On 14/07/2021 6:00 a.m., G?ran Brostr?m wrote:> I wonder about the last sentence in the Details section of the
> documentation of 'weighted.mean':
>
> "However, zero weights _are_ handled specially and the corresponding
?x?
> values are omitted from the sum."
>
> The return value of weighted.mean.default is
>
> sum((x * w)[w != 0])/sum(w)
>
> and indeed, it looks as if zero weights are getting special treatment,
> but what is wrong with the alternative (equivalent?) expression
>
> sum(x * w) / sum(w)?
>
> Is it a good idea to remove zeros from a vector before applying
'sum' to
> it? I don't think so. Anyway, the sentence in the documentation seems
to
> be uncalled for.
Inf*0 is not zero. Setting weights to zero on infinite observations (or
NA, or NaN) will give different results in your two expressions.
Duncan Murdoch