairs(vfr.lmL, id = 0.01, adj = -0.5) # Pinheiro & Bates (p. 141) produces the following error: Error in sprintf(gettext(fmt, domain = domain), ...) : object "form" not found Any guesses as to what I may have done wrong?
2012 Jan 22
2
Calculating & plotting a linear regression between two correlated variables
Hi, I have a Community (COM) composed of 6 species: A, B, C, D, E & F. The density of my Community is thus (Eq.1): dCOM = dA + dB + dC + dE + dF I would like to calculate and plot a linear regression between the density of each of my species and the density of the whole community (illustrating how the density of each species varies with variations of the whole community). For example, I would
2007 Aug 09
2
Systematically biased count data regression model
Dear all, I am attempting to explain patterns of arthropod family richness (count data) using a regression model. It seems to be able to do a pretty good job as an explanatory model (i.e. demonstrating relationships between dependent and independent variables), but it has systematic problems as a predictive model: It is biased high at low observed values of family richness and biased low at
2003 May 08
1
A problem in a glm model
Hallo all, I have the following glm model: f1 <- as.formula(paste("factor(y.fondi)~", "flgsess + segmeta2 + udm + zona.geo + ultimo.prod.", "+flg.a2 + flg.d.na2 + flg.v2 + flg.cc2", " +(flg.a1 + flg.d.na1 + flg.v1 + flg.cc1)^2", " + flg.a2:flg.d.na2 + flg.a2:flg.v2 +
2013 Feb 23
2
assign index to colnames(matrix)
Hello, I’m trying to follow the syntax of a script from a journal website. In order to create a regression formula used later in the script, the regression matrix must have column names “X1”, “X2”, etc. I have tried to assign these column names to my matrix ScoutRSM.mat using a for loop, but I don’t know how to interpret the error message. Suggestions? Thanks, Paul
2024 Aug 02
1
grep
?s 02:10 de 02/08/2024, Steven Yen escreveu: > Good Morning. Below I like statement like > > j<-grep(".r\\b",colnames(mydata),value=TRUE); j > > with the \\b option which I read long time ago which Ive found useful. > > Are there more or these options, other than ? grep? Thanks. > > dstat is just my own descriptive routine. > > > x > ?[1]
2008 Aug 08
2
aggregate
Dear All- I have a dataset that is comprised of the following: doy yr mon day hr hgt1 hgt2 hgt3 co21 co22 co23 sig1 sig2 sig3 dif flag 244.02083 2005 09 01 00 2.6 9.5 17.8 375.665 373.737 373.227 3.698 1.107 0.963 -0.509 PRE 244.0625 2005 09 01 01 2.6 9.5 17.8 393.66 384.773 379.466 15.336 11.033 5.76 -5.307 PRE 244.10417 2005 09 01 02 2.6 9.5 17.8 411.162 397.866 387.755 6.835 5.61 6.728
2005 Sep 20
3
Strange Result using weightedMedian
Dear all, I found a strange result using R's weightedMedian function. Consider the following: > x <- c (0.2, 0.3, 0.5) > w <- c (1,1,2) > weightedMedian(x,w) > 0.3666 In cases like above, when the weights are integers, one could argue that the weighted median should be the same as the standard median with the elements repeated according to their weights. This is
2009 Nov 25
0
ROCR Issue: Averaging Across Multiple Classifier Runs in ROC Curve
Dear R-philes, I am having some trouble averaging across multiple runs of a classifier in an ROC Curve. I am using the ROCR package and the plot() method. First, I initialize a list with two elements where each element is a list of predictions and labels: vowel.ROC <- list(predictions=list(), labels=list()) For every run of the classifier, I append the scores and labels to their