search for: 0.156

the following the the lower.tri matrix in a file named luxry.car and i want to read it in R as a lower.tri matrix.how can i do? i have try to use help.search("read"),but no result what i want. 1.000 0.591 1.000 0.356 0.350 1.000

Dear R-friends, For the following data: > xy x y i 1 731 0.313 2 2 739 0.340 2 3 790 0.373 2 4 855 0.451 2 5 980 0.608 2 6 575 0.156 1 7 608 0.207 1 8 630 0.249 1 9 670 0.332 1 10 838 0.377 1 11 964 0.466 1 > coplot(y ~ x|i, data=xy) coplot gives 3 panels, rather than 2, namely one for i=1 and one for i=2. Futhermore, when I extand data fram xy to have i=3 as follows:

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have the following data: > y [1] 0.000 0.004 0.008 0.016 0.024 0.032 0.044 0.064 0.072 0.088 0.108 0.140 [13] 0.156 0.180 0.208 0.236 0.264 0.296 0.320 0.360 0.408 0.444 0.472 0.524 [25] 0.576 > x [1] 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500 [16] 1600 1700 1800 1900 2000 2100 2200 2300 2400 2500 I'd

Dear R-helpers, First I apologize if my question is quite simple I have a large datasets which more 100 variables. For a research I need to change all name of variables with add one or more letters on each variables. For example, > data(Pima.tr) > Pima.tr[1:5,] npreg glu bp skin bmi ped age type 1 5 86 68 28 30.2 0.364 24 No 2 7 195 70 33 25.1 0.163 55 Yes 3 5

Hi list members, I saw a couple lavaan posts here so I think I?m sending this to the correct list. I am trying to run a multigroup analysis with lavaan in order to compare behavioural correlations across two populations. I?m following the method suggested in the paper by Dingemanse et al. (2010) in Behavioural Ecology. In one of the groups, lavaan returns negative variance for one path and I?m

I am trying to use t.test on the following data: date type INTERVAL nCASES MTF SDF MTO SDO nFST MF nOBS MO MB BIASCV BIASEV ME MAE RMSE CRCF 2001-06-15 avn GE1.00 4385 0.246 0.300 1.502 0.556 1367 1.373 4385 1.502 1.471 0.285 0.164 -1.256 1.266 1.399 0.056 2001-06-15 avn

Hello R'ers, I have a large set of data which has many y samples for each unit x. The data might look like: Seconds Response_time ---------- ---------------- 0 0.150 0 0.202 0 0.065 1 0.110 1 0.280 2 0.230 2 0.156 3 0.070 3 0.185 3 0.255 3 0.311 3 0.120 4 .... and so on When I do a basic plot with type=l or the default of points it obviously plots every

A most puzzling network conundrum has arisen while I was attempting to create a virtual network behind a virtual router which in turn connects the virtual network to my real network. My machine (192.168.103.23) is on the network with my router (192.168.103.1). The virtual router, tiara, has to connect my 192.168.103.* network with the virtual 10.0.0.* network which comprises two other virtual

Hi All, I have conducted the following survival analysis which appears to be OK (thanks BRipley for solving my earlier problem). > surv.mod1 <- survreg( Surv(timep1, relall6)~randgrpc, data=Dataset, dist="weibull", scale = 1) > summary(surv.mod1) Call: survreg(formula = Surv(timep1, relall6) ~ randgrpc, data = Dataset, dist = "weibull", scale = 1)

I am trying to use rbind to have the two data on the top of each other but I am getting an extra X on the column header and the rows are numberd , How to get rid of this problem? I appreciate your help x1<- read.table(file="data1.txt", header=T, sep="\t") x2<-read.table(file="data2.txt", header=T, sep="\t") y<-rbind(x1,x2) > y X0

Dear subscribers, I am looking for a function which would allow me to model the dependent variable as the number of successes in a series of Bernoulli trials. My data looks like this ID TRIALS SUCCESSESS INDEP1 INDEP2 INDEP3 1 4444 0 0.273 0.055 0.156 2 98170 74 0.123 0.456 0.789 3 145486 30 0.124

I am trying to rsync a machine running CYGWIN_NT-5.2 server 1.5.24(0.156/4/2) to another which runs FreeBSD 6.2-STABLE; both with rsync 2.6.9. I'm trying to "pull" the files from the Cygwin machine with: /usr/local/bin/rsync -avz --delete --delete-excluded -e "ssh" [user]@[host]:"/cygdrive/e/Shared" /home/[host] However, rsync stalls. This seems to be

Hello: I am a rookie in using R. When I used the unit root test in "CADFtest", I got the different t-test statistics between using criterion="BIC" and no using criterion. But when I checked the result with eviews, I find out that no using criterion is correct. Why after using criterion="BIC", I got the different result? Paul > data(Canada) > ADFt

$ ls -l a.wav -rw-r--r-- 1 rootboy None 30587804 Jan 7 23:00 a.wav $ flac -v flac 1.2.1 $ type flac flac is hashed (/usr/bin/flac) $ uname -a CYGWIN_NT-5.1 DFBJ7M51 1.5.24(0.156/4/2) 2007-01-31 10:57 i686 Cygwin $ flac -f a.wav a.wav: wrote 16323314 bytes, ratio=0.534 $ flac -l8 -f a.wav a.wav: wrote 16323314 bytes, ratio=0.534 $ flac -l5 -f a.wav a.wav: wrote 16398095 bytes, ratio=0.536 $

Dear R People: I have the following situation. I have observations that are 128 samples per second, which is fine. I want to fit them with ARIMA models, also fine. My question is, please: when I do my forecasting, do I need to do anything special to the "n.ahead" parm, please? Here is the initial setup: > xx <- ts(rnorm(128),start=0,freq=128) > str(xx) Time-Series

Hi, For further calculations I need to extract indivdual Variances of different random effects from a fitted model. I found out how to extract the correlations (VarCorr(m1)@reSumry$group1) but I was not able to find a way to extract the other components individually. To extract the Residuals I tried: (ranef(m1)@ stdErr) which unfortunately did not work. Thank you very much for your help!

Dear all, This question may be too basic quesition for this list, but if someone has time to answer I will be happy. I have tried to find out, but haven't found a consice answer. As an example I use "Pinheiro, J. C. & Bates, D. M. 2000. Mixed-effects models in S and S-PLUS. Springer, New York." page 225, where rats are fed by 3 different diets over time, which body mass has

Hi, In the following results I interpret exp(coef) as the factor that multiplies the base hazard rate if the corresponding variable is TRUE. For example, when the bucket is ks008 and fidelity <= 3, then the rate, compared to the base rate h_0(t), is h(t) = 0.200 h_0(t). My question is then, to what case does the base hazard rate correspond to? I would expect the reference to be the first

I am teaching a DTrace class and a student noticed that 2 iosnoop scripts run in two different windows were producing different results. I was not able to answer why this is. Can anyone explain this. Here are the reults from the two windows: # io.d ... sched 0 <none> 1024 dad1 W 0.156 bash 1998

Hi, In my analysis of impacts of insecticide-treated bednets on malaria, I look at the relationship between malaria incidence and mosquito behaviors. The condensed data set is copied here. Ordinary regression (lm) shows that Incidence was negatively related to Mortality. This makes sense because the latter reflected the strength of killing mosquitoes by insecticide-treated nets. Since the