SITI AISYAH ZAKARIA
2021-Jul-08 23:59 UTC
[R] How to estimate the parameter for many variable?
Dear all, Thank you very much for the feedback. Sorry for the lack of information about this problem. Here, I explain again. I use this package to run my coding. library(ismev) library(mgcv) library(nlme) The purpose of this is I want to get the value of parameter estimation using MLE by applying the GEV distribution. x <- data.matrix(Ozone_weekly2) x refers to my data that consists of 19 variables. I will attach the data together. x head(gev.fit)[1:4] ti = matrix(ncol = 3, nrow = 888) ti[,1] = seq(1, 888, 1) ti[,2]=sin(2*pi*(ti[,1])/52) ti[,3]=cos(2*pi*(ti[,1])/52) *for(i in 1:nrow(x)) + { for(j in 1:ncol(x)) the problem in here, i don't no to create the coding. i target my output will come out in matrix that + {x[i,j] = 1}} show the parameter estimation for 19 variable which have 19 row and 3 column* * row -- refer to variable (station) ; column -- refer to parameter estimation for GEV distribution*thank you. On Thu, 8 Jul 2021 at 18:40, Rui Barradas <ruipbarradas at sapo.pt> wrote:> Hello, > > Also, in the code > > x <- data.matrix(Ozone_weekly) > > [...omited...] > > for(i in 1:nrow(x)) > + { for(j in 1:ncol(x)) > + {x[i,j] = 1}} > > not only you rewrite x but the double for loop is equivalent to > > > x[] <- 1 > > > courtesy R's vectorised behavior. (The square parenthesis are needed to > keep the dimensions, the matrix form.) > And, I'm not sure but isn't > > head(gev.fit)[1:4] > > equivalent to > > head(gev.fit, n = 4) > > ? > > Like Jim says, we need more information, can you post Ozone_weekly2 and > the code that produced gev.fit? But in the mean time you can revise your > code. > > Hope this helps, > > Rui Barradas > > > ?s 11:08 de 08/07/21, Jim Lemon escreveu: > > Hi Siti, > > I think we need a bit more information to respond helpfully. I have no > > idea what "Ozone_weekly2" is and Google is also ignorant. "gev.fit" is > > also unknown. The name suggests that it is the output of some > > regression or similar. What function produced it, and from what > > library? "ti" is known as you have defined it. However, I don't know > > what you want to do with it. Finally, as this is a text mailing list, > > we don't get any highlighting, so the text to which you refer cannot > > be identified. I can see you have a problem, but cannot offer any help > > right now. > > > > Jim > > > > On Thu, Jul 8, 2021 at 12:06 AM SITI AISYAH ZAKARIA > > <aisyahzakaria at unimap.edu.my> wrote: > >> > >> Dear all, > >> > >> Can I ask something about programming in marginal distribution for > spatial > >> extreme? > >> I really stuck on my coding to obtain the parameter estimation for > >> univariate or marginal distribution for new model in spatial extreme. > >> > >> I want to run my data in order to get the parameter estimation value > for 25 > >> stations in one table. But I really didn't get the idea of the correct > >> coding. Here I attached my coding > >> > >> x <- data.matrix(Ozone_weekly2) > >> x > >> head(gev.fit)[1:4] > >> ti = matrix(ncol = 3, nrow = 888) > >> ti[,1] = seq(1, 888, 1) > >> ti[,2]=sin(2*pi*(ti[,1])/52) > >> ti[,3]=cos(2*pi*(ti[,1])/52) > >> for(i in 1:nrow(x)) > >> + { for(j in 1:ncol(x)) > >> + {x[i,j] = 1}} > >> > >> My problem is highlighted in red color. > >> And if are not hesitate to all. Can someone share with me the procedure, > >> how can I map my data using spatial extreme. > >> For example: > >> After I finish my marginal distribution, what the next procedure. It is > I > >> need to get the spatial independent value. > >> > >> That's all > >> Thank you. > >> > >> -- > >> > >> > >> > >> > >> > >> "..Millions of trees are used to make papers, only to be thrown away > >> after a couple of minutes reading from them. Our planet is at stake. > Please > >> be considerate. THINK TWICE BEFORE PRINTING THIS.." > >> > >> DISCLAIMER: This email \ and any files transmitte...{{dropped:24}} > >> > >> ______________________________________________ > >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > >-- "..Millions of trees are used to make papers, only to be thrown away after a couple of minutes reading from them. Our planet is at stake. Please be considerate. THINK TWICE BEFORE PRINTING THIS.." DISCLAIMER:?This email and any files transmitted with it are confidential and intended solely for the use of the individual orentity to whom they are addressed. If you have received this email in error please notify the UniMAP's Email Administrator. Please note that any views or opinions presented in this email are solely those of the author and do not necessarily represent those of the university. Finally, the recipient should check this email and any attachments for the presence of viruses.The university accepts no liability for any damage caused by any virus transmitted by this email. Universiti Malaysia Perlis (UniMAP) | Digital Management & Development Centre (DMDC), Universiti Malaysia Perlis (UniMAP), Pauh Putra Campus, 02600 Arau, Perlis, MALAYSIA |?www.unimap.edu.my <http://www.unimap.edu.my/> -------------- next part -------------- An embedded and charset-unspecified text was scrubbed... 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Hello, The following lapply one-liner fits a GEV to each column vector, there is no need for the double for loop. There's also no need to create a data set x. library(ismev) library(mgcv) library(EnvStats) Ozone_weekly2 <- read.table("~/tmp/Ozone_weekly2.txt", header = TRUE) # fit a GEV to each column gev_fit_list <- lapply(Ozone_weekly2, gev.fit, show = FALSE) # extract the parameters MLE estimates mle_params <- t(sapply(gev_fit_list, '[[', 'mle')) # assign column names colnames(mle_params) <- c("location", "scale", "shape") # see first few rows head(mle_params) The OP doesn't ask for plots but, here they go. y_vals <- function(x, params){ loc <- params[1] scale <- params[2] shape <- params[3] EnvStats::dgevd(x, loc, scale, shape) } plot_fit <- function(data, vec, verbose = FALSE){ fit <- gev.fit(data[[vec]], show = verbose) x <- sort(data[[vec]]) hist(x, freq = FALSE) lines(x, y_vals(x, params = fit$mle)) } # seems a good fit plot_fit(Ozone_weekly2, 1) # column number plot_fit(Ozone_weekly2, "CA01") # col name, equivalent # the data seems gaussian, not a good fit plot_fit(Ozone_weekly2, 4) # column number plot_fit(Ozone_weekly2, "CA08") # col name, equivalent Hope this helps, Rui Barradas ?s 00:59 de 09/07/21, SITI AISYAH ZAKARIA escreveu:> Dear all, > > Thank you very?much for the feedback. > > Sorry for the lack of information about this problem. > > Here, I explain?again. > > I use this package to run my coding. > > library(ismev) > library(mgcv) > library(nlme) > > The purpose?of this is I want to get the value of parameter estimation > using MLE by applying?the GEV distribution. > > x <- data.matrix(Ozone_weekly2)? ? ? ? ? ? ? ? ? ? ? x refers to my data > that consists of 19 variables. I will attach the data together. > x > head(gev.fit)[1:4] > ti = matrix(ncol = 3, nrow = 888) > ti[,1] = seq(1, 888, 1) > ti[,2]=sin(2*pi*(ti[,1])/52) > ti[,3]=cos(2*pi*(ti[,1])/52) > > /for(i in 1:nrow(x)) > ? + { for(j in 1:ncol(x))? ? ? ? ? ? ? ? ? ? ? ? ? ? the problem in > here, i don't no to create the coding. i target my output?will come out > in matrix that > ? ? + {x[i,j] = 1}}? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?show the > parameter estimation for 19 variable which have 19 row and 3 column/ > /? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? row -- > refer to variable (station)? ; column -- refer to parameter estimation > for GEV distribution > > /thank you. > > On Thu, 8 Jul 2021 at 18:40, Rui Barradas <ruipbarradas at sapo.pt > <mailto:ruipbarradas at sapo.pt>> wrote: > > Hello, > > Also, in the code > > x <- data.matrix(Ozone_weekly) > > [...omited...] > > for(i in 1:nrow(x)) > ? ?+ { for(j in 1:ncol(x)) > ? ? ?+ {x[i,j] = 1}} > > not only you rewrite x but the double for loop is equivalent to > > > x[] <- 1 > > > courtesy R's vectorised behavior. (The square parenthesis are needed to > keep the dimensions, the matrix form.) > And, I'm not sure but isn't > > head(gev.fit)[1:4] > > equivalent to > > head(gev.fit, n = 4) > > ? > > Like Jim says, we need more information, can you post Ozone_weekly2 and > the code that produced gev.fit? But in the mean time you can revise > your > code. > > Hope this helps, > > Rui Barradas > > > ?s 11:08 de 08/07/21, Jim Lemon escreveu: > > Hi Siti, > > I think we need a bit more information to respond helpfully. I > have no > > idea what "Ozone_weekly2" is and Google is also ignorant. > "gev.fit" is > > also unknown. The name suggests that it is the output of some > > regression or similar. What function produced it, and from what > > library? "ti" is known as you have defined it. However, I don't know > > what you want to do with it. Finally, as this is a text mailing list, > > we don't get any highlighting, so the text to which you refer cannot > > be identified. I can see you have a problem, but cannot offer any > help > > right now. > > > > Jim > > > > On Thu, Jul 8, 2021 at 12:06 AM SITI AISYAH ZAKARIA > > <aisyahzakaria at unimap.edu.my > <mailto:aisyahzakaria at unimap.edu.my>> wrote: > >> > >> Dear all, > >> > >> Can I ask something about programming in marginal distribution > for spatial > >> extreme? > >> I really stuck on my coding to obtain the parameter estimation for > >> univariate or marginal distribution for new model in spatial > extreme. > >> > >> I want to run my data in order to get the parameter estimation > value for 25 > >> stations in one table. But I really didn't get the idea of the > correct > >> coding. Here I attached my coding > >> > >> x <- data.matrix(Ozone_weekly2) > >> x > >> head(gev.fit)[1:4] > >> ti = matrix(ncol = 3, nrow = 888) > >> ti[,1] = seq(1, 888, 1) > >> ti[,2]=sin(2*pi*(ti[,1])/52) > >> ti[,3]=cos(2*pi*(ti[,1])/52) > >> for(i in 1:nrow(x)) > >>? ? + { for(j in 1:ncol(x)) > >>? ? ? + {x[i,j] = 1}} > >> > >> My problem is highlighted in red color. > >> And if are not hesitate to all. Can someone share with me the > procedure, > >> how can I map my data using spatial extreme. > >> For example: > >> After I finish my marginal distribution, what the next > procedure. It is I > >> need to get the spatial independent value. > >> > >> That's all > >> Thank you. > >> > >> -- > >> > >> > >> > >> > >> > >> "..Millions of trees are used to make papers, only to be thrown away > >> after a couple of minutes reading from them. Our planet is at > stake. Please > >> be considerate. THINK TWICE BEFORE PRINTING THIS.." > >> > >> DISCLAIMER: This email \ and any files transmitte...{{dropped:24}} > >> > >> ______________________________________________ > >> R-help at r-project.org <mailto:R-help at r-project.org> mailing list > -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > <https://stat.ethz.ch/mailman/listinfo/r-help> > >> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > <http://www.R-project.org/posting-guide.html> > >> and provide commented, minimal, self-contained, reproducible code. > > > > ______________________________________________ > > R-help at r-project.org <mailto:R-help at r-project.org> mailing list > -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > <https://stat.ethz.ch/mailman/listinfo/r-help> > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > <http://www.R-project.org/posting-guide.html> > > and provide commented, minimal, self-contained, reproducible code. > > > > > > "..Millions of trees are used to make papers, only to be thrown away > after a couple of minutes reading from them. Our planet is at stake. > Please be considerate. THINK TWICE BEFORE PRINTING THIS.." > > *DISCLAIMER:*?This email and any files transmitted with it are > confidential and intended solely for the use of the individual orentity > to whom they are addressed. If you have received this email in error > please notify the UniMAP's Email Administrator. Please note that any > views or opinions presented in this email are solely those of the author > and do not necessarily represent those of the university. Finally, the > recipient should check this email and any attachments for the presence > of viruses.The university accepts no liability for any damage caused by > any virus transmitted by this email. > > Universiti Malaysia Perlis (UniMAP) | Digital Management & Development > Centre (DMDC), Universiti Malaysia Perlis (UniMAP), Pauh Putra Campus, > 02600 Arau, Perlis, MALAYSIA | www.unimap.edu.my <http://www.unimap.edu.my/> >