Rails spinoffs - Jun 2007 - img element inside div not accessible with $$() or getElementsBySelector

I can''t access an img inside a div using the $$() syntax. Using
getElementsBySelector doesn''t work either. Both return empty arrays. I
can access it with getElementById, however.

<div id="foo">
<img id="image" src="blah.jpg">
<div id="bar"
</div>

- Using $$(''#foo img'') returns an empty array
- Using
$(''foo'').getElementsBySelector(''img'') gets
me an empty array
- Using $(''foo'').childElements() gets me an array with
''blah''
inside... but not the img.
- Using $(''image'') works.

To me, it looks like img doesn''t count as an element of any kind. But
I don''t see how that''s possible, and from the docs it
doesn''t look
like it''s supposed to work that way. Is this a bug or am I missing
something?

Thanks for your help!


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This successfully alerted the image source name:

<div id="foo">
<img id="image" src="blah.jpg">
<div id="bar"
</div>
<script language=javascript>
var thing = $$(''#foo img'')
alert(thing[0].src)
</script>

If it doesn''t work for you maybe you should grab a fresh copy of
Prototype.

On Jun 28, 3:30 pm, Kalvin
<findkal...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:
> I can''t access an img inside a div using the $$() syntax. Using
> getElementsBySelector doesn''t work either. Both return empty
arrays. I
> can access it with getElementById, however.
>
> <div id="foo">
> <img id="image" src="blah.jpg">
> <div id="bar"
> </div>
>
> - Using $$(''#foo img'') returns an empty array
> - Using
$(''foo'').getElementsBySelector(''img'') gets
me an empty array
> - Using $(''foo'').childElements() gets me an array with
''blah''
> inside... but not the img.
> - Using $(''image'') works.
>
> To me, it looks like img doesn''t count as an element of any kind.
But
> I don''t see how that''s possible, and from the docs it
doesn''t look
> like it''s supposed to work that way. Is this a bug or am I missing
> something?
>
> Thanks for your help!

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Oh, shoot-- you''re right, it does work.

The issue I''m actually having is that $$(''img:not(#bag
img)'') returns
all imgs including #bag img... but I don''t think using two selectors
is actually supported. (Someone tell me if I''m wrong!)

Thanks for your help!

On Jun 28, 12:42 pm, Diodeus
<diod...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:
> This successfully alerted the image source name:
>
> <div id="foo">
> <img id="image" src="blah.jpg">
> <div id="bar"
> </div>
> <script language=javascript>
> var thing = $$(''#foo img'')
> alert(thing[0].src)
> </script>
>
> If it doesn''t work for you maybe you should grab a fresh copy of
> Prototype.
>
> On Jun 28, 3:30 pm, Kalvin
<findkal...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:
>
> > I can''t access an img inside a div using the $$() syntax.
Using
> > getElementsBySelector doesn''t work either. Both return empty
arrays. I
> > can access it with getElementById, however.
>
> > <div id="foo">
> > <img id="image" src="blah.jpg">
> > <div id="bar"
> > </div>
>
> > - Using $$(''#foo img'') returns an empty array
> > - Using
$(''foo'').getElementsBySelector(''img'') gets
me an empty array
> > - Using $(''foo'').childElements() gets me an array
with ''blah''
> > inside... but not the img.
> > - Using $(''image'') works.
>
> > To me, it looks like img doesn''t count as an element of any
kind. But
> > I don''t see how that''s possible, and from the docs
it doesn''t look
> > like it''s supposed to work that way. Is this a bug or am I
missing
> > something?
>
> > Thanks for your help!

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