Displaying 20 results from an estimated 78 matches for "0.108".
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2012 Apr 10
0
CESA-2012:0466 Critical CentOS 5 samba3x Update
CentOS Errata and Security Advisory 2012:0466 Critical
Upstream details at : https://rhn.redhat.com/errata/RHSA-2012-0466.html
The following updated files have been uploaded and are currently
syncing to the mirrors: ( sha256sum Filename )
i386:
bd761bf38e7466f89f612824f8ac73fe2558ca218a1fca167285f525c2fd58da samba3x-3.5.10-0.108.el5_8.i386.rpm
2006 Jun 14
2
data managment
First I would really like to thank the mailing list for help I got in the
past, as a new to R I am really needing some support on hoe to code the
following problem.
I am trying to sort some data I have in a big file. The file has 4 columns
and 19000 rows. An example of it looks like this:-
G 0.892 A 0.108
G 0.883 T 0.117
T 0.5 C
2012 Apr 11
0
CentOS-announce Digest, Vol 86, Issue 6
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centos-announce at centos.org
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http://lists.centos.org/mailman/listinfo/centos-announce
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When
2000 Jan 11
1
a +1 shift overlaying lines/points on a boxplot (PR#398)
Full_Name: Adrian Custer
Version: 0.90.0
OS: Linux on Thinkpad (pentium) and desktop (K6)
Submission from: (NULL) (128.32.251.234)
When I create a boxplot, and then try to overlay a lowess fit or just the
points,
the points do not appear in the highest level and the lowess curve does not
reach
the highest level. However, if I add one to each of the models, the problem is
solved.
I tried this
2010 Nov 25
2
aftreg vs survreg loglogistic aft model (different intercept term)
Hi, I'm estimating a loglogistic aft (accelerated failure time) model, just a
simple plain vanilla one (without time dependent covariates), I'm comparing
the results that I obtain between aftreg (eha package) and survreg(surv
package). If I don't use any covariate the results are identical , if I add
covariates all the coefficients are the same until a precision of 10^4 or
10^-5 except
2008 Jan 02
1
extracting pvalue from ANOVA with repeated measures
I made an ANOVA with repeated mesures
(aov(Mesure~Distance*Genre*Correct+Error(Sujet/(Distance*Genre*Correct)),
data)) and I would like to extract the pvalues.
The output is:
-----------------------------------------------------------
Error: Sujet
Df Sum Sq Mean Sq F value Pr(>F)
Residuals 21 97.082 4.623
Error: Sujet:Distance
Df Sum Sq Mean Sq F value Pr(>F)
Distance
2006 Feb 06
3
iteration history
Dear R Users
I would like to use optim function to optimize a function. I read help but I
couldn't find what I need: is it possible to get information after each
iteration, for example as there is in MATLAB:
Gradient's
Iteration Func-count f(x) Step-size infinity-norm
0 24 388.976
2009 Dec 04
3
Combinations and joint probabilities
Dear R helpers
Suppose I have two sets of ranges (interest rates) as
Range 1 : (7 – 7.50, 7.50 – 8.50, 8.50 – 10.00) with respective probabilities 0.42, 0.22 and 0.36.
Range II : (11-12, 12-14, 14-21) with respective probabilities 0.14, 0.56 and 0.30 respectively.
My problem is to form the combinations of these ranges in a decreasing order of joint probabilities. It is assumed that
2012 Mar 10
1
Draw values from multiple data sets as inputs to a Monte-Carlo function; then apply across entire matrix
Hi all,
I am trying to implement a Monte-Carlo simulation for each cell in a
spatial matrix (using mcd2 package) .
I have figured out how to conduct the simulation using data from a single
location (where I manually input distribution parameters into the R code),
but am having trouble (a) adjusting the code to pull input variables from
my various data sets and then (b) applying the entire
2009 Jan 12
4
fitting curve to data
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
I have the following data:
> y
[1] 0.000 0.004 0.008 0.016 0.024 0.032 0.044 0.064 0.072 0.088 0.108 0.140
[13] 0.156 0.180 0.208 0.236 0.264 0.296 0.320 0.360 0.408 0.444 0.472 0.524
[25] 0.576
> x
[1] 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500
[16] 1600 1700 1800 1900 2000 2100 2200 2300 2400 2500
I'd
2013 Dec 18
3
rgamma
Estimados
Quisiera tener la sintaxis generar una serie de números entre 0 y 1 con
distribución gamma de 25 puntos y que la suma de todos los puntos debe dar
1.
Por ejemplo:
c (0.000, 0.001, 0.012, 0.043, 0.078, 0.104, 0.117, 0.116, 0.108, 0.094,
0.078, 0.063, 0.049,
0.038, 0.028, 0.021, 0.015, 0.011, 0.008, 0.005, 0.004, 0.003,
0.002, 0.001, 0.001)
No hemos podido
2010 Oct 25
1
help with adding lines to current plot
HI, Dear R community,
I am using the following codes to plot, however, the lines code works. But
the line was not drawn on the previous plot and did not shown up.
How comes?
# specify the data for missense simulation
x <- seq(0,10, by=1)
y <- c(0.952, 0.947, 0.943, 0.941, 0.933, 0.932, 0.939, 0.932, 0.924, 0.918,
0.920) # missense
z <- c(0.068, 0.082, 0.080, 0.099, 0.108, 0.107,
2008 Mar 04
2
Asking, are simple effects different from 0
Hello, R-i-zens. I'm working on an data set with a factorial ANOVA
that has a significant interaction. I'm interested in seeing whether
the simple effects are different from 0, and I'm pondering how to do
this. So, I have
my.anova<-lm(response ~ trtA*trtB)
The output for which gives me a number of coefficients and whether
they are different from 0. However, I want the
2011 Mar 15
2
Calculate monthly means
I am trying to calculate monthly means by year of phosphates and nitrates from a multi year data set. Can anybody help me out with the most effective way to do this?
My data looks like this:
Collection_Date Test.Name Value
2000-01-24 17:00:00 Phosphate 0.108
2000-01-24 17:00:00 Nitrate 0.037
2001-11-12
2008 Mar 08
1
ask for help on nonlinear fitting
I have a table like the following. I want to fit Cm to Vm like this:
Cm ~ Cl+Q1*b1*38.67*exp(-b1*(Vm-Vp1)*0.03867)/(1+exp(-b1*(Vm-Vp1)*0.03867))^2+Q2*b2*38.67*exp(-b2*(Vm-Vp2)*0.03867)/(1+exp(-b2*(Vm-Vp2)*0.03867))^2
I use nls, with start=list(Q1=2e-3, b1=1, Vp1=-25, Q2=3e-3, b2=1,
Vp2=200). But I always get 'singlular gradient' error like this. But
in SigmaPlot I can get the result. How
2009 Mar 30
2
ggplot2-geom_text()
Hi: I need help with geom_text().
I would like to count the number of Locations
and put the sum of it right above each bar.
x <- "Location Lake_dens Fish Pred
Lake1 1.132 1 0.115
Lake1 0.627 1 0.148
Lake1 1.324 1 0.104
Lake1 1.265 1 0.107
Lake2 1.074 0 0.096
Lake2 0.851 0 0.108
Lake2 1.098 0 0.095
Lake2 0.418 0 0.135
Lake2 1.256 1 0.088
Lake2 0.554 1 0.126
Lake2 1.247 1 0.088
2013 Dec 18
1
rgamma
Estimado Jorge
Perdóneme que lo moleste de nuevo, hay otra condición además de que
sum(y)=1 y es que
y[1] tiene que dar 0
en el ejemplo
y<- c (0.0000000000, 0.6321985783, 0.2325728597, 0.0855587737, 0.0314753138,
0.0115791209, 0.0042597205, 0.0015670636, 0.0005764905,
0.0002120790)
y[1]=0
sum(y)=1
esto se utiliza en el paquete EpiEstim donde se
2012 Aug 03
1
Multiple Comparisons-Kruskal-Wallis-Test: kruskal{agricolae} and kruskalmc{pgirmess} don't yield the same results although they should do (?)
Hi there,
I am doing multiple comparisons for data that is not normally distributed.
For this purpose I tried both functions kruskal{agricolae} and
kruskalmc{pgirmess}. It confuses me that these functions do not yield the
same results although they are doing the same thing, don't they? Can anyone
tell my why this happens and which function I can trust?
kruskalmc() tells me that there are no
2006 Sep 25
2
rpart
Dear r-help-list:
If I use the rpart method like
cfit<-rpart(y~.,data=data,...),
what kind of tree is stored in cfit?
Is it right that this tree is not pruned at all, that it is the full tree?
If so, it's up to me to choose a subtree by using the printcp method.
In the technical report from Atkinson and Therneau "An Introduction to recursive partitioning using the rpart
2008 Aug 22
1
problem with rbind
I am trying to use rbind to have the two data on the top of each other but I
am getting an extra X on the column header and the rows are numberd , How to
get rid of this problem? I appreciate your help
x1<- read.table(file="data1.txt", header=T, sep="\t")
x2<-read.table(file="data2.txt", header=T, sep="\t")
y<-rbind(x1,x2)
> y
X0