Brian Smith
2025-Apr-22 16:55 UTC
[R] Generate random vectors (continuous number) with a fixed sum
i.e. we should have all elements of Reduce("+", res) should be equal to s = 0.05528650577311 My assertion is that it is not happing here. On Tue, 22 Apr 2025 at 22:20, Brian Smith <briansmith199312 at gmail.com> wrote:> > Hi Rui, > > Thanks for the explanation. > > But in this case, are we looking at the correct solution at all? > > My goal is to generate random vector where: > 1) the first element is bounded by (a[1], b[1]) and second element is > bounded by (a[2], b[2]) > 2) sum of the element is s > > According to the outcome, > The first matrix values are bounded by c(a[1], b[1]) & second matrix > values are bounded by c(a[2], b[2]) > > But, > regarding the sum, I think we should have sum (element-wise) sum > should be equal to s = 0.05528650577311. > > How could we achieve that then? > > On Tue, 22 Apr 2025 at 22:03, Rui Barradas <ruipbarradas at sapo.pt> wrote: > > > > ?s 12:39 de 22/04/2025, Brian Smith escreveu: > > > Hi Rui, > > > > > > Many thanks for your time and insight. > > > > > > However, I am not sure if I could understand the code. Below is what I > > > tried based on your code > > > > > > library(Surrogate) > > > a <- c(0.015, 0.005) > > > b <- c(0.070, 0.045) > > > set.seed(2025) > > > res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), > > > MoreArgs = list(s = 0.05528650577311, n = 2, m = 10000), a, b) > > > > > > res1 = res[[1]] > > > res2 = res[[2]] > > > > > > apply(res1, 1, min) > a ## [1] TRUE TRUE > > > apply(res2, 1, min) > a ## [1] FALSE TRUE > > > > > > I could not understand what basically 2 blocks of res signify? Which > > > one I should take as final simulation of the vector? If I take the > > > first block then the lower bound condition is fulfilled, but not with > > > the second block. However with the both blocks, the total equals s is > > > satisfying. > > > > > > I appreciate your further insight. > > > > > > Thanks and regards, > > > > > > On Mon, 21 Apr 2025 at 20:43, Rui Barradas <ruipbarradas at sapo.pt> wrote: > > >> > > >> Hello, > > >> > > >> Inline. > > >> > > >> ?s 16:08 de 21/04/2025, Rui Barradas escreveu: > > >>> ?s 15:27 de 21/04/2025, Brian Smith escreveu: > > >>>> Hi, > > >>>> > > >>>> There is a function called RandVec in the package Surrogate which can > > >>>> generate andom vectors (continuous number) with a fixed sum > > >>>> > > >>>> The help page of this function states that: > > >>>> > > >>>> a > > >>>> > > >>>> The function RandVec generates an n by m matrix x. Each of the m > > >>>> columns contain n random values lying in the interval [a,b]. The > > >>>> argument a specifies the lower limit of the interval. Default 0. > > >>>> > > >>>> b > > >>>> > > >>>> The argument b specifies the upper limit of the interval. Default 1. > > >>>> > > >>>> However in my case, the lower and upper limits are not same. For > > >>>> example, if I need to draw a pair of number x, y, such that x + y = 1, > > >>>> then the lower and upper limits are different. > > >>>> > > >>>> I tried with below code > > >>>> > > >>>> library(Surrogate) > > >>>> > > >>>> RandVec(a=c(0.1, 0.2), b=c(0.2, 0.8), s=1, n=2, m=5)$RandVecOutput > > >>>> > > >>>> This generates error with message > > >>>> > > >>>> Error in if (b - a == 0) { : the condition has length > 1 > > >>>> > > >>>> Is there any way to generate the numbers with different lower and > > >>>> upper limits? > > >>>> > > >>>> ______________________________________________ > > >>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > >>>> https://stat.ethz.ch/mailman/listinfo/r-help > > >>>> PLEASE do read the posting guide https://www.R-project.org/posting- > > >>>> guide.html > > >>>> and provide commented, minimal, self-contained, reproducible code. > > >>> Hello, > > >>> > > >>> Use ?mapply to cycle through all values of a and b. > > >>> Note that the output matrices are transposed, the random vectors are the > > >>> rows. > > >> Sorry, this is not true. The columns are the random vectors, as > > >> documented. An example setting the RNG seed, for reproducibility. > > >> > > >> > > >> library(Surrogate) > > >> > > >> a <- c(0.1, 0.2) > > >> b <- c(0.2, 0.8) > > >> set.seed(2025) > > >> res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), > > >> MoreArgs = list(s = 1, n = 2, m = 5), a, b) > > >> > > >> res > > >> #> $RandVecOutput > > >> #> [,1] [,2] [,3] [,4] [,5] > > >> #> [1,] 0.146079 0.1649319 0.1413759 0.257086 0.1715478 > > >> #> [2,] 0.253921 0.2350681 0.2586241 0.142914 0.2284522 > > >> #> > > >> #> $RandVecOutput > > >> #> [,1] [,2] [,3] [,4] [,5] > > >> #> [1,] 0.5930918 0.2154583 0.6915523 0.7167089 0.3617918 > > >> #> [2,] 0.4069082 0.7845417 0.3084477 0.2832911 0.6382082 > > >> > > >> lapply(res, colSums) > > >> #> $RandVecOutput > > >> #> [1] 0.4 0.4 0.4 0.4 0.4 > > >> #> > > >> #> $RandVecOutput > > >> #> [1] 1 1 1 1 1 > > >> > > >> > > >> Hope this helps, > > >> > > >> Rui Barradas > > >>> > > >>> > > >>> library(Surrogate) > > >>> > > >>> a <- c(0.1, 0.2) > > >>> b <- c(0.2, 0.8) > > >>> mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), > > >>> MoreArgs = list(s = 1, n = 2, m = 5), a, b) > > >>> #> $RandVecOutput > > >>> #> [,1] [,2] [,3] [,4] [,5] > > >>> #> [1,] 0.2004363 0.1552328 0.2391742 0.1744857 0.1949236 > > >>> #> [2,] 0.1995637 0.2447672 0.1608258 0.2255143 0.2050764 > > >>> #> > > >>> #> $RandVecOutput > > >>> #> [,1] [,2] [,3] [,4] [,5] > > >>> #> [1,] 0.2157416 0.4691191 0.5067447 0.7749258 0.7728955 > > >>> #> [2,] 0.7842584 0.5308809 0.4932553 0.2250742 0.2271045 > > >>> > > >>> > > >>> Hope this helps, > > >>> > > >>> Rui Barradas > > >>> > > >>> > > >> > > >> > > >> -- > > >> Este e-mail foi analisado pelo software antiv?rus AVG para verificar a presen?a de v?rus. > > >> www.avg.com > > Hello, > > > > The two blocks of res are the two random matrices, one for each > > combination of (a,b). mapply passes each of the values in its arguments > > list (the ellipses in the help page) and computes the anonymous function > > with the pairs (a[1], b[1]), (a[2], b[2]). > > > > Since a and b are two elements vectors the output res is a two members > > named list. Your error is to compare the result of apply(res2, 1, min) > > to a, when you should compare to a[2]. See the code below. > > > > > > library(Surrogate) > > a <- c(0.015, 0.005) > > b <- c(0.070, 0.045) > > set.seed(2025) > > res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), > > MoreArgs = list(s = 0.05528650577311, n = 2, m = 10000), > > a, b) > > > > res1 = res[[1]] > > res2 = res[[2]] > > > > # first check that the sums are correct > > # these sums should be s = 0.05528650577311, up to floating-point accuracy > > lapply(res, \(x) colSums(x[, 1:5]) |> print(digits = 14L)) > > #> [1] 0.05528650577311 0.05528650577311 0.05528650577311 0.05528650577311 > > #> [5] 0.05528650577311 > > #> [1] 0.05528650577311 0.05528650577311 0.05528650577311 0.05528650577311 > > #> [5] 0.05528650577311 > > #> $RandVecOutput > > #> [1] 0.05528651 0.05528651 0.05528651 0.05528651 0.05528651 > > #> > > #> $RandVecOutput > > #> [1] 0.05528651 0.05528651 0.05528651 0.05528651 0.05528651 > > > > # now check the min and max > > apply(res1, 1, min) > a[1L] ## [1] TRUE TRUE > > #> [1] TRUE TRUE > > apply(res2, 1, min) > a[2L] ## [1] TRUE TRUE > > #> [1] TRUE TRUE > > > > apply(res1, 1, max) < b[1L] ## [1] TRUE TRUE > > #> [1] TRUE TRUE > > apply(res2, 1, max) < b[2L] ## [1] TRUE TRUE > > #> [1] TRUE TRUE > > > > > > > > Which one should you take as final simulation of the vector? Both. > > The first matrix values are bounded by c(a[1], b[1]) with column sums > > equal to s. > > The second matrix values are bounded by c(a[2], b[2]) with column sums > > also equal to s. > > > > Hoep this helps, > > > > Rui Barradas > >
Rui Barradas
2025-Apr-22 22:31 UTC
[R] Generate random vectors (continuous number) with a fixed sum
Hello, Inline. ?s 17:55 de 22/04/2025, Brian Smith escreveu:> i.e. we should have > > all elements of Reduce("+", res) should be equal to s = 0.05528650577311 > > My assertion is that it is not happing here.You are right, that's not what is happening. The output is n vectors of 2 elements each. It's each of these vectors that add up to s. Appparently I misunderstood the problem. Maybe this is what you want? (There is no n argument, the matrix is always 2*m) one_vec <- function(a, b, s) { repeat{ repeat{ u <- runif(1, a[1], b[1]) if(s - u > 0) break } v <- s - u if(a[2] < v && v < b[2]) break } c(u, v) } gen_mat <- function(m, a, b, s) { replicate(m, one_vec(a, b, s)) } set.seed(2025) res <- gen_mat(10000, a, b, s) colSums(res) Hope this helps, Rui Barradas> > > On Tue, 22 Apr 2025 at 22:20, Brian Smith <briansmith199312 at gmail.com> wrote: >> >> Hi Rui, >> >> Thanks for the explanation. >> >> But in this case, are we looking at the correct solution at all? >> >> My goal is to generate random vector where: >> 1) the first element is bounded by (a[1], b[1]) and second element is >> bounded by (a[2], b[2]) >> 2) sum of the element is s >> >> According to the outcome, >> The first matrix values are bounded by c(a[1], b[1]) & second matrix >> values are bounded by c(a[2], b[2]) >> >> But, >> regarding the sum, I think we should have sum (element-wise) sum >> should be equal to s = 0.05528650577311. >> >> How could we achieve that then? >> >> On Tue, 22 Apr 2025 at 22:03, Rui Barradas <ruipbarradas at sapo.pt> wrote: >>> >>> ?s 12:39 de 22/04/2025, Brian Smith escreveu: >>>> Hi Rui, >>>> >>>> Many thanks for your time and insight. >>>> >>>> However, I am not sure if I could understand the code. Below is what I >>>> tried based on your code >>>> >>>> library(Surrogate) >>>> a <- c(0.015, 0.005) >>>> b <- c(0.070, 0.045) >>>> set.seed(2025) >>>> res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), >>>> MoreArgs = list(s = 0.05528650577311, n = 2, m = 10000), a, b) >>>> >>>> res1 = res[[1]] >>>> res2 = res[[2]] >>>> >>>> apply(res1, 1, min) > a ## [1] TRUE TRUE >>>> apply(res2, 1, min) > a ## [1] FALSE TRUE >>>> >>>> I could not understand what basically 2 blocks of res signify? Which >>>> one I should take as final simulation of the vector? If I take the >>>> first block then the lower bound condition is fulfilled, but not with >>>> the second block. However with the both blocks, the total equals s is >>>> satisfying. >>>> >>>> I appreciate your further insight. >>>> >>>> Thanks and regards, >>>> >>>> On Mon, 21 Apr 2025 at 20:43, Rui Barradas <ruipbarradas at sapo.pt> wrote: >>>>> >>>>> Hello, >>>>> >>>>> Inline. >>>>> >>>>> ?s 16:08 de 21/04/2025, Rui Barradas escreveu: >>>>>> ?s 15:27 de 21/04/2025, Brian Smith escreveu: >>>>>>> Hi, >>>>>>> >>>>>>> There is a function called RandVec in the package Surrogate which can >>>>>>> generate andom vectors (continuous number) with a fixed sum >>>>>>> >>>>>>> The help page of this function states that: >>>>>>> >>>>>>> a >>>>>>> >>>>>>> The function RandVec generates an n by m matrix x. Each of the m >>>>>>> columns contain n random values lying in the interval [a,b]. The >>>>>>> argument a specifies the lower limit of the interval. Default 0. >>>>>>> >>>>>>> b >>>>>>> >>>>>>> The argument b specifies the upper limit of the interval. Default 1. >>>>>>> >>>>>>> However in my case, the lower and upper limits are not same. For >>>>>>> example, if I need to draw a pair of number x, y, such that x + y = 1, >>>>>>> then the lower and upper limits are different. >>>>>>> >>>>>>> I tried with below code >>>>>>> >>>>>>> library(Surrogate) >>>>>>> >>>>>>> RandVec(a=c(0.1, 0.2), b=c(0.2, 0.8), s=1, n=2, m=5)$RandVecOutput >>>>>>> >>>>>>> This generates error with message >>>>>>> >>>>>>> Error in if (b - a == 0) { : the condition has length > 1 >>>>>>> >>>>>>> Is there any way to generate the numbers with different lower and >>>>>>> upper limits? >>>>>>> >>>>>>> ______________________________________________ >>>>>>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help >>>>>>> PLEASE do read the posting guide https://www.R-project.org/posting- >>>>>>> guide.html >>>>>>> and provide commented, minimal, self-contained, reproducible code. >>>>>> Hello, >>>>>> >>>>>> Use ?mapply to cycle through all values of a and b. >>>>>> Note that the output matrices are transposed, the random vectors are the >>>>>> rows. >>>>> Sorry, this is not true. The columns are the random vectors, as >>>>> documented. An example setting the RNG seed, for reproducibility. >>>>> >>>>> >>>>> library(Surrogate) >>>>> >>>>> a <- c(0.1, 0.2) >>>>> b <- c(0.2, 0.8) >>>>> set.seed(2025) >>>>> res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), >>>>> MoreArgs = list(s = 1, n = 2, m = 5), a, b) >>>>> >>>>> res >>>>> #> $RandVecOutput >>>>> #> [,1] [,2] [,3] [,4] [,5] >>>>> #> [1,] 0.146079 0.1649319 0.1413759 0.257086 0.1715478 >>>>> #> [2,] 0.253921 0.2350681 0.2586241 0.142914 0.2284522 >>>>> #> >>>>> #> $RandVecOutput >>>>> #> [,1] [,2] [,3] [,4] [,5] >>>>> #> [1,] 0.5930918 0.2154583 0.6915523 0.7167089 0.3617918 >>>>> #> [2,] 0.4069082 0.7845417 0.3084477 0.2832911 0.6382082 >>>>> >>>>> lapply(res, colSums) >>>>> #> $RandVecOutput >>>>> #> [1] 0.4 0.4 0.4 0.4 0.4 >>>>> #> >>>>> #> $RandVecOutput >>>>> #> [1] 1 1 1 1 1 >>>>> >>>>> >>>>> Hope this helps, >>>>> >>>>> Rui Barradas >>>>>> >>>>>> >>>>>> library(Surrogate) >>>>>> >>>>>> a <- c(0.1, 0.2) >>>>>> b <- c(0.2, 0.8) >>>>>> mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), >>>>>> MoreArgs = list(s = 1, n = 2, m = 5), a, b) >>>>>> #> $RandVecOutput >>>>>> #> [,1] [,2] [,3] [,4] [,5] >>>>>> #> [1,] 0.2004363 0.1552328 0.2391742 0.1744857 0.1949236 >>>>>> #> [2,] 0.1995637 0.2447672 0.1608258 0.2255143 0.2050764 >>>>>> #> >>>>>> #> $RandVecOutput >>>>>> #> [,1] [,2] [,3] [,4] [,5] >>>>>> #> [1,] 0.2157416 0.4691191 0.5067447 0.7749258 0.7728955 >>>>>> #> [2,] 0.7842584 0.5308809 0.4932553 0.2250742 0.2271045 >>>>>> >>>>>> >>>>>> Hope this helps, >>>>>> >>>>>> Rui Barradas >>>>>> >>>>>> >>>>> >>>>> >>>>> -- >>>>> Este e-mail foi analisado pelo software antiv?rus AVG para verificar a presen?a de v?rus. >>>>> www.avg.com >>> Hello, >>> >>> The two blocks of res are the two random matrices, one for each >>> combination of (a,b). mapply passes each of the values in its arguments >>> list (the ellipses in the help page) and computes the anonymous function >>> with the pairs (a[1], b[1]), (a[2], b[2]). >>> >>> Since a and b are two elements vectors the output res is a two members >>> named list. Your error is to compare the result of apply(res2, 1, min) >>> to a, when you should compare to a[2]. See the code below. >>> >>> >>> library(Surrogate) >>> a <- c(0.015, 0.005) >>> b <- c(0.070, 0.045) >>> set.seed(2025) >>> res <- mapply(\(a, b, s, n, m) RandVec(a, b, s, n, m), >>> MoreArgs = list(s = 0.05528650577311, n = 2, m = 10000), >>> a, b) >>> >>> res1 = res[[1]] >>> res2 = res[[2]] >>> >>> # first check that the sums are correct >>> # these sums should be s = 0.05528650577311, up to floating-point accuracy >>> lapply(res, \(x) colSums(x[, 1:5]) |> print(digits = 14L)) >>> #> [1] 0.05528650577311 0.05528650577311 0.05528650577311 0.05528650577311 >>> #> [5] 0.05528650577311 >>> #> [1] 0.05528650577311 0.05528650577311 0.05528650577311 0.05528650577311 >>> #> [5] 0.05528650577311 >>> #> $RandVecOutput >>> #> [1] 0.05528651 0.05528651 0.05528651 0.05528651 0.05528651 >>> #> >>> #> $RandVecOutput >>> #> [1] 0.05528651 0.05528651 0.05528651 0.05528651 0.05528651 >>> >>> # now check the min and max >>> apply(res1, 1, min) > a[1L] ## [1] TRUE TRUE >>> #> [1] TRUE TRUE >>> apply(res2, 1, min) > a[2L] ## [1] TRUE TRUE >>> #> [1] TRUE TRUE >>> >>> apply(res1, 1, max) < b[1L] ## [1] TRUE TRUE >>> #> [1] TRUE TRUE >>> apply(res2, 1, max) < b[2L] ## [1] TRUE TRUE >>> #> [1] TRUE TRUE >>> >>> >>> >>> Which one should you take as final simulation of the vector? Both. >>> The first matrix values are bounded by c(a[1], b[1]) with column sums >>> equal to s. >>> The second matrix values are bounded by c(a[2], b[2]) with column sums >>> also equal to s. >>> >>> Hoep this helps, >>> >>> Rui Barradas >>>