Martin Møller Skarbiniks Pedersen
2021-Apr-24 21:17 UTC
[R] Still puzzled about different graph
Hi, Any ideas why I don't get the same graph out of p1 and p3? I have also posted it in the rstudio community without luck. https://community.rstudio.com/t/ggplot2-geom-path-in-a-loop/102716/2 library(ggplot2) df <- data.frame(x = c(0,25,0,-25,0), y = c(25,0,-25,0,25)) p1 <- ggplot() p1 <- p1 + geom_path(data = df,aes(x = x/1, y = y/1)) p1 <- p1 + geom_path(data = df,aes(x = x/2, y = y/2)) p1 <- p1 + xlim(-30,30) p1 <- p1 + ylim(-30,30) p1 df <- data.frame(x = c(0,25,0,-25,0), y = c(25,0,-25,0,25)) p3 <- ggplot() idx <- 1 p3 <- p3 + geom_path(data = df,aes(x = x/idx, y = y/idx)) idx <- 2 p3 <- p3 + geom_path(data = df,aes(x = x/idx, y = y/idx)) p3 <- p3 + xlim(-30,30) p3 <- p3 + ylim(-30,30) p3 [[alternative HTML version deleted]]
On 24/04/2021 5:17 p.m., Martin M?ller Skarbiniks Pedersen wrote:> Hi, > > Any ideas why I don't get the same graph out of p1 and p3? > > I have also posted it in the rstudio community without luck. > https://community.rstudio.com/t/ggplot2-geom-path-in-a-loop/102716/2 > > library(ggplot2) > > df <- data.frame(x = c(0,25,0,-25,0), y = c(25,0,-25,0,25)) > p1 <- ggplot() > p1 <- p1 + geom_path(data = df,aes(x = x/1, y = y/1)) > p1 <- p1 + geom_path(data = df,aes(x = x/2, y = y/2)) > p1 <- p1 + xlim(-30,30) > p1 <- p1 + ylim(-30,30) > p1 > > df <- data.frame(x = c(0,25,0,-25,0), y = c(25,0,-25,0,25)) > p3 <- ggplot() > idx <- 1 > p3 <- p3 + geom_path(data = df,aes(x = x/idx, y = y/idx)) > idx <- 2 > p3 <- p3 + geom_path(data = df,aes(x = x/idx, y = y/idx)) > p3 <- p3 + xlim(-30,30) > p3 <- p3 + ylim(-30,30) > p3 >I don't know where it says this in the docs, but generally speaking ggplot2 graphs don't evaluate everything until you print them. So I'd expect p3's two geom_path components to be identical, even though you changed idx. I think you can force evaluation before printing (using ggplot_build), but I don't think you can modify the graph after that, so you'll need two different variables instead of changing idx. Duncan Murdoch