Just re-read your question and realized I misread the error message. The argument is of zero length. But the conclusion is the same, either a bug in the package, or a problem with your input. On Fri, Aug 21, 2020 at 4:16 PM Abby Spurdle <spurdle.a at gmail.com> wrote:> > Note that I'm not familiar with this package or the method. > Also note that you haven't told anyone what function you're using, or > what your call was. > > I'm assuming that you're using the rotationForest() function. > According to its help page, the default is: > > K = round(ncol(x)/3, 0) > > There's no reason why the default K value should be higher than the > number of columns, unless: > (1) There's a bug with the package; or > (2) There's a problem with your input. > > I note that the package is only version 0.1.3, so a bug is not out of > the question. > Also, I'm a little surprised the author didn't use integer division: > > K = ncol (x) %/% 3 > > You could just set K to the above value, and see what happens... > > > On Fri, Aug 21, 2020 at 1:06 PM Sparks, John <jspark4 at uic.edu> wrote: > > > > Hi R Helpers, > > > > I wanted to try the rotationForest package. > > > > I pointed it at my data set and got the error message "Error in if (K >= ncol(x)) stop("K should not be greater than or equal to the number of columns in x") : > > argument is of length zero'. > > > > My dataset has 3688 obs. of 111 variables. > > > > Would a quick adjustment to the default value of K resolve this? > > > > If anybody with more experience with the package than me has a general suggestion I would appreciate it. > > > > --John Spaarks > > > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code.
On 2020-08-21 16:22 +1200, Abby Spurdle wrote:
| On Fri, Aug 21, 2020 at 4:16 PM Abby Spurdle <spurdle.a at gmail.com>
wrote:
| | On Fri, Aug 21, 2020 at 1:06 PM Sparks, John <jspark4 at uic.edu>
wrote:
| | |
| | | Hi R Helpers,
| | |
| | | I wanted to try the rotationForest
| | | package.
| | |
| | | I pointed it at my data set and
| | | got the error message "Error in if
| | | (K >= ncol(x)) stop("K should not
| | | be greater than or equal to the
| | | number of columns in x") :
| | | argument is of length zero'.
| | |
| | | My dataset has 3688 obs. of 111 variables.
| | |
| | | Would a quick adjustment to the
| | | default value of K resolve this?
| | |
| | | If anybody with more experience
| | | with the package than me has a
| | | general suggestion I would
| | | appreciate it.
| |
| | Note that I'm not familiar with this
| | package or the method. Also note
| | that you haven't told anyone what
| | function you're using, or what your
| | call was.
| |
| | I'm assuming that you're using the
| | rotationForest() function.
| | According to its help page, the
| | default is:
| |
| | K = round(ncol(x)/3, 0)
| |
| | There's no reason why the default K
| | value should be higher than the
| | number of columns, unless:
| | (1) There's a bug with the package; or
| | (2) There's a problem with your input.
| |
| | I note that the package is only
| | version 0.1.3, so a bug is not out
| | of the question. Also, I'm a little
| | surprised the author didn't use
| | integer division:
| |
| | K = ncol(x) %/% 3
| |
| | You could just set K to the above
| | value, and see what happens...
|
| Just re-read your question and
| realized I misread the error message.
| The argument is of zero length.
|
| But the conclusion is the same, either
| a bug in the package, or a problem
| with your input.
Dear John,
check to see if your columns only has
numbers in them like the *de jure* iris
dataset used in the example in
?rotationForest::rotationForest.
idx <- 1:100
idx.new <- which(!(1:nrow(iris) %in% idx))
y <- as.factor(ifelse(iris$Species[idx]=="setosa", 0, 1))
x <- iris[idx, -5]
newdata <- iris[idx.new, -5]
K <- ncol(x) %/% 3
L <- 100
rF <-
rotationForest::rotationForest(
x=x,
y=y,
K=K,
L=L)
predict(object=rF, newdata=newdata)
Best,
Rasmus
Thanks Abby and Rasumus.
I like to leave the solution on this list for the next potential person.
I had failed to realize that this package doesn't use one of the formula
forms. So my call of
RotFor2000<-rotationForest(up~.,data=modeldata)
is what caused the error.
After converting to the appropriate form
x<-subset(modeldata,select=-c(up))
y<-modeldata$up
tic()
RotFor2000<-rotationForest(x,y)
toc()
It ran just fine.
Thanks again.
--John Sparks
________________________________
From: Rasmus Liland <jral at posteo.no>
Sent: Friday, August 21, 2020 3:18 AM
To: Abby Spurdle <spurdle.a at gmail.com>
Cc: Sparks, John <jspark4 at uic.edu>; R-help <r-help at
r-project.org>
Subject: Re: [R] Rotation Forest Error Message
On 2020-08-21 16:22 +1200, Abby Spurdle wrote:
| On Fri, Aug 21, 2020 at 4:16 PM Abby Spurdle <spurdle.a at gmail.com>
wrote:
| | On Fri, Aug 21, 2020 at 1:06 PM Sparks, John <jspark4 at uic.edu>
wrote:
| | |
| | | Hi R Helpers,
| | |
| | | I wanted to try the rotationForest
| | | package.
| | |
| | | I pointed it at my data set and
| | | got the error message "Error in if
| | | (K >= ncol(x)) stop("K should not
| | | be greater than or equal to the
| | | number of columns in x") :
| | | argument is of length zero'.
| | |
| | | My dataset has 3688 obs. of 111 variables.
| | |
| | | Would a quick adjustment to the
| | | default value of K resolve this?
| | |
| | | If anybody with more experience
| | | with the package than me has a
| | | general suggestion I would
| | | appreciate it.
| |
| | Note that I'm not familiar with this
| | package or the method. Also note
| | that you haven't told anyone what
| | function you're using, or what your
| | call was.
| |
| | I'm assuming that you're using the
| | rotationForest() function.
| | According to its help page, the
| | default is:
| |
| | K = round(ncol(x)/3, 0)
| |
| | There's no reason why the default K
| | value should be higher than the
| | number of columns, unless:
| | (1) There's a bug with the package; or
| | (2) There's a problem with your input.
| |
| | I note that the package is only
| | version 0.1.3, so a bug is not out
| | of the question. Also, I'm a little
| | surprised the author didn't use
| | integer division:
| |
| | K = ncol(x) %/% 3
| |
| | You could just set K to the above
| | value, and see what happens...
|
| Just re-read your question and
| realized I misread the error message.
| The argument is of zero length.
|
| But the conclusion is the same, either
| a bug in the package, or a problem
| with your input.
Dear John,
check to see if your columns only has
numbers in them like the *de jure* iris
dataset used in the example in
?rotationForest::rotationForest.
idx <- 1:100
idx.new <- which(!(1:nrow(iris) %in% idx))
y <- as.factor(ifelse(iris$Species[idx]=="setosa", 0, 1))
x <- iris[idx, -5]
newdata <- iris[idx.new, -5]
K <- ncol(x) %/% 3
L <- 100
rF <-
rotationForest::rotationForest(
x=x,
y=y,
K=K,
L=L)
predict(object=rF, newdata=newdata)
Best,
Rasmus
[[alternative HTML version deleted]]