Bert Gunter
2021-Oct-14 17:17 UTC
[R] how to do inverse log of every value in every column in data frame
As all of your columns are numeric, you should probably convert your df to a matrix. Then use exp() on that, of course: exp(as.matrix(b)) see ?exp Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Oct 14, 2021 at 10:10 AM Ana Marija <sokovic.anamarija at gmail.com> wrote:> Hi All, > > I have a data frame like this: > > > head(b) > LRET02 LRET04 LRET06 LRET08 LRET10 LRET12 LRET14 > 1 0 0.6931472 . 1.0986123 1.0986123 1.0986123 0.6931472 > 2 2.1972246 2.4849066 2.4849066 . 2.5649494 2.6390573 2.6390573 > 3 1.6094379 1.7917595 1.6094379 1.7917595 2.0794415 1.9459101 2.0794415 > 4 0 0 0 0 0 0 0 > 5 0.6931472 0 1.0986123 1.0986123 0.6931472 0.6931472 0.6931472 > 6 1.0986123 1.0986123 1.0986123 0.6931472 1.0986123 1.3862944 1.0986123 > > All values in this data frame are product of natural log. I have to do > inverse of it. > So for example do do inverse of 0.6931472 I would do: > > 2.718281828^0.6931472 > [1] 2 > > How do I perform this operation for every single value in this data frame? > > The original data frame is this dimension: > > dim(b) > [1] 1441 18 > > Thanks > Ana > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
Ana Marija
2021-Oct-14 17:23 UTC
[R] how to do inverse log of every value in every column in data frame
Thank you so much! On Thu, Oct 14, 2021 at 12:17 PM Bert Gunter <bgunter.4567 at gmail.com> wrote:> As all of your columns are numeric, you should probably convert your df to > a matrix. Then use exp() on that, of course: > exp(as.matrix(b)) > > see ?exp > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along and > sticking things into it." > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > On Thu, Oct 14, 2021 at 10:10 AM Ana Marija <sokovic.anamarija at gmail.com> > wrote: > >> Hi All, >> >> I have a data frame like this: >> >> > head(b) >> LRET02 LRET04 LRET06 LRET08 LRET10 LRET12 LRET14 >> 1 0 0.6931472 . 1.0986123 1.0986123 1.0986123 0.6931472 >> 2 2.1972246 2.4849066 2.4849066 . 2.5649494 2.6390573 2.6390573 >> 3 1.6094379 1.7917595 1.6094379 1.7917595 2.0794415 1.9459101 2.0794415 >> 4 0 0 0 0 0 0 0 >> 5 0.6931472 0 1.0986123 1.0986123 0.6931472 0.6931472 0.6931472 >> 6 1.0986123 1.0986123 1.0986123 0.6931472 1.0986123 1.3862944 1.0986123 >> >> All values in this data frame are product of natural log. I have to do >> inverse of it. >> So for example do do inverse of 0.6931472 I would do: >> > 2.718281828^0.6931472 >> [1] 2 >> >> How do I perform this operation for every single value in this data frame? >> >> The original data frame is this dimension: >> > dim(b) >> [1] 1441 18 >> >> Thanks >> Ana >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >[[alternative HTML version deleted]]