Nope. She would have wanted the 'each' argument = 84. See ?rep.
-- Bert
On Thu, Jun 13, 2024 at 3:54?PM Ebert,Timothy Aaron <tebert at ufl.edu>
wrote:
> Maybe this was your solution?
>
> blocC <- c(rep(x=c(1:13), times=84))
> blocC <- arrange(.data = data.frame(blocC), blocC)
>
> The second line sorts, but that may not be needed depending on
> application. The object class is also different in the sorted solution.
>
> Tim
> -----Original Message-----
> From: R-help <r-help-bounces at r-project.org> On Behalf Of Francesca
> PANCOTTO via R-help
> Sent: Thursday, June 13, 2024 2:22 PM
> To: r-help at r-project.org
> Subject: Re: [R] Create a numeric series in an efficient way
>
> [External Email]
>
> I apologize, I solved the problem, sorry for that.
> f.
>
>
>
> Il giorno gio 13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
> francesca.pancotto at unimore.it> ha scritto:
>
> > Dear Contributors
> > I am trying to create a numeric series with repeated numbers, not
> > difficult task, but I do not seem to find an efficient way.
> >
> > This is my solution
> >
> > blocB <- c(rep(x = 1, times = 84), rep(x = 2, times = 84), rep(x =
3,
> > times = 84), rep(x = 4, times = 84), rep(x = 5, times = 84), rep(x
> > 6, times = 84), rep(x = 7, times = 84), rep(x = 8, times = 84), rep(x
> > = 9, times = 84), rep(x = 10, times = 84), rep(x = 11, times = 84),
> > rep(x = 12, times = 84), rep(x = 13, times = 84))
> >
> > which works but it is super silly and I need to create different
> > variables similar to this, changing the value of the repetition, 84 in
> this case.
> > Thanks for any help.
> >
> >
> > F.
> >
>
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>
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