Andrew Simmons
2021-Sep-02 19:10 UTC
[R] Calculate daily means from 5-minute interval data
You could use 'split' to create a list of data frames, and then apply a
function to each to get the means and sds.
cols <- "cfs" # add more as necessary
S <- split(discharge[cols], format(discharge$sampdate, format =
"%Y-%m"))
means <- do.call("rbind", lapply(S, colMeans, na.rm = TRUE))
sds <- do.call("rbind", lapply(S, function(xx) sapply(xx, sd,
na.rm TRUE)))
On Thu, Sep 2, 2021 at 3:01 PM Rich Shepard <rshepard at appl-ecosys.com>
wrote:
> On Thu, 2 Sep 2021, Rich Shepard wrote:
>
> > If I correctly understand the output of as.POSIXlt each date and time
> > element is separate, so input such as 2016-03-03 12:00 would now be
2016
> 03
> > 03 12 00 (I've not read how the elements are separated). (The TZ
is not
> > important because all data are either PST or PDT.)
>
> Using this script:
> discharge <- read.csv('../data/water/discharge.dat', header =
TRUE, sep > ',', stringsAsFactors = FALSE)
> discharge$sampdate <- as.POSIXlt(discharge$sampdate, tz = "",
> format = '%Y-%m-%d %H:%M',
> optional = 'logical')
> discharge$cfs <- as.numeric(discharge$cfs, length = 6)
>
> I get this result:
> > head(discharge)
> sampdate cfs
> 1 2016-03-03 12:00:00 149000
> 2 2016-03-03 12:10:00 150000
> 3 2016-03-03 12:20:00 151000
> 4 2016-03-03 12:30:00 156000
> 5 2016-03-03 12:40:00 154000
> 6 2016-03-03 12:50:00 150000
>
> I'm completely open to suggestions on using this output to calculate
> monthly
> means and sds.
>
> If dplyr:summarize() will do so please show me how to modify this command:
> disc_monthly <- ( discharge
> %>% group_by(sampdate)
> %>% summarize(exp_value = mean(cfs, na.rm = TRUE))
> because it produces daily means, not monthly means.
>
> TIA,
>
> Rich
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
On Thu, 2 Sep 2021, Andrew Simmons wrote:> You could use 'split' to create a list of data frames, and then apply a > function to each to get the means and sds. > > cols <- "cfs" # add more as necessary > S <- split(discharge[cols], format(discharge$sampdate, format = "%Y-%m")) > means <- do.call("rbind", lapply(S, colMeans, na.rm = TRUE)) > sds <- do.call("rbind", lapply(S, function(xx) sapply(xx, sd, na.rm > TRUE)))Andrew, Thank you for the valuable lesson. This is new to me and I know I'll have use for it in the future, too. Much appreciated! Stay well, Rich
Jeff Newmiller
2021-Sep-02 19:40 UTC
[R] Calculate daily means from 5-minute interval data
Regardless of whether you use the lower-level split function, or the
higher-level aggregate function, or the tidyverse group_by function, the key is
learning how to create the column that is the same for all records corresponding
to the time interval of interest.
If you convert the sampdate to POSIXct, the tz IS important, because most of us
use local timezones that respect daylight savings time, and a naive conversion
of standard time will run into trouble if R is assuming daylight savings time
applies. The lubridate package gets around this by always assuming UTC and
giving you a function to "fix" the timezone after the conversion. I
prefer to always be specific about timezones, at least by using so something
like
Sys.setenv( TZ = "Etc/GMT+8" )
which does not respect daylight savings.
Regarding using character data for identifying the month, in order to have clean
plots of the data I prefer to use the trunc function but it returns a POSIXlt so
I convert it to POSIXct:
discharge$sampmonthbegin <- as.POSIXct( trunc( discharge$sampdate, units
= "months" ) )
Then any of various ways can be used to aggregate the records by that column.
On September 2, 2021 12:10:15 PM PDT, Andrew Simmons <akwsimmo at
gmail.com> wrote:>You could use 'split' to create a list of data frames, and then
apply a
>function to each to get the means and sds.
>
>
>cols <- "cfs" # add more as necessary
>S <- split(discharge[cols], format(discharge$sampdate, format =
"%Y-%m"))
>means <- do.call("rbind", lapply(S, colMeans, na.rm = TRUE))
>sds <- do.call("rbind", lapply(S, function(xx) sapply(xx, sd,
na.rm >TRUE)))
>
>On Thu, Sep 2, 2021 at 3:01 PM Rich Shepard <rshepard at
appl-ecosys.com>
>wrote:
>
>> On Thu, 2 Sep 2021, Rich Shepard wrote:
>>
>> > If I correctly understand the output of as.POSIXlt each date and
time
>> > element is separate, so input such as 2016-03-03 12:00 would now
be 2016
>> 03
>> > 03 12 00 (I've not read how the elements are separated). (The
TZ is not
>> > important because all data are either PST or PDT.)
>>
>> Using this script:
>> discharge <- read.csv('../data/water/discharge.dat', header
= TRUE, sep >> ',', stringsAsFactors = FALSE)
>> discharge$sampdate <- as.POSIXlt(discharge$sampdate, tz =
"",
>> format = '%Y-%m-%d %H:%M',
>> optional = 'logical')
>> discharge$cfs <- as.numeric(discharge$cfs, length = 6)
>>
>> I get this result:
>> > head(discharge)
>> sampdate cfs
>> 1 2016-03-03 12:00:00 149000
>> 2 2016-03-03 12:10:00 150000
>> 3 2016-03-03 12:20:00 151000
>> 4 2016-03-03 12:30:00 156000
>> 5 2016-03-03 12:40:00 154000
>> 6 2016-03-03 12:50:00 150000
>>
>> I'm completely open to suggestions on using this output to
calculate
>> monthly
>> means and sds.
>>
>> If dplyr:summarize() will do so please show me how to modify this
command:
>> disc_monthly <- ( discharge
>> %>% group_by(sampdate)
>> %>% summarize(exp_value = mean(cfs, na.rm = TRUE))
>> because it produces daily means, not monthly means.
>>
>> TIA,
>>
>> Rich
>>
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> [[alternative HTML version deleted]]
>
>______________________________________________
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
--
Sent from my phone. Please excuse my brevity.