R help - Apr 2022 - "apply" a function that takes two or more vectors as arguments, such as cor(x, y), over a "category" or "grouping variable" or "index"?

Hello,

Another option is ?by.


by(my_df[-1], my_df$my_category, cor)
by(my_df[-1], my_df$my_category, \(x) cor(x)[1,2])


Hope this helps,

Rui Barradas

?s 02:26 de 09/04/2022, Kelly Thompson escreveu:
> #Q. How can I "apply" a function that takes two or more vectors
as
> arguments, such as cor(x, y), over a "category" or "grouping
variable"
> or "index"?
> #I'm using cor() as an example, I'd like to find a way to do this
for
> any function that takes 2 or more vectors as arguments.
> 
> 
> #create example data
> 
> my_category <- rep ( c("a","b","c"),  4)
> 
> set.seed(12345)
> my_x <- rnorm(12)
> 
> set.seed(54321)
> my_y <- rnorm(12)
> 
> my_df <- data.frame(my_category, my_x, my_y)
> 
> #review data
> my_df
> 
> #If i wanted to get the correlation of x and y grouped by category, I
> could use this code and loop:
> 
> my_category_unique <- unique(my_category)
> 
> my_results <- vector("list", length(my_category_unique) )
> names(my_results) <- my_category_unique
> 
> #start i loop
>    for (i in 1:length(my_category_unique) ) {
>      my_criteria_i <- my_category == my_category_unique[i]
>      my_x_i <- my_x[which(my_criteria_i)]
>      my_y_i <- my_y[which(my_criteria_i)]
>      my_correl_i <- cor(x = my_x_i, y = my_y_i)
>      my_results[i] <- list(my_correl_i)
> } # end i loop
> 
> #review results
> my_results
> 
> #Q. Is there a better or more "elegant" way to do this, using
by(),
> aggregate(), apply(), or some other function?
> 
> #This does not work and results in this error message: "Error in
> FUN(dd[x, ], ...) : incompatible dimensions"
> by (data = my_x, INDICES = my_category, FUN = cor, y = my_y)
> 
> #This does not work and results in this error message: "Error in
> cor(my_df$x, my_df$y) : ... supply both 'x' and 'y' or a
matrix-like
> 'x' "
> by (data = my_df, INDICES = my_category, FUN = function(x, y) { cor
> (my_df$x, my_df$y) } )
> 
> 
> #if I wanted the mean of x by category, I could use by() or aggregate():
> by (data = my_x, INDICES = my_category, FUN = mean)
> 
> aggregate(x = my_x, by = list(my_category), FUN = mean)
> 
> #Thanks!
> 
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Thanks. I have a clarification and a follow-up question. I should have
asked this in the original post, and I should have provided a better
example for the FUN argument, I apologize.

For use in an example, here is a "silly" example of a function that
requires arguments such as x and y to be "separately assigned" :

udf_x_plus_y <- function (x, y) { return ( x + y) }

Q. Is there a way to use by() when the argument of FUN is a function
that requires arguments such as "x" and "y" to be separately
assigned
(ex. udf_x_plus_y (x = my_x , y = my_y ), rather than assigned as a
range of columns using brackets (ex. cor(x)[1,2]) ?

Something like this perhaps? (This produces an error message.)
by( data = my_df[-1], INDICES = my_df$my_category,  FUN = function(x,
y) { udf_x_plus_y (x = data$my_x, y = data$my_y) } )

Thanks again.

On Sat, Apr 9, 2022 at 5:32 AM Rui Barradas <ruipbarradas at sapo.pt>
wrote:
>
> Hello,
>
> Another option is ?by.
>
>
> by(my_df[-1], my_df$my_category, cor)
> by(my_df[-1], my_df$my_category, \(x) cor(x)[1,2])
>
>
> Hope this helps,
>
> Rui Barradas
>
> ?s 02:26 de 09/04/2022, Kelly Thompson escreveu:
> > #Q. How can I "apply" a function that takes two or more
vectors as
> > arguments, such as cor(x, y), over a "category" or
"grouping variable"
> > or "index"?
> > #I'm using cor() as an example, I'd like to find a way to do
this for
> > any function that takes 2 or more vectors as arguments.
> >
> >
> > #create example data
> >
> > my_category <- rep ( c("a","b","c"), 
4)
> >
> > set.seed(12345)
> > my_x <- rnorm(12)
> >
> > set.seed(54321)
> > my_y <- rnorm(12)
> >
> > my_df <- data.frame(my_category, my_x, my_y)
> >
> > #review data
> > my_df
> >
> > #If i wanted to get the correlation of x and y grouped by category, I
> > could use this code and loop:
> >
> > my_category_unique <- unique(my_category)
> >
> > my_results <- vector("list", length(my_category_unique) )
> > names(my_results) <- my_category_unique
> >
> > #start i loop
> >    for (i in 1:length(my_category_unique) ) {
> >      my_criteria_i <- my_category == my_category_unique[i]
> >      my_x_i <- my_x[which(my_criteria_i)]
> >      my_y_i <- my_y[which(my_criteria_i)]
> >      my_correl_i <- cor(x = my_x_i, y = my_y_i)
> >      my_results[i] <- list(my_correl_i)
> > } # end i loop
> >
> > #review results
> > my_results
> >
> > #Q. Is there a better or more "elegant" way to do this,
using by(),
> > aggregate(), apply(), or some other function?
> >
> > #This does not work and results in this error message: "Error in
> > FUN(dd[x, ], ...) : incompatible dimensions"
> > by (data = my_x, INDICES = my_category, FUN = cor, y = my_y)
> >
> > #This does not work and results in this error message: "Error in
> > cor(my_df$x, my_df$y) : ... supply both 'x' and 'y' or
a matrix-like
> > 'x' "
> > by (data = my_df, INDICES = my_category, FUN = function(x, y) { cor
> > (my_df$x, my_df$y) } )
> >
> >
> > #if I wanted the mean of x by category, I could use by() or
aggregate():
> > by (data = my_x, INDICES = my_category, FUN = mean)
> >
> > aggregate(x = my_x, by = list(my_category), FUN = mean)
> >
> > #Thanks!
> >
> > ______________________________________________
> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.