Hi Bert,
I am too old for school.
On Tue, Apr 26, 2022 at 5:41 PM Bert Gunter <bgunter.4567 at gmail.com>
wrote:>
> Sounds like homework. We try not to do homework here. See the posting
> guide linked below for details. (If not homework, let us know).
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip
)
>
> On Tue, Apr 26, 2022 at 3:17 PM Val <valkremk at gmail.com> wrote:
> >
> > Hi All,
> >
> > I want to flag a record based on the following condition.
> > The variables in the sample data are
> > State, name, day, text, ddate
> >
> > Sort the data by State, name, day ddate,
> >
> > Within State, name, day
> > assign consecutive number for each row
> > find the date difference between consecutive rows,
> > if the difference is less than 50 days and the text string in
> > previous and current rows are the same then flag the record as X,
> > otherwise Y.
> >
> > Here is sample data and my attempt,
> >
> > DF<-read.table(text="State name day text ddate
> > CA A 1 xch 2014/09/16
> > CA A 2 xck 2015/5/29
> > CA A 2 xck 2015/6/18
> > CA A 2 xcm 2015/8/3
> > CA A 2 xcj 2015/8/26
> > FL B 3 xcu 2017/7/23
> > FL B 3 xcl 2017/7/03
> > FL B 3 xmc 2017/7/26
> > FL B 3 xca 2017/3/17
> > FL B 3 xcb 2017/4/8
> > FL B 4 xhh 2017/3/17
> > FL B 4 xhh 2017/1/29",header=TRUE)
> >
> > DF$ddate <- as.Date (as.Date(DF$ddate),
format="%Y/%m/%d" )
> > DF3 <- DF[order(DF$State,DF$name,DF$day,xtfrm(DF$ddate)),
]
> > DF3$C <- with(DF3, ave(State, name, day, FUN = seq_along))
> > DF3$diff <- with(DF3, ave(as.integer(ddate), State, name, day,
> > FUN = function(x) x - x[1]))
> >
> > I stopped here, how do I evaluate the previous and the current rows
> > text string and date difference?
> >
> > Desired result,
> >
> >
> > State name day text ddate C diff flag
> > 1 CA A 1 xch 2014-09-16 1 0 y
> > 2 CA A 2 xck 2015-05-29 1 0 y
> > 3 CA A 2 xck 2015-06-18 2 20 x
> > 4 CA A 2 xcm 2015-08-03 3 66 y
> > 5 CA A 2 xcj 2015-08-26 4 89 y
> > 9 FL B 3 xca 2017-03-17 1 0 y
> > 10 FL B 3 xcb 2017-04-08 2 22 y
> > 7 FL B 3 xcl 2017-07-03 3 108 y
> > 6 FL B 3 xcu 2017-07-23 4 128 y
> > 8 FL B 3 xmc 2017-07-26 5 131 y
> > 12 FL B 4 xhh 2017-01-29 1 0 y
> > 11 FL B 4 xhh 2017-03-17 2 47 x
> >
> >
> >
> > Thank you,
> >
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