Rails spinoffs - Mar 2007 - Get back into object's scope after onSuccess?

Hello, please help me with this:
Thank you!

var foo = Class.create();
foo.prototype = {
	testVar: null,
	script: ''/script.foo.php'',
	initialize: function(){},
	sendRequest: function(){
		textVar = "test string.";
		new Ajax.Request(this.script, {onSuccess:this.handleResponse});
	},
	handleResponse: function(response){
		// I can''t access foo''s properties or methods from within
		// here after called from onSuccess.
		alert(this.textVar); // returns undefined instead of "test string."
		alert(this);
		// alert(this) returns [object Window] in Firefox and [object] in
IE6
		// instead of [object Object] as is foo.
	}
};


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Use bind:

new Ajax.Request(this.script, {onSuccess:this.handleResponse.bind(this)});

http://prototypejs.org/api/function

Colin



SAR wrote:
> Hello, please help me with this:
> Thank you!
>
> var foo = Class.create();
> foo.prototype = {
> 	testVar: null,
> 	script: ''/script.foo.php'',
> 	initialize: function(){},
> 	sendRequest: function(){
> 		textVar = "test string.";
> 		new Ajax.Request(this.script, {onSuccess:this.handleResponse});
> 	},
> 	handleResponse: function(response){
> 		// I can''t access foo''s properties or methods from
within
> 		// here after called from onSuccess.
> 		alert(this.textVar); // returns undefined instead of "test
string."
> 		alert(this);
> 		// alert(this) returns [object Window] in Firefox and [object] in
> IE6
> 		// instead of [object Object] as is foo.
> 	}
> };
>
>
> >
>
>   

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That was the solution!
I also realized that referencing the object outside the call would
work as well:
	var thisObject = this;
	new Ajax.Request(this.script, {onSuccess:function(response)
{thisObject.handleXMLResponse(response);}});

But your solution was the one I was looking for for a while!

Thanks!

On Mar 5, 1:15 am, Colin Mollenhour
<eliteii...-NPSFNn/7+NYVo650/ln6uw@public.gmane.org>
wrote:
> Use bind:
>
> new Ajax.Request(this.script, {onSuccess:this.handleResponse.bind(this)});
>
> http://prototypejs.org/api/function
>
> Colin
>
> SAR wrote:
> > Hello, please help me with this:
> > Thank you!
>
> > var foo = Class.create();
> > foo.prototype = {
> >    testVar: null,
> >    script: ''/script.foo.php'',
> >    initialize: function(){},
> >    sendRequest: function(){
> >            textVar = "test string.";
> >            new Ajax.Request(this.script,
{onSuccess:this.handleResponse});
> >    },
> >    handleResponse: function(response){
> >            // I can''t access foo''s properties or
methods from within
> >            // here after called from onSuccess.
> >            alert(this.textVar); // returns undefined instead of
"test string."
> >            alert(this);
> >            // alert(this) returns [object Window] in Firefox and
[object] in
> > IE6
> >            // instead of [object Object] as is foo.
> >    }
> > };

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Hey there,

SAR a écrit :
> var foo = Class.create();
> foo.prototype = {
Aside from Colin''s answer (the usual bind issue), note that
you''re
stepping on your own foot here: if you use Class.create, you do so to
leverage an initialize function in your prototype when the object is
created.  So instead of rewriting your whole prototype like this, you
should go:

Object.extend(foo.prototype, {
  ...
});

JM2C,

-- 
Christophe Porteneuve a.k.a. TDD
"[They] did not know it was impossible, so they did it." --Mark Twain
Email: tdd-x+CfDp/qHev2eFz/2MeuCQ@public.gmane.org

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Christophe Porteneuve wrote:
> Aside from Colin''s answer (the usual bind issue), note that
you''re
> stepping on your own foot here: if you use Class.create, you do so to
> leverage an initialize function in your prototype when the object is
> created.  So instead of rewriting your whole prototype like this, you
> should go:
>
> Object.extend(foo.prototype, {
>   ...
> });
>
> JM2C,
>   
Actually there is no reason to do this. initialize is never a property 
of prototype until you make it one. Class.create returns a function that 
will call this.initialize and no properties of the prototype of that 
function are set beforehand so the YourClass.prototype = {...} works 
just fine and looks prettier :)

Colin


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Hey Colin!

Colin Mollenhour a écrit :
> will call this.initialize and no properties of the prototype of that 
> function are set beforehand so the YourClass.prototype = {...} works 
> just fine and looks prettier :)
--> D''oh!  Of course.

That''s what you get for posting while waking up in front of your tea
mug...

-- 
Christophe Porteneuve aka TDD
tdd-x+CfDp/qHev2eFz/2MeuCQ@public.gmane.org

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