search for: 0.102

Hi I have dataset that consists of two columns AB 0.102 AC -0.002 BA -0.102 BC 0.270 CA 0.002 CB -0.270 I wish to create a matrix so that I can eventually plot the data. A B C A 1 0.102 -0.002 B -0.102 1 0.27 C 0.002 -0.27 1 Any help or guidance would be greatly

Dear all, The documentation for `all.equal.numeric` says Numerical comparisons for ?scale = NULL? (the default) are done by first computing the mean absolute difference of the two numerical vectors. If this is smaller than ?tolerance? or not finite, absolute differences are used, otherwise relative differences scaled by the mean absolute difference. But the actual behaviour

For the heck of it I tried upgrading to gcc 3.4.2 (from 3.3.3). It didn't make a difference. So here are the failures for llvm-test. All diffs are against the "native" output. ===================== MultiSource/Applications/sgefa cbe failed differently from jit/llc. First cbe: 84c84 < One-Norm(A) ---------- 8.879153e+02. --- > One-Norm(A) ---------- 8.879156e+02.

Hello Everyone,I think this is a very simple problem, I have been struggling with it for a few days now. I have a 10-year daily data in the following format. Date A B C D E 1978-10-22 18 20.64 0.0 0.176 -1.76 1978-10-23 15 17.06 0.4 0.147 2.52 1978-10-24 3 7.588 0.0 0.068 -6.86 1978-10-25 9 11.491 0.0 0.102

On Thu, 9 Sep 2004 20:16:37 -0700 Jeff Cohen <jeffc at jolt-lang.org> wrote: > On Thu, 9 Sep 2004 08:52:10 -0700 > Jeff Cohen <jeffc at jolt-lang.org> wrote: > > > > I haven't got around to this yet but I will. The odds are good the > > > problem is in a BSD system header file so I need to capture the > > > preprocessed source. > > >

Dear Jon, thank you for raising the issue, >>>>> Jon Clayden <jon.clayden at gmail.com> >>>>> on Tue, 28 Jul 2015 12:14:48 +0100 writes: > Sorry; minor clarification. The actual test criterion in the example I > gave is of course abs((0.1-0.102)/0.1) < 0.01, not abs(0.1) < 0.01. In > any case, this does not match (my reading of) the docs,

Hi all I am trying to generate a normal unbalanced data to estimate the coefficients of LM, LMM, GLM, and GLMM and their standard errors. Also, I am trying to estimate the variance components and their standard errors. Further, I am trying to use the likelihood ratio test to test H0: sigma^2_b = 0 (random effects variance component), and the t-test to test H0:mu=0 (intercept of the model Yij = mu

Hi, Is anybody know the purpose of this method (xen_evtchn_do_upcall)? When I run a user level application involved in TCP receiving and the SoftIRQ for eth0 on the same CPU core, everything is OK. But if I run them on 2 different cores, there will be xen_evtchn_do_upcall() existing (maybe when the local_bh_disable<http://www.cs.fsu.edu/~baker/devices/lxr/http/ident?i=local_bh_disable>() or

Sorry; minor clarification. The actual test criterion in the example I gave is of course abs((0.1-0.102)/0.1) < 0.01, not abs(0.1) < 0.01. In any case, this does not match (my reading of) the docs, and the result is not `TRUE`. Regards, Jon On 28 July 2015 at 11:58, Jon Clayden <jon.clayden at gmail.com> wrote: > Dear all, > > The documentation for `all.equal.numeric` says

My apologies, to elaborate I carried out a correlation analysis and I want to plot the data (similar to the graphs available in the corrplot package. However, the results are as follows (I have many more combinations): AB 0.102 AC -0.002 BA -0.102 BC 0.270 CA 0.002 CB -0.270 I now want to create a matrix that uses the names from the

Hi r-users,   I would like to extract the data that match.  Attached is my data: I'm interested in matchind the value in column 'intg' with value in column 'rand_no' > cbind(z=z,intg=dd,rand_no = rr)             z  intg rand_no    [1,]  0.00 0.000   0.001    [2,]  0.01 0.000   0.002    [3,]  0.02 0.000   0.002    [4,]  0.03 0.000   0.003    [5,]  0.04 0.000   0.003    [6,] 

On Thu, Apr 04, 2019 at 11:52:46AM -0400, Michael S. Tsirkin wrote: > I simply love it that you have analysed the individual impact of > each patch! Great job! Thanks! I followed Stefan's suggestions! > > For comparison's sake, it could be IMHO benefitial to add a column > with virtio-net+vhost-net performance. > > This will both give us an idea about whether the

On Thu, Apr 04, 2019 at 11:52:46AM -0400, Michael S. Tsirkin wrote: > I simply love it that you have analysed the individual impact of > each patch! Great job! Thanks! I followed Stefan's suggestions! > > For comparison's sake, it could be IMHO benefitial to add a column > with virtio-net+vhost-net performance. > > This will both give us an idea about whether the

Hello, I am trying to filter a data set like below so that the peaks in the Phase value are more obvious and can be identified by a peak finding function following the useful advise of Carl Witthoft. I have written the following for(i in length(data$Phase)){ newphase=if(abs(data$Phase[i+1]-data$Phase[i])>6){ data$Phase[i+1] }else{data$Phase[i] } } I get the following error which I have not

This series tries to increase the throughput of virtio-vsock with slight changes: - patch 1/4: reduces the number of credit update messages sent to the transmitter - patch 2/4: allows the host to split packets on multiple buffers, in this way, we can remove the packet size limit to VIRTIO_VSOCK_DEFAULT_RX_BUF_SIZE - patch 3/4: uses

This series tries to increase the throughput of virtio-vsock with slight changes: - patch 1/4: reduces the number of credit update messages sent to the transmitter - patch 2/4: allows the host to split packets on multiple buffers, in this way, we can remove the packet size limit to VIRTIO_VSOCK_DEFAULT_RX_BUF_SIZE - patch 3/4: uses

On 2019/4/4 ??6:58, Stefano Garzarella wrote: > This series tries to increase the throughput of virtio-vsock with slight > changes: > - patch 1/4: reduces the number of credit update messages sent to the > transmitter > - patch 2/4: allows the host to split packets on multiple buffers, > in this way, we can remove the packet size limit to >

On Thu, Apr 04, 2019 at 06:47:15PM +0200, Stefano Garzarella wrote: > On Thu, Apr 04, 2019 at 11:52:46AM -0400, Michael S. Tsirkin wrote: > > I simply love it that you have analysed the individual impact of > > each patch! Great job! > > Thanks! I followed Stefan's suggestions! > > > > > For comparison's sake, it could be IMHO benefitial to add a

On Thu, Apr 04, 2019 at 12:58:34PM +0200, Stefano Garzarella wrote: > This series tries to increase the throughput of virtio-vsock with slight > changes: > - patch 1/4: reduces the number of credit update messages sent to the > transmitter > - patch 2/4: allows the host to split packets on multiple buffers, > in this way, we can remove the packet

I have a table like the following. I want to fit Cm to Vm like this: Cm ~ Cl+Q1*b1*38.67*exp(-b1*(Vm-Vp1)*0.03867)/(1+exp(-b1*(Vm-Vp1)*0.03867))^2+Q2*b2*38.67*exp(-b2*(Vm-Vp2)*0.03867)/(1+exp(-b2*(Vm-Vp2)*0.03867))^2 I use nls, with start=list(Q1=2e-3, b1=1, Vp1=-25, Q2=3e-3, b2=1, Vp2=200). But I always get 'singlular gradient' error like this. But in SigmaPlot I can get the result. How