Hello everyone,
The following is a portion of coding that a colleague sent. Given my lack
of experience in R, I am not quite sure what the significance of the
following arguments. Could anyone help me translate? For context, I am
aware of the downloading portion of the script... library(data.table) etc.,
but am not familiar with the portion pertaining to an1 .
library(data.table)
anno = as.data.frame(fread(file
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/450K/mapper.txt", sep
="\t",
header = T))
meth = read.table(file
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/27K/GBM.txt", sep
="\t",
header = T, row.names = 1)
meth = as.matrix(meth)
""" the loop just formats the methylation column names to match
format"""
colnames(meth) = sapply(colnames(meth), function(i){
c1 = strsplit(i,split = '.', fixed = T)[[1]]
c1[4] = paste(strsplit(c1[4],split = "",fixed =
T)[[1]][1:2],collapse "")
paste(c1,collapse = ".")
})
exp = read.table(file
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/RNAseq/GBM.txt", sep =
"\t",
header = T, row.names = 1)
exp = as.matrix(exp)
c = intersect(colnames(exp),colnames(meth))
exp = exp[,c]
meth = meth[,c]
m = apply(meth, 1, function(i){
log2(i/(1-i))
})
m = t(as.matrix(m))
an = anno[anno$probe %in% rownames(m),]
an = an[an$gene %in% rownames(exp),]
an = an[an$location %in% c("TSS200","TSS1500"),]
p = apply(an,1,function(i){
tryCatch(summary(lm(exp[as.character(i[2]),] ~
m[as.character(i[1]),]))$coefficient[2,4], error= function(e)NA)
})
t = apply(an,1,function(i){
tryCatch(summary(lm(exp[as.character(i[2]),] ~
m[as.character(i[1]),]))$coefficient[2,3], error= function(e)NA)
})
an1 =cbind(an,p)
an1 = cbind(an1,t)
an1$q = p.adjust(as.numeric(an1$p))
summary(lm(exp["MAOB",] ~
m["cg00121904",]$coefficient[2,c(3:4)]
###############################################
[[alternative HTML version deleted]]
Hi Spencer,
The an1 syntax is adding regression coefficients (or NAs where a regression
could not be done) to the downloaded and processed data, which ends up a matrix.
The cbind function adds the regression coefficients to the last column of the
matrix (i.e. bind the columns of the inputs in the order given). Simple example
below. Not actually any need for the separate cbind commands, could have just
used an1=cbind(an,p,t). The cbind function expects all the columns to be of the
same length, hence the use of the tryCatch function to capture NA's for
failed regression attempts, ensuring that p and t correspond row by row with the
matrix.
x=seq(1,5)
y=seq(6,10)
z=seq(1,5)
xyz=cbind(x,y,z)
xyz
x y z
[1,] 1 6 1
[2,] 2 7 2
[3,] 3 8 3
[4,] 4 9 4
[5,] 5 10 5
dangs=rep(NA,5)
xyzd=cbind(xyz,dangs)
xyzd
x y z dangs
[1,] 1 6 1 NA
[2,] 2 7 2 NA
[3,] 3 8 3 NA
[4,] 4 9 4 NA
[5,] 5 10 5 NA
-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Spencer
Brackett
Sent: February 14, 2019 12:32 AM
To: R-help <r-help at r-project.org>; Sarah Goslee <sarah.goslee at
gmail.com>; Caitlin Gibbons <bioprogrammer at gmail.com>; Jeff
Newmiller <jdnewmil at dcn.davis.ca.us>
Subject: [R] R Data
Hello everyone,
The following is a portion of coding that a colleague sent. Given my lack of
experience in R, I am not quite sure what the significance of the following
arguments. Could anyone help me translate? For context, I am aware of the
downloading portion of the script... library(data.table) etc., but am not
familiar with the portion pertaining to an1 .
library(data.table)
anno = as.data.frame(fread(file
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/450K/mapper.txt", sep
="\t", header = T)) meth = read.table(file =
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/27K/GBM.txt", sep
="\t", header = T, row.names = 1) meth = as.matrix(meth)
""" the loop just formats the methylation column names to match
format"""
colnames(meth) = sapply(colnames(meth), function(i){
c1 = strsplit(i,split = '.', fixed = T)[[1]]
c1[4] = paste(strsplit(c1[4],split = "",fixed =
T)[[1]][1:2],collapse "")
paste(c1,collapse = ".")
})
exp = read.table(file
"/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/RNAseq/GBM.txt", sep =
"\t", header = T, row.names = 1) exp = as.matrix(exp) c =
intersect(colnames(exp),colnames(meth))
exp = exp[,c]
meth = meth[,c]
m = apply(meth, 1, function(i){
log2(i/(1-i))
})
m = t(as.matrix(m))
an = anno[anno$probe %in% rownames(m),]
an = an[an$gene %in% rownames(exp),]
an = an[an$location %in% c("TSS200","TSS1500"),]
p = apply(an,1,function(i){
tryCatch(summary(lm(exp[as.character(i[2]),] ~
m[as.character(i[1]),]))$coefficient[2,4], error= function(e)NA)
})
t = apply(an,1,function(i){
tryCatch(summary(lm(exp[as.character(i[2]),] ~
m[as.character(i[1]),]))$coefficient[2,3], error= function(e)NA)
})
an1 =cbind(an,p)
an1 = cbind(an1,t)
an1$q = p.adjust(as.numeric(an1$p))
summary(lm(exp["MAOB",] ~
m["cg00121904",]$coefficient[2,c(3:4)]
###############################################
[[alternative HTML version deleted]]
______________________________________________
R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Mr. Fowler, Thank you! This information is most helpful. So from my understanding, I can use the regression coefficients shown (via the coding I originally sent, to generate a continuous distribution with what is essentially a line of best fit? The data added here had some 30,000 variables (it is genomic data from TCGA), does this mean that any none NA data is being accounted for in said distribution? Best, Spencer Brackett On Thursday, February 14, 2019, Fowler, Mark <Mark.Fowler at dfo-mpo.gc.ca> wrote:> Hi Spencer, > > The an1 syntax is adding regression coefficients (or NAs where a > regression could not be done) to the downloaded and processed data, which > ends up a matrix. The cbind function adds the regression coefficients to > the last column of the matrix (i.e. bind the columns of the inputs in the > order given). Simple example below. Not actually any need for the separate > cbind commands, could have just used an1=cbind(an,p,t). The cbind function > expects all the columns to be of the same length, hence the use of the > tryCatch function to capture NA's for failed regression attempts, ensuring > that p and t correspond row by row with the matrix. > > x=seq(1,5) > y=seq(6,10) > z=seq(1,5) > xyz=cbind(x,y,z) > xyz > x y z > [1,] 1 6 1 > [2,] 2 7 2 > [3,] 3 8 3 > [4,] 4 9 4 > [5,] 5 10 5 > dangs=rep(NA,5) > xyzd=cbind(xyz,dangs) > xyzd > x y z dangs > [1,] 1 6 1 NA > [2,] 2 7 2 NA > [3,] 3 8 3 NA > [4,] 4 9 4 NA > [5,] 5 10 5 NA > > -----Original Message----- > From: R-help <r-help-bounces at r-project.org> On Behalf Of Spencer Brackett > Sent: February 14, 2019 12:32 AM > To: R-help <r-help at r-project.org>; Sarah Goslee <sarah.goslee at gmail.com>; > Caitlin Gibbons <bioprogrammer at gmail.com>; Jeff Newmiller < > jdnewmil at dcn.davis.ca.us> > Subject: [R] R Data > > Hello everyone, > > The following is a portion of coding that a colleague sent. Given my lack > of experience in R, I am not quite sure what the significance of the > following arguments. Could anyone help me translate? For context, I am > aware of the downloading portion of the script... library(data.table) etc., > but am not familiar with the portion pertaining to an1 . > > library(data.table) > anno = as.data.frame(fread(file > "/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/450K/mapper.txt", sep ="\t", > header = T)) meth = read.table(file = "/rsrch1/bcb/kchen_group/v_ > mohanty/data/TCGA/27K/GBM.txt", sep ="\t", header = T, row.names = 1) > meth = as.matrix(meth) """ the loop just formats the methylation column > names to match format""" > colnames(meth) = sapply(colnames(meth), function(i){ > c1 = strsplit(i,split = '.', fixed = T)[[1]] > c1[4] = paste(strsplit(c1[4],split = "",fixed = T)[[1]][1:2],collapse > "") > paste(c1,collapse = ".") > }) > exp = read.table(file > "/rsrch1/bcb/kchen_group/v_mohanty/data/TCGA/RNAseq/GBM.txt", sep = "\t", > header = T, row.names = 1) exp = as.matrix(exp) c = intersect(colnames(exp), > colnames(meth)) > exp = exp[,c] > meth = meth[,c] > m = apply(meth, 1, function(i){ > log2(i/(1-i)) > }) > m = t(as.matrix(m)) > an = anno[anno$probe %in% rownames(m),] > an = an[an$gene %in% rownames(exp),] > an = an[an$location %in% c("TSS200","TSS1500"),] > > p = apply(an,1,function(i){ > tryCatch(summary(lm(exp[as.character(i[2]),] ~ m[as.character(i[1]),]))$coefficient[2,4], > error= function(e)NA) > }) > t = apply(an,1,function(i){ > tryCatch(summary(lm(exp[as.character(i[2]),] ~ m[as.character(i[1]),]))$coefficient[2,3], > error= function(e)NA) > }) > an1 =cbind(an,p) > an1 = cbind(an1,t) > an1$q = p.adjust(as.numeric(an1$p)) > summary(lm(exp["MAOB",] ~ m["cg00121904",]$coefficient[2,c(3:4)] > ############################################### > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/ > posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]