You could use a for loop in a brute force approach.
-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Rui Barradas
Sent: Sunday, August 6, 2023 7:37 PM
To: Iris Simmons <ikwsimmo at gmail.com>; Steven Yen <styen at
ntu.edu.tw>
Cc: R-help Mailing List <r-help at r-project.org>
Subject: Re: [R] Stacking matrix columns
[External Email]
?s 01:15 de 06/08/2023, Iris Simmons escreveu:> You could also do
>
> dim(x) <- c(length(x), 1)
>
> On Sat, Aug 5, 2023, 20:12 Steven Yen <styen at ntu.edu.tw> wrote:
>
>> I wish to stack columns of a matrix into one column. The following
>> matrix command does it. Any other ways? Thanks.
>>
>> > x<-matrix(1:20,5,4)
>> > x
>> [,1] [,2] [,3] [,4]
>> [1,] 1 6 11 16
>> [2,] 2 7 12 17
>> [3,] 3 8 13 18
>> [4,] 4 9 14 19
>> [5,] 5 10 15 20
>>
>> > matrix(x,ncol=1)
>> [,1]
>> [1,] 1
>> [2,] 2
>> [3,] 3
>> [4,] 4
>> [5,] 5
>> [6,] 6
>> [7,] 7
>> [8,] 8
>> [9,] 9
>> [10,] 10
>> [11,] 11
>> [12,] 12
>> [13,] 13
>> [14,] 14
>> [15,] 15
>> [16,] 16
>> [17,] 17
>> [18,] 18
>> [19,] 19
>> [20,] 20
>> >
>>
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Hello,
Yet another solution.
t(t(c(x)))
or
x |> c() |> t() |> t()
At first I liked it but it's the slowest of the three, OP's, Iris'
(the fastest).
Hope this helps,
Rui Barradas
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