R help - Jan 2019 - troubleshooting data structure to run krippendorff's alpha

Hi -
I'm trying to run Krippendorff's alpha for data consisting of 4 subjects
rated on 6 events each by three raters.  The ratings are interval ratio
scale data.

I've rearranged my data into a 3 x 24  of ratersXevents. (per this
discussion on CrossValidated: (
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144)
).

This is the code I've used:
library(irr)
dat <- read.csv(file.choose(), header = TRUE)
head(dat)
kripp.alpha(dat, method=c("ratio"))
#### error message: Error in sort.list(y) : 'x' must be atomic for
'sort.list'
Have you called 'sort' on a list?
kripp.alpha(dat,"ratio")
#### error message: Error in sort.list(y) : 'x' must be atomic for
'sort.list'
Have you called 'sort' on a list?

I read rhelp on sort, but I'm still confused.  Please help!
Thank you!

PS
I arranged my data in that matrix based upon this comment and response from
the CrossValidated posting forum (
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144),
but my question above was rejected there.

	[[alternative HTML version deleted]]

I don't understand most of what you wrote, but when you say
"matrix" you are mistaken. A matrix is NOT the same thing as a data
frame, which is what you get when you call read.csv(). Read

RShowDoc("R-intro")

Sections 5 and 6... A data frame is a list of column vectors, while a matrix is
a vector with a dimension attribute.

You can use the as.matrix function to convert a data frame to a matrix.

On January 27, 2019 9:08:02 AM PST, Hallie Kamesch <hallie.kamesch at
gmail.com> wrote:
>Hi -
>I'm trying to run Krippendorff's alpha for data consisting of 4
>subjects
>rated on 6 events each by three raters.  The ratings are interval ratio
>scale data.
>
>I've rearranged my data into a 3 x 24  of ratersXevents. (per this
>discussion on CrossValidated: (
>https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144)
>).
>
>This is the code I've used:
>library(irr)
>dat <- read.csv(file.choose(), header = TRUE)
>head(dat)
>kripp.alpha(dat, method=c("ratio"))
>#### error message: Error in sort.list(y) : 'x' must be atomic for
>'sort.list'
>Have you called 'sort' on a list?
>kripp.alpha(dat,"ratio")
>#### error message: Error in sort.list(y) : 'x' must be atomic for
>'sort.list'
>Have you called 'sort' on a list?
>
>I read rhelp on sort, but I'm still confused.  Please help!
>Thank you!
>
>PS
>I arranged my data in that matrix based upon this comment and response
>from
>the CrossValidated posting forum (
>https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144),
>but my question above was rejected there.
>
>	[[alternative HTML version deleted]]
>
>______________________________________________
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
-- 
Sent from my phone. Please excuse my brevity.

Hi Halllie,
As Jeff noted, a data frame is not a matrix (it is a variety of list),
so that looks like your problem.

hkdf<-data.frame(sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE),
 sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE))
library(irr)
kripp.alpha(hkdf)
kripp.alpha(as.matrix(hkdf))

Jim

On Mon, Jan 28, 2019 at 6:04 PM Hallie Kamesch <hallie.kamesch at
gmail.com> wrote:
>
> Hi -
> I'm trying to run Krippendorff's alpha for data consisting of 4
subjects
> rated on 6 events each by three raters.  The ratings are interval ratio
> scale data.
>
> I've rearranged my data into a 3 x 24  of ratersXevents. (per this
> discussion on CrossValidated: (
>
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144)
> ).
>
> This is the code I've used:
> library(irr)
> dat <- read.csv(file.choose(), header = TRUE)
> head(dat)
> kripp.alpha(dat, method=c("ratio"))
> #### error message: Error in sort.list(y) : 'x' must be atomic for
> 'sort.list'
> Have you called 'sort' on a list?
> kripp.alpha(dat,"ratio")
> #### error message: Error in sort.list(y) : 'x' must be atomic for
> 'sort.list'
> Have you called 'sort' on a list?
>
> I read rhelp on sort, but I'm still confused.  Please help!
> Thank you!
>
> PS
> I arranged my data in that matrix based upon this comment and response from
> the CrossValidated posting forum (
>
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144),
> but my question above was rejected there.
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Hi all, 
Thank you for your responses. You are correct that it is not a matrix. I used
the incorrect term.
I meant I put my data in a spreadsheet with three rows and 24 columns. 

Sent from my iPhone
> On Jan 28, 2019, at 3:36 AM, Jim Lemon <drjimlemon at gmail.com>
wrote:
> 
> Hi Halllie,
> As Jeff noted, a data frame is not a matrix (it is a variety of list),
> so that looks like your problem.
> 
>
hkdf<-data.frame(sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE),
> sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE))
> library(irr)
> kripp.alpha(hkdf)
> kripp.alpha(as.matrix(hkdf))
> 
> Jim
> 
>> On Mon, Jan 28, 2019 at 6:04 PM Hallie Kamesch <hallie.kamesch at
gmail.com> wrote:
>> 
>> Hi -
>> I'm trying to run Krippendorff's alpha for data consisting of 4
subjects
>> rated on 6 events each by three raters.  The ratings are interval ratio
>> scale data.
>> 
>> I've rearranged my data into a 3 x 24  of ratersXevents. (per this
>> discussion on CrossValidated: (
>>
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144)
>> ).
>> 
>> This is the code I've used:
>> library(irr)
>> dat <- read.csv(file.choose(), header = TRUE)
>> head(dat)
>> kripp.alpha(dat, method=c("ratio"))
>> #### error message: Error in sort.list(y) : 'x' must be atomic
for
>> 'sort.list'
>> Have you called 'sort' on a list?
>> kripp.alpha(dat,"ratio")
>> #### error message: Error in sort.list(y) : 'x' must be atomic
for
>> 'sort.list'
>> Have you called 'sort' on a list?
>> 
>> I read rhelp on sort, but I'm still confused.  Please help!
>> Thank you!
>> 
>> PS
>> I arranged my data in that matrix based upon this comment and response
from
>> the CrossValidated posting forum (
>>
https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144),
>> but my question above was rejected there.
>> 
>>        [[alternative HTML version deleted]]
>> 
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.